Problem 20
Question
For each equation, find the slope \(m\) and \(y\) -intercept \((0, b)\) (when they exist) and draw the graph. $$ y=-3 $$
Step-by-Step Solution
Verified Answer
Slope \( m = 0 \), y-intercept \((0, -3)\). The graph is a horizontal line at \( y = -3 \).
1Step 1: Identify the Equation Type
The given equation is \( y = -3 \). This is a linear equation where \( y \) is constant and does not depend on \( x \).
2Step 2: Determine the Slope
Since \( y \) does not change with \( x \) (as there is no \( x \) term in the equation), the slope \( m \) is 0. This means the line is horizontal.
3Step 3: Find the y-intercept
The y-intercept \((0, b)\) is the point where the graph crosses the y-axis. Since \( y = -3 \) for all values of \( x \), the y-intercept is \((0, -3)\).
4Step 4: Sketch the Graph
Draw a horizontal line across the coordinate plane at \( y = -3 \). All points on this line have y-coordinate of -3, indicating that the line does not rise or fall as \( x \) changes.
Key Concepts
Slope of a LineY-InterceptGraphing Linear Equations
Slope of a Line
Understanding the slope of a line is crucial when working with linear equations. Slope is a measure of how steep a line is. Think of it as how much the line "goes up" for each step you take horizontally. Mathematically, this is often expressed as the change in the vertical direction (rise) over the change in the horizontal direction (run).
This concept is usually associated with a variable called "m". For instance, in an equation like \( y = mx + b \), "m" represents the slope. A positive slope indicates the line rises as you move from left to right, while a negative slope tells you the line falls. In the given exercise, the equation is \( y = -3 \). Here, there is no \( x \) term, meaning the slope \( m \) is 0.
This concept is usually associated with a variable called "m". For instance, in an equation like \( y = mx + b \), "m" represents the slope. A positive slope indicates the line rises as you move from left to right, while a negative slope tells you the line falls. In the given exercise, the equation is \( y = -3 \). Here, there is no \( x \) term, meaning the slope \( m \) is 0.
- Zero slope: The line is horizontal and does not rise or fall.
- Positive slope: The line increases from left to right.
- Negative slope: The line decreases from left to right.
Y-Intercept
The y-intercept is the point where your line touches or crosses the y-axis. This special point provides valuable information about the equation's behavior, especially when graphing it. Essentially, it tells us the value of \( y \) when \( x \) is zero.
In the equation \( y = mx + b \), "b" is the y-intercept. It's the constant term. For the exercise you have, the equation is \( y = -3 \). This means that for every \( x \), \( y \) is consistently \(-3\). Thus, the y-intercept is the point \((0, -3)\).
In the equation \( y = mx + b \), "b" is the y-intercept. It's the constant term. For the exercise you have, the equation is \( y = -3 \). This means that for every \( x \), \( y \) is consistently \(-3\). Thus, the y-intercept is the point \((0, -3)\).
- Y-intercept of \( (0, -3) \) signals that the line crosses the y-axis at this point.
- It's a fixed point on the graph where the line intersects the y-axis.
- Provides a starting point when sketching the graph.
Graphing Linear Equations
Graphing linear equations is a visual way to represent how an equation looks on a coordinate plane. By plotting the y-intercept first and then using the slope, you can sketch the entire line step-by-step.
For the equation \( y = -3 \):
For the equation \( y = -3 \):
- Identify the slope and y-intercept first. The slope here is \( 0 \), and the y-intercept is \( (0, -3) \).
- Since the slope is \( 0 \), the line is horizontal. This means you draw a straight line parallel to the x-axis, passing through \( y = -3 \).
- Each point on the line will have a y-value of \(-3\), regardless of the x-value.
Other exercises in this chapter
Problem 20
For each function: a. Evaluate the given expression. b. Find the domain of the function. c. Find the range. $$ f(x)=\frac{1}{\sqrt{x}} ; \text { find } f(4) $$
View solution Problem 20
Solve each equation by factoring. [Hint for: First factor out a fractional power.] $$ 2 x^{7 / 2}+8 x^{5 / 2}=24 x^{3 / 2} $$
View solution Problem 21
Evaluate each expression without using a calculator. $$ 16^{3 / 4} $$
View solution Problem 21
For each function: a. Evaluate the given expression. b. Find the domain of the function. c. Find the range. $$ f(x)=\sqrt{-x} ; \text { find } f(-25) $$
View solution