Problem 2
Question
Prove that the absolute value of a Riemann integrable function is Riemann integrable.
Step-by-Step Solution
Verified Answer
The absolute value of a Riemann integrable function is Riemann integrable.
1Step 1: Define Riemann Integrable Function
A function \( f \) is said to be Riemann integrable on an interval \([a, b]\) if for every \( \epsilon > 0 \), there exist partitions \( P \) of \( [a, b] \) such that the upper sum \( U(f, P) \) and the lower sum \( L(f, P) \) satisfy \( U(f, P) - L(f, P) < \epsilon \).
2Step 2: Understand Absolute Value Property
The absolute value of a function, \( |f| \), which is defined by \( |f(x)| = \max(f(x), -f(x)) \), retains the characteristic of the original function, but it is always non-negative.
3Step 3: Prove \(|f|\) is Bounded on Partition
Since \( f \) is Riemann integrable, \( f \) is bounded on \([a, b]\). Therefore, \(|f|\) is also bounded, as \( |f(x)| \leq M \) for some \( M > 0 \) and for all \( x \in [a, b] \).
4Step 4: Consider Partitions for Riemann Integrability of \(|f|\)
Let \( \epsilon > 0 \) be given. Since \( f \) is Riemann integrable, there exists a partition \( P \) such that \( U(f, P) - L(f, P) < \epsilon \). The same partition can be used to analyze \( |f| \).
5Step 5: Relate \( U(|f|, P) \) and \( L(|f|, P) \)
Since \( |f(x)| \leq M \) and \( |f(x)| \geq 0 \), calculate the upper and lower sums for \(|f|\) using the same partition \( P \) and note that \( U(|f|, P) - L(|f|, P) \leq U(f, P) - L(f, P) < \epsilon \).
6Step 6: Conclude \(|f|\) is Riemann Integrable
Given \( U(|f|, P) - L(|f|, P) < \epsilon \), we conclude that \(|f|\) is also Riemann integrable on \([a, b]\) since we can make the difference between the upper and lower sums for \(|f|\) as small as desired.
Key Concepts
Absolute Value FunctionUpper Sum and Lower SumBounded FunctionsPartitions in Integration
Absolute Value Function
The absolute value function, denoted as \(|x|\), transforms any real number to its non-negative counterpart. For a function \(f(x)\), the absolute value is expressed as \(|f(x)| = \max(f(x), -f(x))\). This ensures that the result is always zero or greater, regardless of the input value. This property makes the absolute value function very useful in calculus, particularly when working with Riemann integrals. The essence here is maintaining the nature of \(f(x)\) while ensuring all outputs are non-negative, thus simplifying the analysis when determining integrability.
Upper Sum and Lower Sum
To determine if a function is Riemann integrable, we use the concepts of upper and lower sums. These sums help measure the area under a curve, which is crucial for integration.
- The **upper sum** \(U(f, P)\) calculates an overestimate of this area. It's the sum of areas of rectangles that sit above the curve.
- The **lower sum** \(L(f, P)\) provides an underestimate. It's the sum of areas of rectangles under the curve.
Bounded Functions
A function is bounded on an interval if it can be confined within some limits, not going to infinity. For Riemann integrable functions, being bounded is a key property. It means there are numbers \(m\) and \(M\) such that \(m \leq f(x) \leq M\) for all \(x\) in a certain interval.
This boundedness criterion is essential in proving integrability, ensuring that the function does not have any unmanageable spikes or dips that could make integration impossible. When discussing the absolute value, the bounded nature of \(f\) guarantees that \(|f|\) is also confined within a specific range, hence itself being bounded.
This boundedness criterion is essential in proving integrability, ensuring that the function does not have any unmanageable spikes or dips that could make integration impossible. When discussing the absolute value, the bounded nature of \(f\) guarantees that \(|f|\) is also confined within a specific range, hence itself being bounded.
Partitions in Integration
Partitions divide the interval into smaller sub-intervals, essential for calculating upper and lower sums.
A partition \(P\) of an interval \([a, b]\) is a finite sequence of numbers \(a = x_0 < x_1 < ... < x_n = b\). These partitions help refine the area approximation under a curve.
The choice of partition affects how precisely the upper and lower sums approximate the integral of the function.
By choosing sufficiently small sub-intervals in \(P\), the difference between \(U(f, P)\) and \(L(f, P)\) can be minimized to be less than any allocated \(\epsilon\), demonstrating the function's integrability. Thus, partitions are a crucial tool in the process of showing a function is Riemann integrable.
A partition \(P\) of an interval \([a, b]\) is a finite sequence of numbers \(a = x_0 < x_1 < ... < x_n = b\). These partitions help refine the area approximation under a curve.
The choice of partition affects how precisely the upper and lower sums approximate the integral of the function.
By choosing sufficiently small sub-intervals in \(P\), the difference between \(U(f, P)\) and \(L(f, P)\) can be minimized to be less than any allocated \(\epsilon\), demonstrating the function's integrability. Thus, partitions are a crucial tool in the process of showing a function is Riemann integrable.
Other exercises in this chapter
Problem 1
Show that the continuous function \(f(x)=1 / x\) on the open interval \((0,1)\) is not regulated, i.e., it cannot be uniformly approximated by step functions.
View solution Problem 1
Prove that the collection of all step functions on a closed interval \([a, b]\) is a vector space of functions which contains the constant functions.
View solution Problem 2
Give an example of a bounded continuous function on the open interval \((0,1)\) which is not regulated.
View solution Problem 2
Prove that if \(x_{0}=a
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