Problem 21
Question
Find an appropriate graphing software viewing window for the given function and use it to display its graph. The window should give a picture of the overall behavior of the function. There is more than one choice, but incorrect choices can miss important aspects of the function. \begin{equation} f(x)=\frac{x-1}{x^{2}-x-6} \end{equation}
Step-by-Step Solution
Verified Answer
Set the window to \(-5 \leq x \leq 5\) and \(-10 \leq y \leq 10\).
1Step 1: Factor the Denominator
First, we need to factor the quadratic expression in the denominator of the function \( f(x) = \frac{x-1}{x^2-x-6} \). The denominator \( x^2 - x - 6 \) can be factored as \( (x - 3)(x + 2) \).
2Step 2: Identify Discontinuities
The function \( f(x) = \frac{x-1}{(x-3)(x+2)} \) is undefined where the denominator is zero. Therefore, the points \( x = 3 \) and \( x = -2 \) are vertical asymptotes. These are important discontinuities to consider when choosing the viewing window.
3Step 3: Determine Horizontal Asymptote
As \( x \to \pm \infty \), the function behaves like \( \frac{x}{x^2} = \frac{1}{x} \), which approaches 0 as \( x \) goes to \( \pm \infty \). Thus, the line \( y = 0 \) is a horizontal asymptote.
4Step 4: Consider the Behavior Near Asymptotes
Consider the behavior of the function near the asymptotes: around \( x = 3 \) and \( x = -2 \), the function dramatically increases or decreases, confirming the presence of vertical asymptotes.
5Step 5: Set Graphing Software Viewing Window
A suitable window for viewing the overall behavior of this function can be \(-5 \leq x \leq 5\) for the x-axis and \(-10 \leq y \leq 10\) for the y-axis. This includes extreme changes near asymptotes and the horizontal asymptote along the axis.
Key Concepts
Vertical AsymptotesHorizontal AsymptotesFactoring Quadratics
Vertical Asymptotes
Vertical asymptotes are lines where a graph heads towards infinity or negative infinity. They are essentially boundaries that the function cannot touch or cross. To find these in a rational function, you look at the points that cause the denominator to be zero. For the function \( f(x) = \frac{x-1}{x^2-x-6} \), the denominator is \( x^2 - x - 6 \). Factoring this quadratic gives \((x-3)(x+2)\). The points where these factors equal zero, \(x = 3\) and \(x = -2\), are where the function is undefined. These become your vertical asymptotes.
- At \(x = 3\), the graph approaches but never touches this vertical line.
- At \(x = -2\), a similar behavior occurs.
Horizontal Asymptotes
Horizontal asymptotes help us understand the end behavior of a rational function, or how the function behaves as \(x\) goes to infinity or negative infinity. For the function \( f(x) = \frac{x-1}{x^2-x-6} \), analyzing the degrees of the polynomial in the numerator and the denominator helps find this line. Here, the numerator \(x-1\) has degree 1, and the denominator \(x^2-x-6\) has degree 2.
- When the degree of the denominator is higher than the numerator, the horizontal asymptote is \(y = 0\).
Factoring Quadratics
Factoring quadratics is a fundamental skill in algebra that involves expressing a quadratic expression as a product of its linear factors. This step is often crucial for finding the roots of the quadratic equation and can help simplify rational expressions. Take the quadratic \(x^2 - x - 6\). To factor this, we're looking for two numbers that multiply to \(-6\) (the constant term) and add up to \(-1\) (the coefficient of the middle term).
- \(x^2 - x - 6 = (x-3)(x+2)\), where \(-3\) and \(+2\) multiply to \(-6\) and add to \(-1\).
Other exercises in this chapter
Problem 20
Find an appropriate graphing software viewing window for the given function and use it to display its graph. The window should give a picture of the overall beh
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Graph the functions in Exercises \(13-22 .\) What is the period of each function? $$\sin \left(x-\frac{\pi}{4}\right)+1$$
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Find the domain of $$y=\frac{x+3}{4-\sqrt{x^{2}-9}}$$
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