Problem 2
Question
Solve each equation for \(y\). $$\frac{y+1}{x-9}=\frac{3}{4}$$
Step-by-Step Solution
Verified Answer
y = \frac{3x - 31}{4}
1Step 1: Cross Multiply
To eliminate the fractions, cross-multiply the equation. Multiply the numerator of the left fraction by the denominator of the right fraction, and the numerator of the right fraction by the denominator of the left fraction. This gives:display porn movies content:\[4(y+1) = 3(x-9)\]
2Step 2: Distribute
Distribute the 4 on the left side and the 3 on the right side:\[4y + 4 = 3x - 27\]
3Step 3: Isolate the y-Term
Subtract 4 from both sides of the equation to isolate the term with y:\[4y = 3x - 31\]
4Step 4: Solve for y
Divide both sides by 4 to solve for y:\[y = \frac{3x - 31}{4}\]
Key Concepts
cross-multiplicationdistributive propertyisolating variablesfraction manipulation
cross-multiplication
Cross-multiplication is a method used to eliminate fractions in an equation by multiplying across the equal sign. This technique helps to simplify the equation and make it easier to solve.
For the equation \(\frac{y+1}{x-9}=\frac{3}{4}\), we cross-multiply by multiplying the numerator of one fraction by the denominator of the other fraction:
\[4(y+1) = 3(x-9)\].
This results in an equation with no fractions, making it easier to proceed to the next steps. Cross-multiplication is particularly useful when dealing with proportions and fractional equations.
For the equation \(\frac{y+1}{x-9}=\frac{3}{4}\), we cross-multiply by multiplying the numerator of one fraction by the denominator of the other fraction:
\[4(y+1) = 3(x-9)\].
This results in an equation with no fractions, making it easier to proceed to the next steps. Cross-multiplication is particularly useful when dealing with proportions and fractional equations.
distributive property
The distributive property helps to multiply a single term across a sum or difference inside parentheses. It states that \(a(b + c) = ab + ac\).
In our problem, we apply the distributive property to both sides of the equation:
\[4(y+1) = 4y + 4\]
and
\[3(x-9) = 3x - 27\]
This step is crucial because it expands the terms, removing the parentheses and making it possible to combine like terms or isolate variables in later steps.
In our problem, we apply the distributive property to both sides of the equation:
\[4(y+1) = 4y + 4\]
and
\[3(x-9) = 3x - 27\]
This step is crucial because it expands the terms, removing the parentheses and making it possible to combine like terms or isolate variables in later steps.
isolating variables
Isolating a variable means getting it alone on one side of the equation. Here, we need to isolate \y\. Starting with the equation \4y + 4 = 3x - 27\, we need to remove the constant term from the left side:
Subtract 4 from both sides:
\[4y = 3x - 31\].
Now, \y\ is in a simpler form, only with a constant multiplied to it.
In equations, isolating the variable helps in finding the solution by making the variable's coefficient 1 through further manipulation or operations.
Subtract 4 from both sides:
\[4y = 3x - 31\].
Now, \y\ is in a simpler form, only with a constant multiplied to it.
In equations, isolating the variable helps in finding the solution by making the variable's coefficient 1 through further manipulation or operations.
fraction manipulation
Fraction manipulation involves performing operations to simplify or solve fractions. After isolating the variable \y\, our equation \[4y = 3x - 31\] needs one final step:
Divide both sides by 4 to solve for \y\:
\[y = \frac{3x - 31}{4}\].
This step ensures \y\ is alone and the equation is simplified. Fraction manipulation is key in solving equations involving fractions, ensuring all terms are correctly handled and simplified.
Divide both sides by 4 to solve for \y\:
\[y = \frac{3x - 31}{4}\].
This step ensures \y\ is alone and the equation is simplified. Fraction manipulation is key in solving equations involving fractions, ensuring all terms are correctly handled and simplified.
Other exercises in this chapter
Problem 1
Solve each equation for \(y\). $$\frac{y-5}{x+3}=-\frac{4}{3}$$
View solution Problem 2
Reading and Writing After reading this section, write out the answers to these questions. Use complete sentences. How can an equation involving rational express
View solution Problem 2
After reading this section, write out the answers to these questions. Use complete sentences. What is the domain of a rational expression?
View solution Problem 3
Solve each equation for \(y\). $$M=\frac{1}{y}$$
View solution