Problem 20
Question
Solve each inequality. Graph the solution set, and write it using interval notation. \(-\frac{2}{3} x \leq 12\)
Step-by-Step Solution
Verified Answer
x \geq -18; [-18, \infty)
1Step 1 - Isolate the variable
To solve the inequality \(-\frac{2}{3} x \leq 12\), first isolate the variable x. Start by multiplying both sides of the inequality by the reciprocal of -\(\frac{2}{3}\). Since we multiply or divide by a negative number, we must reverse the inequality sign. The reciprocal of -\(\frac{2}{3}\) is -\(\frac{3}{2}\): \[ \left( -\frac{3}{2} \right) \left( -\frac{2}{3} x \right) \geq 12 \left( \frac{3}{2} \right) \]
2Step 2 - Simplify
Simplify both sides of the inequality: \[ x \geq 12 \times -\frac{3}{2} \] \[ x \geq -18 \]
3Step 3 - Graph the solution set
On a number line, shade all numbers greater than or equal to -18. This means starting from -18 and shading to the right with a closed circle at -18.
4Step 4 - Write the solution in interval notation
The solution in interval notation is written as: \([-18, \infty)\). This interval includes all numbers from -18 to positive infinity, and it includes -18.
Key Concepts
InequalitiesInterval NotationReciprocalGraphing Inequalities
Inequalities
Inequalities are mathematical statements that show the relationship between two expressions that are not necessarily equal. In the given exercise, we have an inequality: equation: \[ -\frac{2}{3} x \leq 12 \]
To solve inequalities, we use similar techniques as we do for solving equations, with one key difference: whenever we multiply or divide both sides of an inequality by a negative number, we must reverse the inequality sign. Inequalities can be of different types, such as <, >, ≤, and ≥.
Understanding inequalities is crucial because they allow us to find ranges of values rather than a single specific value, giving us more flexibility and real-world applicability.
To solve inequalities, we use similar techniques as we do for solving equations, with one key difference: whenever we multiply or divide both sides of an inequality by a negative number, we must reverse the inequality sign. Inequalities can be of different types, such as <, >, ≤, and ≥.
Understanding inequalities is crucial because they allow us to find ranges of values rather than a single specific value, giving us more flexibility and real-world applicability.
Interval Notation
Once we solve an inequality, we often express the solution using interval notation. Interval notation is a way of writing subsets of the real number line. For the given solution, we obtained:\[ x \geq -18 \]
Interval notation for this inequality is:” \[ [-18, \infty) \]
Here,
Interval notation for this inequality is:” \[ [-18, \infty) \]
Here,
- '[' means the interval includes -18.
- ',' denotes a separation between the two bounds.
- ‘∞’ means it extends to positive infinity.
- ')' indicates that the interval does not include ∞.
Reciprocal
In this exercise, we used the reciprocal of a fraction to isolate the variable. The reciprocal of a number is what you multiply that number by to get 1. For the fraction \[ -\frac{2}{3} \], we need to identify its reciprocal. We flip the numerator and the denominator, so the reciprocal is\[ -\frac{3}{2} \].
When we multiply both sides of our inequality \[ -\frac{2}{3} x \leq 12 \] by the reciprocal \[ -\frac{3}{2} \], we must remember to reverse the inequality sign. This step allows us to isolate the variable x and simplify to find the solution.
When we multiply both sides of our inequality \[ -\frac{2}{3} x \leq 12 \] by the reciprocal \[ -\frac{3}{2} \], we must remember to reverse the inequality sign. This step allows us to isolate the variable x and simplify to find the solution.
Graphing Inequalities
To visually represent the solution, we graph it on a number line. For the inequality \[ x \geq -18, \] we need to shade all values greater than or equal to -18. Here's how to graph it:
- Draw a number line.
- Locate -18 on the number line.
- Use a closed circle (or dot) at -18 to indicate that -18 is included in the solution.
- Shade the number line to the right of -18, extending to positive infinity.
Other exercises in this chapter
Problem 20
Solve each formula for the specified variable. \(y=m x+b\) (slope-intercept form of a linear equation) (a) for \(x\) (b) for \(m\)
View solution Problem 20
Solve each equation. $$ \left|14-\frac{1}{3} x\right|=8 $$
View solution Problem 20
Solve each compound inequality. Graph the solution set, and write it using interval notation. $$ x0 $$
View solution Problem 20
Translate each verbal sentence into an equation, using \(x\) as the variable. Then solve the equation. $$ \text { When } 75 \% \text { of a number is added to }
View solution