Problem 22
Question
Write in standard form an equation of the line that passes through the given point and has the given slope. \((-2,7), m=-4\)
Step-by-Step Solution
Verified Answer
So, the equation of the line in standard form is \(4x + y = -1\).
1Step 1: Filling the point and slope in point-slope form
Substitute \((x1, y1) = (-2, 7)\) and \(m = -4\) into the point-slope equation \(y - y1 = m(x - x1)\). This will result to \(y - 7 = -4(x + 2)\).
2Step 2: Distributing and simplifying the equation
Next, distribute \( -4 \) into the parentheses to simplify the equation: \(y - 7 = -4x - 8\).
3Step 3: Turning into standard form
To convert this equation into standard form, the equation should look like this: \(Ax + By = C\). So, add \(4x\) and \(7\) to both sides to form: \(4x + y = -1\).
Key Concepts
Point-Slope FormStandard Form of a LineSlope of a Line
Point-Slope Form
The point-slope form of a line is an algebraic equation that allows us to construct the equation of a line when we know one point on the line and the slope of that line. It is written as: \[ y - y_1 = m(x - x_1) \]
In this formula, the point \( (x_1, y_1) \) is a point that the line passes through, and \( m \) is the slope of the line.
To use this form effectively, first identify the given point and the slope. In our problem, the given point is \( (-2,7) \) and the slope is \(m=-4\). By substituting these values into the point-slope form, we get the equation \( y - 7 = -4(x + 2) \), which is the initial step of our exercise solution.
In this formula, the point \( (x_1, y_1) \) is a point that the line passes through, and \( m \) is the slope of the line.
To use this form effectively, first identify the given point and the slope. In our problem, the given point is \( (-2,7) \) and the slope is \(m=-4\). By substituting these values into the point-slope form, we get the equation \( y - 7 = -4(x + 2) \), which is the initial step of our exercise solution.
Why Point-Slope Form is Useful:
- Quickly provides the linear equation when a point and a slope are known.
- Allows for easy plotting of the line on a graph.
- Facilitates the understanding of how the slope affects the position of the line.
Standard Form of a Line
The standard form of a line's equation is another way to write the equation of a line. It is typically represented as: \[ Ax + By = C \]
where \( A \) and \( B \) are the coefficients of \( x \) and \( y \) respectively, and should be integers. The value \( C \) is the constant. In the standard form, \( A \) should be non-negative, and \( A \) and \( B \) should not both be zero.
To convert an equation from point-slope to standard form, one has to rearrange and simplify the equation by moving \( x \) and \( y \) terms to one side, and the constant to the other side. In the given exercise, after rearranging the point-slope form equation, we achieve \( 4x + y = -1 \), which is now in standard form.
where \( A \) and \( B \) are the coefficients of \( x \) and \( y \) respectively, and should be integers. The value \( C \) is the constant. In the standard form, \( A \) should be non-negative, and \( A \) and \( B \) should not both be zero.
To convert an equation from point-slope to standard form, one has to rearrange and simplify the equation by moving \( x \) and \( y \) terms to one side, and the constant to the other side. In the given exercise, after rearranging the point-slope form equation, we achieve \( 4x + y = -1 \), which is now in standard form.
Characteristics of Standard Form:
- The coefficients \( A \) and \( B \) should be whole numbers.
- Preferably, \( A \) is non-negative.
- Provides a clear view of the intercepts on the \( x \) and \( y \) axes.
Slope of a Line
The slope of a line is a measure of its steepness or gradient and is commonly represented by \( m \). It is calculated as the ratio of the vertical change (rise) to the horizontal change (run) between any two points on the line. Formally, it is written as: \[ m = \frac{{rise}}{{run}} = \frac{{y_2 - y_1}}{{x_2 - x_1}} \]
In the exercise, the slope is provided as \( m=-4 \), which indicates that for every unit of horizontal change to the right, there is a four-unit vertical change downwards (since it is negative). This negative slope results in a line that tilts downwards as it moves from left to right.
In the exercise, the slope is provided as \( m=-4 \), which indicates that for every unit of horizontal change to the right, there is a four-unit vertical change downwards (since it is negative). This negative slope results in a line that tilts downwards as it moves from left to right.
Understanding Slope:
- A positive slope indicates a line rising from left to right.
- A negative slope indicates a line falling from left to right.
- A slope of zero indicates a horizontal line.
- An undefined slope (division by zero) indicates a vertical line.
Other exercises in this chapter
Problem 22
Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (-10,0), m=2 $$
View solution Problem 22
Write in slope-intercept form the equation of the line passing through the two points. Show that the line is perpendicular to the given line. Check your answer
View solution Problem 23
Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (-8,-2), m=2 $$
View solution Problem 23
Write in slope-intercept form the equation of the line passing through the two points. Show that the line is perpendicular to the given line. Check your answer
View solution