Problem 22
Question
Verify the identity. \(\cos ^{4} x-\sin ^{4} x=\cos 2 x\)
Step-by-Step Solution
Verified Answer
Identity verified: \( \cos^4 x - \sin^4 x = \cos 2x \).
1Step 1: Recognize the Difference of Squares
The expression \( \cos^4 x - \sin^4 x \) is a difference of squares, which we can factor using the identity \( a^2 - b^2 = (a-b)(a+b) \). In our case, \( a = \cos^2 x \) and \( b = \sin^2 x \).
2Step 2: Factor the Expression
Applying the difference of squares identity, we get:\[ \cos^4 x - \sin^4 x = (\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) \].
3Step 3: Simplify Using Pythagorean Identity
From the Pythagorean identity, we know \( \cos^2 x + \sin^2 x = 1 \). Substitute this in to simplify:\[ (\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) = (\cos^2 x - \sin^2 x)(1) = \cos^2 x - \sin^2 x \].
4Step 4: Recognize the Cosine Double Angle Identity
The expression \( \cos^2 x - \sin^2 x \) is equivalent to \( \cos 2x \), according to the cosine double angle identity.
5Step 5: Verify the Identity
Thus, we have shown that \( \cos^4 x - \sin^4 x = \cos 2x \), verifying the given identity.
Key Concepts
Difference of SquaresPythagorean IdentitiesCosine Double Angle Identity
Difference of Squares
In mathematics, the difference of squares is an important concept and appears frequently in expressions that need simplification or factoration. The difference of squares formula states that for any two expressions, say \( a \) and \( b \), the formula can be written as:
In the original problem, \( \cos^4 x - \sin^4 x \) aligns with the difference of squares format. Here, \( \cos^2 x \) acts as \( a \), and \( \sin^2 x \) as \( b \). Thus, the expression can be factored as:
- \( a^2 - b^2 = (a-b)(a+b) \)
In the original problem, \( \cos^4 x - \sin^4 x \) aligns with the difference of squares format. Here, \( \cos^2 x \) acts as \( a \), and \( \sin^2 x \) as \( b \). Thus, the expression can be factored as:
- \( (\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) \)
Pythagorean Identities
The Pythagorean identities are fundamental relationships in trigonometry that are derived from the Pythagorean Theorem. They help in simplifying trigonometric expressions and confirming identities.
In the original exercise, during the simplification step, this identity makes the factor \( \cos^2 x + \sin^2 x \) reduce to 1:
- One basic Pythagorean identity is \( \cos^2 x + \sin^2 x = 1 \)
In the original exercise, during the simplification step, this identity makes the factor \( \cos^2 x + \sin^2 x \) reduce to 1:
- Thus, changing \( (\cos^2 x - \sin^2 x)(1) \) into \( \cos^2 x - \sin^2 x \)
Cosine Double Angle Identity
The cosine double angle identity is another vital tool when working with trigonometric identities. It offers a way to express the cosine of a double angle in terms of the squares of sine and cosine of a single angle.
In this exercise, the expression \( \cos^2 x - \sin^2 x \) exactly matches the cosine double angle identity. Thus, it is equivalent to \( \cos 2x \).
- The identity is given by: \( \cos 2x = \cos^2 x - \sin^2 x \)
In this exercise, the expression \( \cos^2 x - \sin^2 x \) exactly matches the cosine double angle identity. Thus, it is equivalent to \( \cos 2x \).
- Using this identity confirms that \( \cos^4 x - \sin^4 x = \cos 2x \)
Other exercises in this chapter
Problem 22
Verify the identity. $$\frac{\cos u-\cos v}{\cos u+\cos v}=-\tan \frac{1}{2}(u+v) \tan \frac{1}{2}(u-v)$$
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Verify the Identity. $$\sin ^{4} \theta+2 \sin ^{2} \theta \cos ^{2} \theta+\cos ^{4} \theta=1$$
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If \(\tan \alpha=-\frac{7}{24}\) and \(\cot \beta=\frac{3}{4}\) for a second- quadrant angle \(\alpha\) and a third-quadrant angle \(\boldsymbol{\beta},\) find
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Find all solutions of the equation. $$4 \cos \theta-2=0$$
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