Problem 21
Question
Graph the functions in Exercises \(13-22 .\) What is the period of each function? $$\sin \left(x-\frac{\pi}{4}\right)+1$$
Step-by-Step Solution
Verified Answer
The period of the function is \(2\pi\).
1Step 1: Identify the Base Function
The given function is \( \sin \left(x-\frac{\pi}{4}\right)+1 \). The base function here is the sine function \( \sin(x) \). We will analyze how this base function is transformed.
2Step 2: Determine Horizontal Shift
The expression inside the sine function is \( x - \frac{\pi}{4} \). This indicates a horizontal shift to the right by \( \frac{\pi}{4} \). The graph of the sine function will start \( \frac{\pi}{4} \) units to the right.
3Step 3: Determine Vertical Shift
The entire function is \( \sin \left(x-\frac{\pi}{4}\right)+1 \). The \(+1\) denotes a vertical shift upwards by 1 unit. Each point on the sine graph is moved 1 unit up.
4Step 4: Identify Period of Sine Function
The period of the basic sine function \( \sin(x) \) is \( 2\pi \). This period is not altered by horizontal or vertical shifts, so it remains \( 2\pi \) for this function.
5Step 5: Conclusion on Period
Even after incorporating shifts (horizontal or vertical), the period of \( \sin \left(x-\frac{\pi}{4}\right)+1 \) remains \( 2\pi \). Therefore, the function completes one full cycle every \( 2\pi \) units.
Key Concepts
Sine FunctionPeriod of FunctionFunction Transformations
Sine Function
The sine function, represented as \(\sin(x)\), is a fundamental trigonometric function that describes a smooth, periodic wave. The graph of the basic sine function is a continuous wave that oscillates between -1 and 1, moving above and below the x-axis. Each complete wave cycle of \(\sin(x)\) repeats over an interval known as the "period." This inherent property makes sine waves crucial in modeling repetitive phenomena such as sound or light waves.
- The sine wave starts at the origin \((0,0)\) and rises to a maximum point of 1 at \(\frac{\pi}{2}\).
- It returns to zero at \(\pi\), dips to a minimum of -1 at \(\frac{3\pi}{2}\), and completes the cycle back at zero at \(2\pi\).
Period of Function
The period of a function, especially in trigonometry, refers to the length of one complete cycle of the wave before it repeats. For the basic sine function \(\sin(x)\), the period is \(2\pi\). This means that every \(2\pi\) units along the x-axis, the sine wave starts a new cycle. The period is crucial when graphing as it dictates the spacing of the repeating pattern.
- For \(\sin(x)\), alterations in the equation like \(\sin(kx)\) can affect the period, where the period becomes \(\frac{2\pi}{k}\).
- However, shifts in the sine function, such as horizontal or vertical shifts (like in the given function), do not change the period; it remains \(2\pi\).
Function Transformations
Function transformations are modifications that alter the appearance of the graph without changing the fundamental nature of the function. When dealing with transformations of the sine function, the main changes include vertical and horizontal shifts, as well as reflections and dilations.
- Vertical Shifts: Adding or subtracting a constant (e.g., \(+1\) in \(\sin(x) + 1\)) moves the entire graph up or down accordingly.
- Horizontal Shifts: Adjustments inside the function's argument, such as \(x - \frac{\pi}{4}\), shift the graph left or right. The given function shifts the sine wave right by \(\frac{\pi}{4}\) units.
- Amplitude Changes: Altering the coefficient of \(\sin\) (unseen in this problem) affects the wave’s height.
Other exercises in this chapter
Problem 20
Find the natural domain and graph the functions in Exercises \(15-20 .\) $$G(t)=1 /|t|$$
View solution Problem 21
Find an appropriate graphing software viewing window for the given function and use it to display its graph. The window should give a picture of the overall beh
View solution Problem 21
Find the domain of $$y=\frac{x+3}{4-\sqrt{x^{2}-9}}$$
View solution Problem 22
Find the range of $$y=2+\frac{x^{2}}{x^{2}+4}$$
View solution