Problem 202
Question
Which of the following is the correct order of decreasing \(\mathrm{SN}^{2}\) reactivity? (a) \(\mathrm{RCH}_{2} \mathrm{X}>\mathrm{R}_{2} \mathrm{CHX}>\mathrm{R}_{3} \mathrm{CX}\) (b) \(\mathrm{R}_{3} \mathrm{CX}>\mathrm{R}_{2} \mathrm{CHX}>\mathrm{RCH}_{2} \mathrm{X}\) (c) \(\mathrm{R}_{2} \mathrm{CHX}>\mathrm{R}_{3} \mathrm{CX}>\mathrm{RCH}_{2} \mathrm{X}\) (d) \(\mathrm{RCH}_{2} \mathrm{X}>\mathrm{R}_{3} \mathrm{CX}>\mathrm{R}_{2} \mathrm{CHX}\)
Step-by-Step Solution
Verified Answer
The correct order of decreasing SN2 reactivity is option (a): \(\mathrm{RCH}_{2} \mathrm{X}>\mathrm{R}_{2} \mathrm{CHX}>\mathrm{R}_{3} \mathrm{CX}\.\)
1Step 1: Understand SN2 Reactivity
The reactivity in an SN2 mechanism is inversely related to steric hindrance. This means that the less crowded the carbon center where the reaction occurs, the more reactive it will be. Typically, primary alkyl halides react faster than secondary, which react faster than tertiary due to increasing steric hindrance.
2Step 2: Analyzing the Options
Let's analyze each option based on what we just learned about steric hindrance and SN2 reactivity:
- (a) suggests primary > secondary > tertiary.
- (b) suggests tertiary > secondary > primary.
- (c) suggests secondary > tertiary > primary.
- (d) suggests primary > tertiary > secondary.
3Step 3: Identify the Correct Order
Based on the theory of SN2 reactivity, primary alkyl halides ({RCH2X}) are the most reactive, followed by secondary ({R2CHX}), and tertiary ({R3CX}) are the least reactive. Therefore, the correct order is primary (least steric hindrance) > secondary > tertiary.
4Step 4: Choose the Correct Option
Now, compare the theoretical order to the given options. Option (a) matches the expected order of primary > secondary > tertiary. Thus, option (a) is the correct answer for decreasing SN2 reactivity.
Key Concepts
Steric HindrancePrimary Alkyl HalideSecondary Alkyl HalideTertiary Alkyl Halide
Steric Hindrance
Steric hindrance is a crucial concept in understanding the reactivity of chemical compounds, especially within organic chemistry. Imagine trying to squeeze through a crowded room; the more people there, the harder it is to move. Similarly, in a chemical structure, the more atoms or groups near a reactive center, the harder it is for a reaction to occur.
In an SN2 reaction, a nucleophile attacks a substrate, displacing a leaving group in a one-step process. If there are fewer atoms around the reactive center (usually a carbon atom), the nucleophile can approach more easily and react faster. That's why compounds with low steric hindrance, like primary alkyl halides, react more readily in SN2 reactions.
In an SN2 reaction, a nucleophile attacks a substrate, displacing a leaving group in a one-step process. If there are fewer atoms around the reactive center (usually a carbon atom), the nucleophile can approach more easily and react faster. That's why compounds with low steric hindrance, like primary alkyl halides, react more readily in SN2 reactions.
- Less crowded = more reactive in SN2
- More crowded = less reactive in SN2
Primary Alkyl Halide
Primary alkyl halides have the structure RCH2X, where the halogen (X) is bonded to a carbon that is attached to only one other carbon. This configuration leads to minimal steric hindrance, allowing nucleophiles easy access to the carbon center. Because of this lack of crowding, primary alkyl halides are generally the most reactive in SN2 reactions.
- Structure: RCH2X
- Little crowding around carbon makes Nucleophilic Attack easy
- Most reactive in SN2 reactions
Secondary Alkyl Halide
Secondary alkyl halides are positioned between primary and tertiary in terms of reactivity in SN2 reactions. Their general formula is R2CHX, where the halogen is attached to a carbon linked to two other carbons. This introduces more steric hindrance than in primary alkyl halides, but still less than tertiary ones.
- Formula: R2CHX
- More steric hindrance than primary; less than tertiary
- Moderate reactivity in SN2 reactions
Tertiary Alkyl Halide
Tertiary alkyl halides, with the structure R3CX, are characterized by a carbon atom bonded to three other carbon atoms. This structure makes them the most crowded and thus the least reactive in SN2 reactions due to the high steric hindrance.
- Structure: R3CX
- Maximum steric hindrance
- Least reactive in SN2 reactions
Other exercises in this chapter
Problem 198
Reaction of trans-2-phenyl-1-bromocyclopentane on reaction with alcoholic KOH produces (a) 4-phenylcyclopentene (b) 2-phenylcyclopentene (c) 1 -phenylcyclopente
View solution Problem 201
The increasing order of stability of the following free radicals is (a) \(\left(\mathrm{CH}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}
View solution Problem 204
The correct order of increasing basicity of the given conjugate bases \(\left(\mathrm{R}=\mathrm{CH}_{3}\right)\) is (a) \(\mathrm{RCO} \overline{\mathrm{O}}
View solution Problem 206
The order of stability of the following carbocations: (I) \(\mathrm{CH}_{2}=\mathrm{CH}-\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}\) \(\mathbf{[ 2 0 1 3}]\) (
View solution