Problem 201
Question
The increasing order of stability of the following free radicals is (a) \(\left(\mathrm{CH}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}<\left(\mathrm{CH}_{3}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{2} \dot{\mathrm{C}} \mathrm{H}<\left(\mathrm{C}_{6} \mathrm{H}_{3}\right)_{3} \dot{\mathrm{C}}\) (b) \(\left(\mathrm{C}_{6} \mathrm{H}_{3}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{2} \dot{\mathrm{C}} \mathrm{H}<\left(\mathrm{CH}_{3}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{CH}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}\) (c) \(\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{2} \dot{\mathrm{C}} \mathrm{H}<\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{CH}_{3}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{CH}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}\) (d) \(\left(\mathrm{CH}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}<\left(\mathrm{CH}_{3}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \dot{\mathrm{C}}<\left(\mathrm{C}_{6} \mathrm{H}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}\)
Step-by-Step Solution
VerifiedKey Concepts
Radical Stability
Free radical stability is often governed by both structural factors and electronic effects. Two primary structural factors that stabilize radicals are resonance and hyperconjugation. Elevated stability is achieved when the radical's lone electron can be delocalized across a larger molecular framework.
Typically, radicals that permit electron delocalization, whether through resonance in conjugated systems or hyperconjugation through alkyl groups, exhibit greater stability. This delocalization distributes the radical's energy and makes the entire molecule more stable.
Resonance Stabilization
Molecules with aromatic phenyl rings, like benzene, are prime examples where electrons can resonate between different locations. This ability to spread out the electron density makes such radicals more stable than those that do not have resonance capability.
Resonance comes into play with radicals such as
- Those containing phenyl groups,
- Polyphenyl radicals,
- Benzyl radicals.
Hyperconjugation
This effect occurs when electrons in sigma bonds (typically C-H or C-C bonds) adjacent to the radical center overlap with the free radical's p orbital.
The interaction aids in dispersing the electron density away from the radical center and slightly reduces the radical's reactivity.
For example, larger alkyl radicals like
- Tertiary radicals are generally
- More stable than secondary radicals,
- And secondary radicals are more stable than primary radicals.
Phenyl Groups
These groups are composed of an aromatic ring with alternating double and single bonds, allowing for extensive electron delocalization.
Radicals that feature phenyl groups can effectively stabilize an unpaired electron due to resonance diffusion across the aromatic ring, effectively utilizing the ring's conjugated double bonds.
- Phenyl radicals like the triphenylmethyl radical,
- And diphenylmethyl radical exhibit stability due to
- The expanded electron distribution within their aromatic systems.
Alkyl Groups
Their role becomes more significant with increasing numbers of carbon atoms surrounding the radical center.
Tertiary alkyl radicals, in particular, benefit from enhanced stability because they have numerous C-H bonds capable of participating in hyperconjugation.
- As you move from methyl radicals to tertiary carbon radicals,
- The stability increases due to a higher number of supporting
- C-H bonds involved in hyperconjugation.