Problem 22
Question
Verify the identity. $$ \cos ^{4} x-\sin ^{4} x=\cos 2 x $$
Step-by-Step Solution
Verified Answer
The identity \( \cos^4 x - \sin^4 x = \cos 2x \) is verified.
1Step 1: Rewrite the left-hand side using the difference of squares
The expression \( \cos^4 x - \sin^4 x \) is a difference of squares. We can rewrite it as \( (\cos^2 x)^2 - (\sin^2 x)^2 \). This matches the form \( a^2 - b^2 = (a-b)(a+b) \).
2Step 2: Factor the difference of squares
Apply the difference of squares formula: \( \cos^4 x - \sin^4 x = (\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) \).
3Step 3: Simplify \( \cos^2 x + \sin^2 x \)
Since \( \cos^2 x + \sin^2 x = 1 \) (Pythagorean identity), the expression becomes \( (\cos^2 x - \sin^2 x)(1) = \cos^2 x - \sin^2 x \).
4Step 4: Recognize \( \cos^2 x - \sin^2 x \) as a trigonometric identity
The expression \( \cos^2 x - \sin^2 x \) is a known trigonometric identity for \( \cos 2x \). Therefore, \( \cos^4 x - \sin^4 x = \cos 2x \).
5Step 5: Conclude the identity verification
We've shown that \( \cos^4 x - \sin^4 x = \cos 2x \) holds true, verifying the identity as correct.
Key Concepts
Difference of SquaresPythagorean IdentityTrigonometric Functions
Difference of Squares
In mathematics, a difference of squares is a particular case of polynomial identity that simplifies products of terms. Specifically, the expression has the form \( a^2 - b^2 \), which can be rewritten as \( (a-b)(a+b) \). This is incredibly useful in algebra for simplifying expressions and solving equations more efficiently.
In the given exercise, \( \cos^4 x - \sin^4 x \) resembles this identity. By setting \( a = \cos^2 x \) and \( b = \sin^2 x \), you can transform \( \cos^4 x - \sin^4 x \) into \( (\cos^2 x)^2 - (\sin^2 x)^2 \), fitting perfectly into the \( a^2 - b^2 \) mold.
Applying the difference of squares formula, it simplifies to:
In the given exercise, \( \cos^4 x - \sin^4 x \) resembles this identity. By setting \( a = \cos^2 x \) and \( b = \sin^2 x \), you can transform \( \cos^4 x - \sin^4 x \) into \( (\cos^2 x)^2 - (\sin^2 x)^2 \), fitting perfectly into the \( a^2 - b^2 \) mold.
Applying the difference of squares formula, it simplifies to:
- \( (\cos^2 x - \sin^2 x)(\cos^2 x + \sin^2 x) \)
Pythagorean Identity
The Pythagorean Identity in trigonometry is a fundamental relation between sine and cosine functions. It states that for any angle \( x \), \( \cos^2 x + \sin^2 x = 1 \). This identity stems from the Pythagorean theorem and is valid for all real numbers.
In the exercise, after applying the difference of squares, we encounter the term \( \cos^2 x + \sin^2 x \). According to the Pythagorean Identity, this simplifies to 1.
By substituting 1 into the expression, we get:
In the exercise, after applying the difference of squares, we encounter the term \( \cos^2 x + \sin^2 x \). According to the Pythagorean Identity, this simplifies to 1.
By substituting 1 into the expression, we get:
- \( (\cos^2 x - \sin^2 x)(1) = \cos^2 x - \sin^2 x \)
Trigonometric Functions
Trigonometric functions are the core foundation of trigonometry and are integral to defining relationships in right-angled triangles. The primary trigonometric functions are sine, cosine, and tangent. They help describe the angle, size, and position of geometrical figures.
For this problem specifically, recognizing \( \cos^2 x - \sin^2 x \) as a known trigonometric identity is crucial. This equals \( \cos 2x \), which is the double angle identity expression.
This revelation leads directly to the equation from the problem:
For this problem specifically, recognizing \( \cos^2 x - \sin^2 x \) as a known trigonometric identity is crucial. This equals \( \cos 2x \), which is the double angle identity expression.
This revelation leads directly to the equation from the problem:
- \( \cos^4 x - \sin^4 x = \cos 2x \)
Other exercises in this chapter
Problem 22
If \(\tan \alpha=-\frac{7}{24}\) and \(\cot \beta=\frac{3}{4}\) for a second- quadrant angle \(\alpha\) and a third-quadrant angle \(\beta\), find (a) \(\sin (\
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Exer. 1-38: Find all solutions of the equation. $$ (\cos \theta-1)(\sin \theta+1)=0 $$
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