Problem 23
Question
Exer. 23-34: Sketch the graph of the circle or semicircle. $$ x^{2}+y^{2}=11 $$
Step-by-Step Solution
Verified Answer
The graph is a circle centered at the origin with radius \(\sqrt{11}\).
1Step 1: Identify the Equation Type
The given equation is in the form \(x^2 + y^2 = r^2\), which represents a circle centered at the origin \((0, 0)\) with radius \(r\). In the equation \(x^2 + y^2 = 11\), \(r^2 = 11\).
2Step 2: Calculate the Radius
We need to find the radius \(r\) by taking the square root of \(11\). Therefore, \(r = \sqrt{11}\).
3Step 3: Sketch the Graph
Draw a coordinate plane with an x-axis and a y-axis intersecting at the origin. Measure out the distance \(\sqrt{11}\) from the origin in all directions (up, down, left, right) on both axes, since the center of the circle is \((0, 0)\). Draw a full circle through these points, maintaining a constant distance of \(\sqrt{11}\) from the center at all points on the circle.
Key Concepts
Coordinate PlaneCircle EquationRadius Calculation
Coordinate Plane
The coordinate plane is a fundamental tool in graphing and geometry. It consists of two perpendicular lines, which form the x-axis (horizontal line) and y-axis (vertical line). These axes intersect at a point called the origin, designated as \((0, 0)\). Think of the coordinate plane as a map where we can locate points and graph shapes, such as circles and lines.
When graphing on the coordinate plane, it's important to understand the layout:
When graphing on the coordinate plane, it's important to understand the layout:
- The x-axis usually runs left to right.
- The y-axis runs up and down.
- Points are named using ordered pairs \((x, y)\), indicating their distance from the origin.
Circle Equation
The circle equation in the standard form is given by \(x^2 + y^2 = r^2\), where \((x, y)\) represents the coordinates of any point on the circle, and \(r\) is the radius. This equation shows that every point on the circle is at a fixed distance, the radius, from the center point, usually \((0, 0)\) in these simple formulas.
Here's how to interpret the circle equation:
Here's how to interpret the circle equation:
- The expression \(x^2 + y^2\) represents the squared distance from any point \((x,y)\) to the origin.
- The equals sign and \(r^2\) indicates that this distance remains constant for all points on the circle.
Radius Calculation
The radius of a circle is the distance from the center to any point on the circle's edge. In the equation \(x^2 + y^2 = r^2\), the term \(r^2\) represents the square of the circle's radius. To find the radius itself, we take the square root of \(r^2\).
In the given problem, the circle equation is \(x^2 + y^2 = 11\).
Here, \(r^2 = 11\), which suggests we need to calculate \(r\) by addressing the following:
In the given problem, the circle equation is \(x^2 + y^2 = 11\).
Here, \(r^2 = 11\), which suggests we need to calculate \(r\) by addressing the following:
- Apply the square root: \(r = \sqrt{11}\).
- This value represents the length from the center point of the circle (origin) to any point on its circumference.
Other exercises in this chapter
Problem 23
Exer. 21-32: Find a general form of an equation of the line through the point \(A\) that satisfies the given condition. $$ A(5,-3) ; \quad \text { slope }-4 $$
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Exer. 21-32: Find the domain of \(f\). $$ f(x)=\sqrt{9-x^{2}} $$
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Exer. 23-24: Find a formula that expresses the fact that an arbitrary point \(P(x, y)\) is on the perpendicular bisector \(l\) of segment \(A B\). $$ A(-4,-3),
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Exer. 13-26: Sketch, on the same coordinate plane, the graphs of \(f\) for the given values of \(c\). (Make use of symmetry, shifting, stretching, compressing,
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