Problem 22
Question
Find the slope of the tangent line to the graph of each function at the given point and determine an equation of the tangent line. \(f(x)=\frac{3}{2 x}\) at \(\left(1, \frac{3}{2}\right)\)
Step-by-Step Solution
Verified Answer
The slope of the tangent line to the graph of \(f(x) = \frac{3}{2x}\) at the point \((1, \frac{3}{2})\) is \(-\frac{3}{4}\), and the equation of the tangent line is \(y = -\frac{3}{4}x + \frac{5}{2}\).
1Step 1: Find the derivative of the function.
The given function is \(f(x) = \frac{3}{2x}\). To find the derivative with respect to \(x\), we will apply the power rule:
\(f(x) = 3\cdot (2x)^{-1}\)
Now use the power rule, \((x^n)' = nx^{n-1}\):
\(f'(x) = 3(-1)(2x)^{-2}\)
Simplify the expression:
\(f'(x) = -\frac{3}{4x^2}\)
2Step 2: Find the slope at the given point.
We have found the derivative \(f'(x) = -\frac{3}{4x^2}\), which gives the slope of the tangent line for any point on the graph of \(f(x)\). Now, we need to evaluate the derivative at the given point \((1, \frac{3}{2})\). Since the point lies on the graph of the function, we will plug in the given \(x\)-coordinate, \(1\), into the derivative:
\(m = f'(1) = -\frac{3}{4(1^2)}\)
\(m = -\frac{3}{4}\)
So, the slope of the tangent line at \((1, \frac{3}{2})\) is \(-\frac{3}{4}\).
3Step 3: Determine the equation of the tangent line.
Now that we have the slope of the tangent line (\(m = -\frac{3}{4}\)) and the point \((1,\frac{3}{2})\), we can use the point-slope form of the line to find the equation of the tangent line:
\(y - y_1 = m(x - x_1)\)
Plugging in the slope and the given point:
\(y - \frac{3}{2} = -\frac{3}{4}(x - 1)\)
Now, solve for \(y\) to get the equation of the tangent line:
\(y - \frac{3}{2} = -\frac{3}{4}x + \frac{3}{4}\)
\(y = -\frac{3}{4}x + \frac{3}{4} + \frac{3}{2}\)
\(y = -\frac{3}{4}x + \frac{5}{2}\)
Thus, the equation of the tangent line to the graph of \(f(x) = \frac{3}{2x}\) at the point \((1, \frac{3}{2})\) is \(y=-\frac{3}{4}x + \frac{5}{2}\).
Key Concepts
Tangent LineSlope of a CurvePower Rule
Tangent Line
In the realm of calculus, the tangent line is a fundamental concept that describes the straight line that touches a curve at a single point without crossing it. It essentially "hugs" the curve at that exact spot, providing an approximation of the curve's geometry at that point.
When you think about it, the tangent line tells us about the nature of the curve. It's like peeking into the curve's behavior around that particular point.
To find a tangent line to a curve at a point, we need two pieces of information:
When you think about it, the tangent line tells us about the nature of the curve. It's like peeking into the curve's behavior around that particular point.
To find a tangent line to a curve at a point, we need two pieces of information:
- The exact point on the curve where the line will touch.
- The slope of the tangent line at that point.
- \(y - y_1 = m(x - x_1)\) where \(m\) is the slope and \((x_1, y_1)\) is the point.
Slope of a Curve
The slope of a curve is crucial when working with derivatives and tangents. But what exactly is it?
Simply put, the slope at a specific point on a curve is the rate at which the curve rises or falls. It's the same idea as the slope of a straight line but applied to a nonlinear graph.
Simply put, the slope at a specific point on a curve is the rate at which the curve rises or falls. It's the same idea as the slope of a straight line but applied to a nonlinear graph.
- For curves, this involves solving the derivative of the function, which tells us the slope at any given point.
- In cases where a curve changes its steepness or direction, the slope varies depending on where you are on the curve.
- Calculate the derivative of the function to get a formula representing the slope for all points.
- Substitute the given point's x-coordinate into the derivative to find the slope at that specific location.
Power Rule
When it comes to differentiating functions, the power rule is one of the simplest and most efficient techniques in calculus.
If you have a function of the form \(x^n\), the power rule helps you quickly find its derivative.
The process involves the following steps:
Consider the function \(f(x) = \frac{3}{2x} = 3(2x)^{-1}\). Applying the power rule, recognize that the negative exponent can be handled just like any other exponent. Multiply and reduce the power:
If you have a function of the form \(x^n\), the power rule helps you quickly find its derivative.
The process involves the following steps:
- Multiply the exponent by the coefficient in front of the term.
- Decrement the exponent on the variable by one.
Consider the function \(f(x) = \frac{3}{2x} = 3(2x)^{-1}\). Applying the power rule, recognize that the negative exponent can be handled just like any other exponent. Multiply and reduce the power:
- Multiply 3 by -1, resulting in -3.
- Decrease the power from -1 to -2, eliminating one more from the exponent.
- Simplify the expression to: \(-\frac{3}{4x^2}\).
Other exercises in this chapter
Problem 22
Find the derivative of each function. \(f(x)=\frac{x^{3}-2}{x^{2}+1}\)
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Find the derivative of the function \(f\) by using the rules of differentiation. \(f(x)=0.002 x^{3}-0.05 x^{2}+0.1 x-20\)
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Find the indicated one-sided limit, if it exists. \(\lim _{x \rightarrow 1^{-}}(3 x-4)\)
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Sketch the graph of the function \(f\) and evaluate \(\lim _{x \rightarrow a} f(x)\), if it exists, for the given value of \(a\). \(f(x)=\left\\{\begin{array}{l
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