Problem 22
Question
Verify the identity. $$\frac{\cos u-\cos v}{\cos u+\cos v}=-\tan \frac{1}{2}(u+v) \tan \frac{1}{2}(u-v)$$
Step-by-Step Solution
Verified Answer
The identity is verified using sum-to-product identities and simplification steps.
1Step 1: Use Trigonometric Identities for Simplification
We begin by expressing both sides of the equation using trigonometric identities. For the left-hand side, which is \( \frac{\cos u - \cos v}{\cos u + \cos v} \), we use the sum-to-product identities:\[\cos u - \cos v = -2 \sin \left(\frac{u+v}{2}\right) \sin \left(\frac{u-v}{2}\right) \\cos u + \cos v = 2 \cos \left(\frac{u+v}{2}\right) \cos \left(\frac{u-v}{2}\right) \]This allows us to rewrite the left-hand side as:\[\frac{-2 \sin \left(\frac{u+v}{2}\right) \sin \left(\frac{u-v}{2}\right)}{2 \cos \left(\frac{u+v}{2}\right) \cos \left(\frac{u-v}{2}\right)}\]
2Step 2: Simplify the Expression
Cancel common terms on the numerator and the denominator of the fraction:\[= -\frac{\sin \left(\frac{u+v}{2}\right)}{\cos \left(\frac{u+v}{2}\right)} \cdot \frac{\sin \left(\frac{u-v}{2}\right)}{\cos \left(\frac{u-v}{2}\right)}\]This simplifies to:\[= -\tan \left(\frac{u+v}{2}\right) \tan \left(\frac{u-v}{2}\right)\]This is the same expression as the right-hand side of the identity we need to verify.
3Step 3: Verify the Identity
Both sides of the original equation now match:\[\frac{\cos u - \cos v}{\cos u + \cos v} = -\tan \left(\frac{u+v}{2}\right) \tan \left(\frac{u-v}{2}\right)\]Thus, we have verified that the identity holds true through trigonometric transformations and simplifications.
Key Concepts
Sum-to-Product IdentitiesTrigonometric TransformationsVerifying Trigonometric Identities
Sum-to-Product Identities
The concept of sum-to-product identities plays a crucial role in trigonometry. These identities are particularly useful for transforming the sum or difference of trigonometric functions into products of functions. This can simplify complex expressions and make them easier to solve. For example, if you have \( \cos u - \cos v \), sum-to-product identities allow you to transform this into something more manageable:
- \( \cos u - \cos v = -2 \sin \left( \frac{u+v}{2} \right) \sin \left( \frac{u-v}{2} \right) \)
- \( \cos u + \cos v = 2 \cos \left( \frac{u+v}{2} \right) \cos \left( \frac{u-v}{2} \right) \)
Trigonometric Transformations
Trigonometric transformations are techniques used in solving trigonometric expressions. They involve changing the form without affecting the equality. These transformations often leverage identities to simplify or rewrite expressions to match other, more familiar forms.
In our original problem, the transformation was performed by using the sum-to-product identities. Initially, we had complex expressions with a sum involving cosines. By transforming it, we get:
In our original problem, the transformation was performed by using the sum-to-product identities. Initially, we had complex expressions with a sum involving cosines. By transforming it, we get:
- \( \frac{-2 \sin \left( \frac{u+v}{2} \right) \sin \left( \frac{u-v}{2} \right)}{2 \cos \left( \frac{u+v}{2} \right) \cos \left( \frac{u-v}{2} \right)} \)
Verifying Trigonometric Identities
Verifying trigonometric identities is about showing that two sides of an equation are equivalent using trigonometric laws and rules. It often involves manipulation and transformation of one side to make it appear like the other.
In our exercise, once we transformed and simplified the original expression, we were able to match both sides:
In our exercise, once we transformed and simplified the original expression, we were able to match both sides:
- The left side became \( -\tan \left( \frac{u+v}{2} \right) \tan \left( \frac{u-v}{2} \right) \)
- The right side was already presented in that form
Other exercises in this chapter
Problem 21
If \(\sin \alpha=-\frac{4}{5}\) and \(\sec \beta=\frac{5}{3}\) for a third- quadrant angle \(\alpha\) and a first-quadrant angle \(\beta,\) find (a) \(\sin (\al
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View solution Problem 22
Verify the Identity. $$\sin ^{4} \theta+2 \sin ^{2} \theta \cos ^{2} \theta+\cos ^{4} \theta=1$$
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Verify the identity. \(\cos ^{4} x-\sin ^{4} x=\cos 2 x\)
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