Problem 23
Question
Find the value of the indicated variable. Round approximate answers to three decimal places. Find \(h\) if \(r=3, V=12 \pi,\) and \(r^{2}=\frac{V}{\pi h}\)
Step-by-Step Solution
Verified Answer
The value of \( h \) is approximately 1.333.
1Step 1: Identify and Write Down the Given Values
Given values are:\( r = 3 \ V = 12 \pi \)
2Step 2: Write Down the Formula
The equation given is: \( r^2 = \frac{V}{\pi h} \)
3Step 3: Substitute the Given Values into the Formula
Substitute \(r\) and \(V\) with the given values:\[ 3^2 = \frac{12 \pi}{\pi h} \]
4Step 4: Simplify the Equation
First, simplify \( \pi \) in the denominator and numerator:\[ 9 = \frac{12}{h} \]
5Step 5: Solve for \(h\)
Rearrange the equation to solve for \(h\): \[ h = \frac{12}{9} \]\[ h = \frac{4}{3} \approx 1.333 \]
Key Concepts
solving equationsalgebraic simplificationsubstitution methodvolume formulas
solving equations
Solving equations is the process of finding the value of a variable that makes an equation true. In the given exercise, we needed to find the value of the variable \(h\) using the given equation \(r^{2} = \frac{V}{\text{π} h}\). To solve for \(h\), we performed several steps:
We started by plugging in the provided values for \(r\) and \(V\). Then we simplified the equation to isolate \(h\) on one side. Finally, we performed basic arithmetic to solve for \(h\).
Remember, the goal is to manipulate the equation until the variable you are solving for is by itself on one side of the equation.
We started by plugging in the provided values for \(r\) and \(V\). Then we simplified the equation to isolate \(h\) on one side. Finally, we performed basic arithmetic to solve for \(h\).
Remember, the goal is to manipulate the equation until the variable you are solving for is by itself on one side of the equation.
algebraic simplification
Algebraic simplification involves reducing an equation or expression to its simplest form. In this problem, we needed to simplify the equation \(3^{2} = \frac{12π}{π h}\) after substituting the given values.
Here's how we simplified it: First, we noticed the \(\text{π}\) terms in the numerator and denominator and canceled them out, resulting in \(3^{2} = \frac{12}{h}\).
Simplifying further, \(3^{2}\) is equal to \(9\), so we get \(9 = \frac{12}{h}\). This simplified form made it easier to isolate the variable \(h\) and find its value.
Simplifying equations can help you see the relationships between variables more clearly and make it easier to solve them.
Here's how we simplified it: First, we noticed the \(\text{π}\) terms in the numerator and denominator and canceled them out, resulting in \(3^{2} = \frac{12}{h}\).
Simplifying further, \(3^{2}\) is equal to \(9\), so we get \(9 = \frac{12}{h}\). This simplified form made it easier to isolate the variable \(h\) and find its value.
Simplifying equations can help you see the relationships between variables more clearly and make it easier to solve them.
substitution method
The substitution method involves replacing variables with their given values or expressions to solve an equation. In the exercise, we substituted \(r = 3\) and \(V = 12π\) into the original formula \(r^{2} = \frac{V}{\text{π} h}\).
This substitution changed the abstract equation into a more concrete form: \(3^{2} = \frac{12\text{π}}{\text{π} h}\).
By substituting these values, you turn an equation with unknowns into a simpler equation with known values that is easier to solve.
The substitution method is particularly useful in problems where multiple variables are involved, and you need to simplify the problem step-by-step.
This substitution changed the abstract equation into a more concrete form: \(3^{2} = \frac{12\text{π}}{\text{π} h}\).
By substituting these values, you turn an equation with unknowns into a simpler equation with known values that is easier to solve.
The substitution method is particularly useful in problems where multiple variables are involved, and you need to simplify the problem step-by-step.
volume formulas
Volume formulas are mathematical expressions that calculate the space inside a 3-dimensional object. Here, the provided volume \(V\) was given as \(12\text{π}\), which might relate to the formula for the volume of a cylinder or similar shape.
Although this problem didn't explicitly state the shape of the object, knowing volume formulas helps us understand where the equation \(r^{2} = \frac{V}{\text{π} h}\) might come from.
Be familiar with common volume formulas like those for cylinders, cones, and spheres. For example,
Although this problem didn't explicitly state the shape of the object, knowing volume formulas helps us understand where the equation \(r^{2} = \frac{V}{\text{π} h}\) might come from.
Be familiar with common volume formulas like those for cylinders, cones, and spheres. For example,
- Volume of a cylinder: \(V = \text{π} r^{2} h\)
- Volume of a sphere: \(V = \frac{4}{3} \text{π} r^{3}\)
- Volume of a cone: \(V = \frac{1}{3} \text{π} r^{2} h\)
Other exercises in this chapter
Problem 22
Reduce each rational expression to its lowest terms. $$\frac{242}{154}$$
View solution Problem 23
Find the solution set to each equation. $$\frac{2}{x+2}+\frac{x}{x-3}+\frac{1}{x^{2}-x-6}=0$$
View solution Problem 23
Simplify each complex fraction. $$\frac{x+\frac{4}{x+4}}{x-\frac{4 x+4}{x+4}}$$
View solution Problem 23
Reduce each rational expression to its lowest terms. $$\frac{2 x+2}{4}$$
View solution