Problem 21
Question
Find the value of the indicated variable. Round approximate answers to three decimal places. Find \(f\) if \(M=10, F=5,\) and \(M=\frac{F}{f}\)
Step-by-Step Solution
Verified Answer
f = 0.5
1Step 1: Write Down the Given Equation
The given equation is \[M = \frac{F}{f}\].
2Step 2: Substitute Given Values
Substitute the given values for variables M and F into the equation: \[10 = \frac{5}{f}\].
3Step 3: Solve for \( f \)
To find \( f \), multiply both sides of the equation by \( f \) to get: \[10f = 5\].
4Step 4: Isolate \( f \)
Divide both sides of the equation by 10 to isolate \( f \): \[f = \frac{5}{10}\].
5Step 5: Simplify the Fraction
Simplify the fraction: \[f = 0.5\].
Key Concepts
AlgebraVariable IsolationFractions
Algebra
Algebra is a branch of mathematics that deals with symbols and the rules for manipulating those symbols. In this exercise, we work with an equation that includes fractions. An equation is a statement that two expressions are equal. Understanding how to form and solve equations using algebra is crucial in mathematics. When dealing with equations, we often need to substitute known values for variables and perform operations to isolate the unknown variable.
Variable Isolation
Variable isolation is a key concept in algebra. It involves rearranging an equation to make one variable stand alone on one side of the equation.
Let's break it down:
By isolating the variable, we find the solution to the equation.
Let's break it down:
- First, identify the variable you need to isolate. In our example, it's the variable \( f \).
- Next, use algebraic operations such as addition, subtraction, multiplication, and division to move all other terms to the opposite side of the equation.
- In our case, we multiplied both sides of the equation by \( f \) to remove the fraction: \(10f = 5 \).
- Then, we divided both sides by 10 to isolate \( f \): \( f = \frac{5}{10} \).
By isolating the variable, we find the solution to the equation.
Fractions
Fractions represent a part of a whole and are written in the form of \(\frac{numerator}{denominator}\). In this exercise, fractions were used to express the relationship between the variables.
Here's a simple way to handle fractions in equations:
Simplifying fractions makes the equation easier to solve. It's essential to practice fraction operations to master solving algebraic equations.
Here's a simple way to handle fractions in equations:
- To get rid of a fraction, multiply both sides of the equation by the denominator of the fraction.
- In our example, we had \( M = \frac{F}{f} \) which became \(10 = \frac{5}{f} \). By multiplying both sides by the denominator \( f \), we eliminated the fraction.
- We performed a multiplication on both sides: \(10 f = 5 \).
- Once the fraction was cleared, we simplified the equation by isolating \( f \).
Simplifying fractions makes the equation easier to solve. It's essential to practice fraction operations to master solving algebraic equations.
Other exercises in this chapter
Problem 20
Reduce each rational expression to its lowest terms. $$\frac{14}{91}$$
View solution Problem 21
Find the solution set to each equation. $$5+\frac{9}{x-2}=2+\frac{x+7}{x-2}$$
View solution Problem 21
Reduce each rational expression to its lowest terms. $$\frac{42}{210}$$
View solution Problem 22
Find the solution set to each equation. $$3+\frac{x+1}{x-3}=2-\frac{5-3 x}{x-3}$$
View solution