Problem 20
Question
Simplify each expression. $$ \sqrt[4]{32} $$
Step-by-Step Solution
Verified Answer
\( 2 \cdot \sqrt[4]{2} \)
1Step 1: Express the Number Under the Root
First, we express 32 as a power of 2, since it’s a factor of 32 and can be easily managed. We recognize that 32 can be written as, \[ 32 = 2^5 \].
2Step 2: Rewrite the Expression Using Exponent Form
Replace the number inside the radical with its exponential form: \[ \sqrt[4]{32} = \sqrt[4]{2^5} \].
3Step 3: Use the Property of Radicals
Apply the property of radicals, \( \sqrt[n]{a^m} = a^{\frac{m}{n}} \), to convert the fourth root into an exponent: \[ (2^5)^{\frac{1}{4}} = 2^{\frac{5}{4}} \].
4Step 4: Simplify the Fractional Exponent
Simplify the expression by separating integer powers from fractional powers, \[ 2^{\frac{5}{4}} = 2^{1 + \frac{1}{4}} = 2^1 \cdot 2^{\frac{1}{4}} \].
5Step 5: Calculate the Integer Power
Calculate the integer component, which is straightforward: \[ 2^1 = 2 \].
6Step 6: Express the Final Answer in Radical Form
Realize that the fractional part \(2^{\frac{1}{4}}\) is equivalent to the fourth root of 2. So, the expression becomes: \[ 2 \cdot \sqrt[4]{2} \].
Key Concepts
ExponentsProperties of RadicalsFractional Exponents
Exponents
Exponents are a way to express repeated multiplication of the same number. When you see something like \( 2^5 \), it means that 2 is multiplied by itself 5 times: \( 2 \times 2 \times 2 \times 2 \times 2 = 32 \). This shorthand notation simplifies expressions and calculations. Exponents consist of two parts:
- The base (2 in this case), which is the number being multiplied.
- The exponent (5), which tells you how many times to multiply the base by itself.
Properties of Radicals
Radicals involve root functions, like square roots or cube roots. The radical symbol \( \sqrt{} \) often indicates these operations. An important property to remember is that radicals and exponents are closely connected. This is useful for simplifying expressions. A key property is \( \sqrt[n]{a^m} = a^{\frac{m}{n}} \), which lets us convert radical expressions into fractions with exponents. This is handy because working with exponents is often more manageable than with radicals. Another crucial point is that:
- If two radicals have the same index (the little number outside the root symbol), you can multiply the radicands (the stuff inside the root) together under a single radical. For instance, \( \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \).
- If you have a radical raised to a power, the power can be applied either to the radicand first or to the entire expression, like \( (\sqrt{a})^n = (a^{\frac{1}{2}})^n \).
Fractional Exponents
Fractional exponents are another way to represent roots. They can make complex root operations easier to deal with and appear when converting between radicals and exponents. Here, the numerator of the fraction is the power, and the denominator is the root. For example, \( a^{\frac{m}{n}} \) implies that you're finding the \( n \)-th root of \( a^m \). This could be thought of as \( \sqrt[n]{a^m} \), but written as an exponent.To understand the simplification:
- Convert \( n \)-th roots to fractional exponents using the formula \( \sqrt[n]{a} = a^{\frac{1}{n}} \).
- Multiply fractional exponents just like you would with whole numbers: \( a^{\frac{m}{n}} \cdot a^{\frac{p}{q}} = a^{\frac{mq + pn}{nq}} \).
Other exercises in this chapter
Problem 20
Multiply and simplify. All variables represent positive real numbers. $$ (2 \sqrt[3]{16})(-\sqrt[3]{4}) $$
View solution Problem 20
The lengths of two sides of the right triangle \(A B C\) are given. Find the length of the missing side. \(b=18 \mathrm{m}\) and \(c=82 \mathrm{m}\) (RIGHT TRIA
View solution Problem 20
Solve each equation. $$ \sqrt{6 x+1}=5 $$
View solution Problem 21
Multiply and simplify. All variables represent positive real numbers. $$ \sqrt[3]{2} \cdot \sqrt[3]{12} $$
View solution