Problem 21
Question
Multiply and simplify. All variables represent positive real numbers. $$ \sqrt[3]{2} \cdot \sqrt[3]{12} $$
Step-by-Step Solution
Verified Answer
The product simplifies to \(2 \sqrt[3]{3}\).
1Step 1: Express Radicals as Powers
First, we need to express the cube roots using exponent notation. We can write the cube root of a number as that number raised to the power of \( \frac{1}{3} \). Thus, \( \sqrt[3]{2} = 2^{\frac{1}{3}} \) and \( \sqrt[3]{12} = 12^{\frac{1}{3}} \).
2Step 2: Apply the Product of Powers Property
Using the property of exponents that states \(a^{m} \cdot a^{n} = a^{m+n}\), we multiply the expressions: \(2^{\frac{1}{3}} \cdot 12^{\frac{1}{3}} = (2 \cdot 12)^{\frac{1}{3}} \).
3Step 3: Simplify Inside the Radical
Multiply the numbers inside the parentheses: \(2 \cdot 12 = 24\). So we have \((2 \cdot 12)^{\frac{1}{3}} = 24^{\frac{1}{3}}\).
4Step 4: Breakdown 24 to Simplify
Factor 24 to simplify further: \(24 = 2^3 \cdot 3\). So, \(24^{\frac{1}{3}} = (2^3 \cdot 3)^{\frac{1}{3}}\).
5Step 5: Apply the Power of a Product Property
Applying the property \((a \cdot b)^m = a^m \cdot b^m\), we have: \((2^3 \cdot 3)^{\frac{1}{3}} = (2^3)^{\frac{1}{3}} \cdot 3^{\frac{1}{3}} = 2^{\frac{3}{3}} \cdot 3^{\frac{1}{3}}\).
6Step 6: Simplify the Expression
Since \(2^{\frac{3}{3}} = 2^1 = 2\), we can simplify the expression to \(2 \cdot 3^{\frac{1}{3}}\).
7Step 7: Write the Final Simplified Form
Thus, the simplified form of the expression is \(2 \sqrt[3]{3}\).
Key Concepts
Product of PowersSimplifying RadicalsPower of a Product
Product of Powers
To understand the concept of the "product of powers," we begin by expressing radicals as powers. When we have cube roots, these can be rewritten as numbers raised to the power of \(\frac{1}{3}\). For example, \(\sqrt[3]{2}\) is equivalent to \(2^{\frac{1}{3}}\). This allows us to correctly apply properties of exponents. The product of powers property states that when multiplying like bases with exponents, you add the exponents together. Mathematically, \[a^m \cdot a^n = a^{m+n}\] Here, since the bases are numbers, \(2^{\frac{1}{3}} \cdot 12^{\frac{1}{3}}\) isn't directly combining because the bases are different (2 and 12). However, understanding powers equips us to rearrange and manipulate expressions, including combining like bases. If the bases were the same, we would simply add \(m\) and \(n\) together. By rewriting and combining, such as multiplying under a single radical (when possible), we leverage this powerful tool to simplify expressions effectively.
Simplifying Radicals
Simplifying radicals involves breaking down complex root expressions into simpler, more manageable forms. When we encounter a problem like \(\sqrt[3]{24}\), our task is to simplify the expression by finding perfect cubes inside the radical, if any.
- First, factor the number into its prime components: for instance, 24 factors to \(2^3 \cdot 3\).
- Next, identify a perfect cube factor. Here, \(2^3\) is a perfect cube of 2.
Power of a Product
When dealing with expressions like \((a \cdot b)^m\), we use the "power of a product" property to streamline simplification. This property says that you can distribute the exponent \(m\) across the base components in a multiplication, such that: \[(a \cdot b)^m = a^m \cdot b^m\] Applying this concept can significantly clarify problems that include multiple terms under a single radical or exponent. For example, consider \((2^3 \cdot 3)^{\frac{1}{3}}\). By using this property:
- Distribute \(\frac{1}{3}\) to both 2 and 3 separately: \((2^3)^{\frac{1}{3}}\) and \(3^{\frac{1}{3}}\).
- This becomes \(2^{\frac{3}{3}} \cdot 3^{\frac{1}{3}}\).
Other exercises in this chapter
Problem 20
Simplify each expression. $$ \sqrt[4]{32} $$
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Solve each equation. $$ \sqrt{6 x+1}=5 $$
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Translate each sentence into mathematical symbols. a. The square root of \(x\) squared is the absolute value of \(x .\) b. The cube root of \(x\) cubed is \(x\)
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The lengths of two sides of the right triangle \(A B C\) are given. Find the length of the missing side. \(a=10 \mathrm{cm}\) and \(c=26 \mathrm{cm}\) (RIGHT TR
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