Problem 22
Question
Solve the inequality. Express the answer using interval notation. $$ \frac{1}{2}|x| \geq 1 $$
Step-by-Step Solution
Verified Answer
The solution in interval notation is \((-\infty, -2] \cup [2, \infty)\).
1Step 1: Isolate the Absolute Value
Start with the given inequality: \( \frac{1}{2}|x| \geq 1 \). Multiply both sides by 2 to eliminate the fraction: \(|x| \geq 2\).
2Step 2: Break into Two Inequalities
Since \(|x| \geq 2\), this can be split into two separate inequalities: 1. \( x \geq 2 \)2. \( x \leq -2 \) These represent the two parts of the absolute value condition being greater than or equal to 2.
3Step 3: Write Solution in Interval Notation
Express the solution from Step 2 in interval notation. The solution is the union of the intervals: \((-\infty, -2]\) and \([2, \infty)\).Therefore, the solution in interval notation is: \((-\infty, -2] \cup [2, \infty)\).
Key Concepts
Interval NotationInequality SolutionAbsolute Value Inequalities
Interval Notation
Interval notation is a way to describe the set of numbers that satisfy an inequality. It's a shorthand method used to express a range of values on the number line. In interval notation, we use parentheses \(()\) and brackets \([]\) to denote whether endpoints are included or excluded.
For the inequality \(|x| \geq 2\), the interval notation is written as \((-\infty, -2] \cup [2, \infty)\), meaning all values of \(x\) that are either less than or equal to \(-2\), or greater than or equal to \(2\).
- Parentheses \(()\): Used when the endpoint is not included in the interval. For example, \((a, b)\) means greater than \(a\) and less than \(b\), but does not include \(a\) or \(b\).
- Brackets \([]\): Used when the endpoint is included. For example, \([a, b]\) means the same as \((a, b)\) but includes \(a\) and \(b\).
For the inequality \(|x| \geq 2\), the interval notation is written as \((-\infty, -2] \cup [2, \infty)\), meaning all values of \(x\) that are either less than or equal to \(-2\), or greater than or equal to \(2\).
Inequality Solution
Solving an inequality, like an equation, involves finding all possible values of the variable that make the inequality true. The key difference is that inequalities can have a range of solutions rather than a single solution.
To solve inequalities effectively:
To solve inequalities effectively:
- Isolate the variable: Just like solving equations, try to get the variable of interest by itself on one side of the inequality.
- Consider the direction: When multiplying or dividing both sides by a negative number, reverse the inequality symbol.
- Check the solution: Substitute values back into the original inequality to verify they work.
Absolute Value Inequalities
Absolute value inequalities involve expressions within absolute value symbols, which measure the distance a number is from zero on the number line without considering direction. The expression \(|x|\) indicates how far \(x\) is from zero, always producing a non-negative result.
When dealing with absolute value inequalities like \(|x| \geq 2\), there are two parts to consider because the absolute value can be seen as a "mirror" reflecting values on both positive and negative sides.
In solving \(\frac{1}{2}|x| \geq 1\), once you isolate \(|x| \geq 2\), split it into \(x \geq 2\) and \(x \leq -2\). This highlights how you handle absolute values greater than a certain number, effectively utilizing the concept to capture all possible solutions.
When dealing with absolute value inequalities like \(|x| \geq 2\), there are two parts to consider because the absolute value can be seen as a "mirror" reflecting values on both positive and negative sides.
- Greater than (or equal): For \(|x| \geq c\), break it into two conditions: \(x \geq c\) and \(x \leq -c\).
- Less than: For \(|x| < c\), the solutions are between \(-c\) and \(c\), forming \(-c < x < c\).
In solving \(\frac{1}{2}|x| \geq 1\), once you isolate \(|x| \geq 2\), split it into \(x \geq 2\) and \(x \leq -2\). This highlights how you handle absolute values greater than a certain number, effectively utilizing the concept to capture all possible solutions.
Other exercises in this chapter
Problem 21
Solve the equation by completing the square. \(2 x^{2}+8 x+1=0\)
View solution Problem 21
\(9- 46\) The given equation is either linear or equivalent to a linear equation. Solve the equation. $$ 4\left(y-\frac{1}{2}\right)-y=6(5-y) $$
View solution Problem 22
A Riddle A father is four times as old as his daughter. In 6 years, he will be three times as old as she is. How old is the daughter now?
View solution Problem 22
\(9-32\) me solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ \frac{2}{3}-\frac{1}{2} x \geq \frac{1}{6}+
View solution