Problem 22
Question
Find the indicated one-sided limit, if it exists. \(\lim _{x \rightarrow 1^{-}}(3 x-4)\)
Step-by-Step Solution
Verified Answer
The one-sided limit as x approaches 1 from the negative side of the function \(f(x) = 3x - 4\) exists, and the value of the limit is \(\lim_{x \rightarrow 1^{-}}(3x-4) = -1\).
1Step 1: Understand the given function
The function given is a linear function, \(f(x) = 3x - 4\). The graph of this function is a straight line. Linear functions are continuous everywhere, which means that as x approaches any value, the limit from both sides of that value will always exist.
2Step 2: Evaluate the limit
Since this is a linear function, we can simply plug in the value of x that we are interested in, which in this case is x=1:
\(f(1) = 3(1) - 4 = -1\)
\[\lim _{x \rightarrow 1^{-}}(3 x-4) = -1\]
As f(x) is continuous everywhere, the limit of the given function as x approaches 1 from the negative side exists, and the value of the limit is -1.
Key Concepts
Linear FunctionsContinuity of FunctionsLimit Evaluation
Linear Functions
When it comes to linear functions, they are essentially the most basic type of algebraic function you can encounter. They are expressed in the form of a straight-line equation, typically represented as \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. The slope dictates the steepness of the line and the direction it tilts, while the y-intercept indicates the point where the line crosses the y-axis.
In our particular exercise, the linear function in question is \( f(x) = 3x - 4 \), clearly defining a slope of 3 and a y-intercept of -4. One essential characteristic of linear functions is their predictability and simplicity in calculating values. You can calculate the value of the function for any input \( x \) by using the equation directly, making it straightforward to evaluate limits, as shown in the original solution.
In our particular exercise, the linear function in question is \( f(x) = 3x - 4 \), clearly defining a slope of 3 and a y-intercept of -4. One essential characteristic of linear functions is their predictability and simplicity in calculating values. You can calculate the value of the function for any input \( x \) by using the equation directly, making it straightforward to evaluate limits, as shown in the original solution.
Continuity of Functions
Continuity is a foundational concept in calculus that determines whether a function smoothly transitions from one point to another without any gaps, jumps, or abrupt changes in direction. In more technical terms, a function is considered continuous at a point \( x = a \) if the following three conditions are met:
Linear functions are inherently continuous over their entire domain because they satisfy these three conditions at every point. This feature allows us to evaluate one-sided limits with the certainty that the function will not exhibit any 'surprises,' such as sudden jumps, at the point of interest.
- The function is defined at \( a \), meaning \( f(a) \) exists.
- The limit of the function as it approaches \( a \) exists.
- The limit of the function as it approaches \( a \) equals \( f(a) \).
Linear functions are inherently continuous over their entire domain because they satisfy these three conditions at every point. This feature allows us to evaluate one-sided limits with the certainty that the function will not exhibit any 'surprises,' such as sudden jumps, at the point of interest.
Limit Evaluation
Limit evaluation is a critical operation in calculus, used to predict a function's behavior as the input approaches a certain value. In the context of our exercise, we're exploring a one-sided limit—specifically, the limit as \( x \) approaches 1 from the left, denoted by \( x \rightarrow 1^{-} \). This notation signifies a scenario where we're only considering the values of \( x \) that are less than 1 (hence coming from the negative side).
The evaluation itself is straightforward for linear functions. Since there's no threat of discontinuity, we can simply substitute the \( x \) value directly into the function to find the limit. If the question asks for a limit that approaches from the negative side, like our problem does, it simply reinforces the value that the function would inherently approach. The step-by-step solution provided is a prime example of the practical application of this concept, with our limit being directly evaluated to \( -1 \) by substitution.
The evaluation itself is straightforward for linear functions. Since there's no threat of discontinuity, we can simply substitute the \( x \) value directly into the function to find the limit. If the question asks for a limit that approaches from the negative side, like our problem does, it simply reinforces the value that the function would inherently approach. The step-by-step solution provided is a prime example of the practical application of this concept, with our limit being directly evaluated to \( -1 \) by substitution.
Other exercises in this chapter
Problem 22
Find the derivative of the function \(f\) by using the rules of differentiation. \(f(x)=0.002 x^{3}-0.05 x^{2}+0.1 x-20\)
View solution Problem 22
Find the slope of the tangent line to the graph of each function at the given point and determine an equation of the tangent line. \(f(x)=\frac{3}{2 x}\) at \(\
View solution Problem 22
Sketch the graph of the function \(f\) and evaluate \(\lim _{x \rightarrow a} f(x)\), if it exists, for the given value of \(a\). \(f(x)=\left\\{\begin{array}{l
View solution Problem 23
Find the derivative of each function. \(f(x)=\left(x^{2}+1\right)^{3}-\left(x^{3}+1\right)^{2}\)
View solution