Problem 20
Question
Begin by graphing the square root function, \(f(x)=\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$ g(x)=2 \sqrt{x+1} $$
Step-by-Step Solution
Verified Answer
The graph of \(g(x) = 2 \sqrt{x+1}\) can be obtained by vertically stretching the graph of \(f(x) = \sqrt{x}\) by a factor of 2, and then shifting it one unit to the left.
1Step 1: Graph the basic function
Start by graphing the basic function \(f(x) = \sqrt{x}\). This is a function that starts at the origin (0, 0) and increases as x increases, forming a curve.
2Step 2: Identify the transformations
Looking at the function \(g(x) = 2 \sqrt{x+1}\), there are two transformations to the basic square root function. The '2' before the square root is a vertical stretch: this means the y-values of the function are doubled. The '+1' inside the square root is a horizontal shift: it moves the function one unit to the left.
3Step 3: Apply the transformations
Now apply these transformations to the graph of \(f(x) = \sqrt{x}\). All the y-values will be double of what they were in the original function, and the entire curve will shift one unit to the left. This forms the graph of \(g(x) = 2 \sqrt{x+1}\).
Key Concepts
Square Root FunctionVertical StretchHorizontal Shift
Square Root Function
The square root function is an essential building block for understanding many mathematical concepts. It is defined as \( f(x) = \sqrt{x} \). In simpler terms, this function returns the square root of a given non-negative input \( x \). The graph of this function is quite distinctive:
- It starts at the origin, (0, 0), which means it doesn't output a value for negative \( x \).
- As \( x \) increases, \( f(x) \) also increases, creating a curve that rises to the right.
- The curve's slope decreases as \( x \) becomes larger, meaning it flattens out but never truly becomes horizontal.
Vertical Stretch
When we discuss a vertical stretch, we focus on changes in the y-values of a function's graph. The expression \( 2\sqrt{x} \) implies that each y-value of the basic square root function \( \sqrt{x} \) is now doubled. Here's what a vertical stretch involves:
- All points on the graph are moved further away from the x-axis. So, if a point on \( f(x) = \sqrt{x} \) was \( (a, b) \), in \( 2\sqrt{x} \) it becomes \( (a, 2b) \).
- This makes the graph appear stretched vertically, making it steeper than the parent curve.
- The overall shape of the curve remains the same; however, its rate of increase is exaggerated.
Horizontal Shift
Horizontal shifts cause the graph of a function to move left or right. In the function \( g(x) = 2\sqrt{x+1} \), the \( +1 \) inside the square root indicates a horizontal shift. Here is how it works:
- The addition of \(+1\) causes the entire graph to shift one unit to the left. This is because you must subtract 1 from \( x \) to 'compensate', which mirrors the graph relative to the y-axis.
- Every point on the basic graph \( \sqrt{x} \) shifts; so a point originally at \( (a, b) \) will move to \( (a-1, b) \).
- The shape of the graph remains unchanged, but its position on the x-axis adjusts.
Other exercises in this chapter
Problem 19
In Exercises \(9-20,\) determine whether each equation defines \(y\) as a function of \(x .\) $$x+y^{3}=8$$
View solution Problem 19
Find the midpoint of each line segment with the given endpoints. $$(6,8) \text { and }(2,4)$$
View solution Problem 20
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(=-1,\) passing through \(\left(-4,-\frac{1}{4}
View solution Problem 20
Find: a. \((f \circ g)(x)\) b. \(\left(g^{\circ} f\right)(x)\) c. \((f \circ g)(2)\) $$f(x)=5 x+2, g(x)=3 x-4$$
View solution