Problem 22
Question
In \(3-26,\) prove that each equation is an identity. $$ \cos \theta+\frac{\sin ^{2} \theta}{1+\cos \theta}=1 $$
Step-by-Step Solution
Verified Answer
The equation \( \cos \theta + \frac{\sin^2 \theta}{1 + \cos \theta} = 1 \) is an identity.
1Step 1: Understand the Identity
The goal is to show that the equation \( \cos \theta + \frac{\sin^2 \theta}{1+\cos \theta} = 1 \) holds true for all values of \( \theta \). This means the left side and right side of the equation must be equal under all valid conditions.
2Step 2: Rewrite \( \sin^2 \theta \)
Recall the Pythagorean identity: \( \sin^2 \theta = 1 - \cos^2 \theta \). Substitute this into the expression: \( \cos \theta + \frac{1 - \cos^2 \theta}{1 + \cos \theta} \).
3Step 3: Simplify the Fraction
The expression inside the fraction is \( \frac{1 - \cos^2 \theta}{1 + \cos \theta} \). Factor the numerator: \( 1 - \cos^2 \theta = (1 - \cos \theta)(1 + \cos \theta) \). Substitute this into the fraction: \( \frac{(1 - \cos \theta)(1 + \cos \theta)}{1 + \cos \theta} \).
4Step 4: Cancel Terms
Cancel the \( 1 + \cos \theta \) in the numerator and denominator: \( \frac{1 - \cos \theta}{1} = 1 - \cos \theta \).
5Step 5: Simplify the Expression
Combine this result with \( \cos \theta \): \( \cos \theta + (1 - \cos \theta) = 1 \). This simplifies the left side of the equation to match the right side, which is \( 1 \).
6Step 6: Conclusion
Since the left side simplifies to equal the right side \(1\), we have shown that the given equation is indeed an identity.
Key Concepts
Pythagorean IdentityCosine FunctionSine FunctionAlgebraic Manipulation
Pythagorean Identity
The Pythagorean identity is one of the cornerstones of trigonometry. It states that for any angle \( \theta \), the sum of the squares of the sine and cosine of that angle is always equal to one. Mathematically, it is expressed as:
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
Cosine Function
The cosine function is one of the primary trigonometric functions. It expresses the ratio of the adjacent side to the hypotenuse in a right-angle triangle. The cosine of angle \( \theta \), denoted as \( \cos \theta \), is crucial in trigonometry and appears frequently in various identities and equations.
- The range of cosine is between -1 and 1.
- \( \cos \theta \) is an even function, meaning \( \cos(-\theta) = \cos \theta \).
Sine Function
Another integral component of trigonometry is the sine function. It gives us the ratio of the opposite side to the hypotenuse in a right triangle for a given angle \( \theta \). Represented as \( \sin \theta \), this function plays a central role in trigonometric identities and equations.
- The range of \( \sin \theta \) is also between -1 and 1.
- \( \sin \theta \) is an odd function, meaning \( \sin(-\theta) = -\sin \theta \).
Algebraic Manipulation
Algebraic manipulation is an essential skill in working with trigonometric identities. It involves transforming expressions through operations such as factoring, substituting, expanding, and simplifying to achieve a desired form or solution.
- In finding identities, algebraic manipulation often involves canceling out terms.
- It's about restructuring expressions without changing their inherent values.
Other exercises in this chapter
Problem 22
Prove the identity: \(\frac{\cos 2 \theta}{\sin \theta}+\frac{\sin 2 \theta}{\cos \theta}=\csc \theta\)
View solution Problem 22
If \(A=\arctan 2\) and \(B=\arctan (-2),\) find \(\tan (A-B)\)
View solution Problem 23
Show that \(\cos 2 \theta=1-2 \sin ^{2} \theta\)
View solution Problem 23
a. Derive an identity for \(\sin \frac{1}{4} A\) in terms of \(\cos \frac{1}{2} A .\) b. Derive an identity for \(\cos \frac{1}{4} A\) in terms of \(\cos \frac{
View solution