Problem 1
Question
Prove that the collection of all step functions on a closed interval \([a, b]\) is a vector space of functions which contains the constant functions.
Step-by-Step Solution
Verified Answer
The collection of all step functions on \([a, b]\) is a vector space because they satisfy vector space axioms and include constant functions.
1Step 1: Define a Step Function
A step function on a closed interval \([a, b]\) is a function that can be written in the form \( f(x) = c_i \) for \( x \in I_i \), where \( I_i \) are subintervals of \([a, b]\) and \( c_i \) are constants. The main feature of step functions is that they are constant on each subinterval.
2Step 2: Verify Vector Addition
Consider two step functions \( f \) and \( g \) on \([a, b]\), where \( f(x) = c_i \) and \( g(x) = d_i \) on the same subdivision of \([a, b]\). The sum \((f+g)(x) = c_i + d_i\) is also a step function on the same intervals, thus satisfying the closure property of vector addition.
3Step 3: Verify Scalar Multiplication
For a scalar \( k \) and a step function \( f(x) = c_i \) on \([a, b]\), the scalar multiplication \( (kf)(x) = k \cdot c_i \) results in another step function. This proves that step functions are closed under scalar multiplication.
4Step 4: Check Zero Function Existence
The zero function \( f(x) = 0 \) for all \( x \in [a, b] \) is a step function where each \( c_i = 0 \). This shows that the zero vector exists within the set of step functions.
5Step 5: Confirm Existence of Additive Inverses
For any step function \( f(x) = c_i \), the function \( -f(x) = -c_i \) is also a step function. This ensures that for every element, an additive inverse exists.
6Step 6: Address Constant Functions
Constant functions can be written as step functions where each subinterval is the whole interval \([a,b]\) with the same constant value \( c \). Thus, constant functions are simply a special case of step functions.
Key Concepts
Step FunctionScalar MultiplicationConstant Functions
Step Function
A step function is a type of mathematical function characterized by its piecewise constant nature. Imagine a staircase; that's similar to what a step function looks like graphically. It takes constant values on specific subintervals of its domain.
For example, consider a closed interval \( [a, b] \) on the real line. A step function \( f(x) \) on this interval can be expressed as \( f(x) = c_i \) for \( x \) in some subinterval \( I_i \). Each \( c_i \) is a constant, and \( I_i \) are disjoint subintervals that together cover the entire interval \( [a, b] \).
For example, consider a closed interval \( [a, b] \) on the real line. A step function \( f(x) \) on this interval can be expressed as \( f(x) = c_i \) for \( x \) in some subinterval \( I_i \). Each \( c_i \) is a constant, and \( I_i \) are disjoint subintervals that together cover the entire interval \( [a, b] \).
- **Characteristics of Step Functions**: They are simple, defined by a finite number of constant pieces.
- **Graphical Representation**: Their graph resembles a series of horizontal steps.
- **Common Examples**: A step function can represent sudden changes, such as tax brackets or fare zones.
Scalar Multiplication
Scalar multiplication is a fundamental operation in vector spaces; it involves multiplying a scalar (a constant) with a vector or a function. In the context of step functions, this concept is simple yet powerful.
Given a step function \( f(x) = c_i \) on some interval \( [a, b] \), if a scalar \( k \) is multiplied by this function, the result is another step function defined as \( (kf)(x) = k \cdot c_i \). This operation scales the function without altering its fundamental step-like structure.
Given a step function \( f(x) = c_i \) on some interval \( [a, b] \), if a scalar \( k \) is multiplied by this function, the result is another step function defined as \( (kf)(x) = k \cdot c_i \). This operation scales the function without altering its fundamental step-like structure.
- **Preservation of Structure**: Scalar multiplication does not change the fact that the function is a step function; it merely changes the height of each 'step'.
- **Closure Property**: The result of scalar multiplication remains within the set of step functions, ensuring the set is closed under this operation.
Constant Functions
Constant functions maintain the same value throughout their entire domain. They are a special and very simple kind of function observed in various mathematical applications.
In the world of vector spaces, especially within the realm of step functions, constant functions appear naturally. For any closed interval \( [a, b] \), a constant function takes the same value \( c \) for every point within this interval.
In the world of vector spaces, especially within the realm of step functions, constant functions appear naturally. For any closed interval \( [a, b] \), a constant function takes the same value \( c \) for every point within this interval.
- **Relation to Step Functions**: They can be seen as step functions with only one subdivision, the entire interval \( [a, b] \), having a single constant step.
- **Role in Vector Spaces**: Constant functions satisfy all properties that define a vector space. They can be combined using vector addition and scalar multiplication while retaining their constant nature.
- **Utility in Modeling**: Constant functions are often used in modeling scenarios with uniform conditions, like fixed fees or baseline temperatures.
Other exercises in this chapter
Problem 1
Prove that if \(f:[a, b] \rightarrow \mathbb{R}\) is a regulated function and \(F:[a, b] \rightarrow \mathbb{R}\) is defined by \(F(x)=\int_{a}^{x} f(t) d t\),
View solution Problem 1
Show that the continuous function \(f(x)=1 / x\) on the open interval \((0,1)\) is not regulated, i.e., it cannot be uniformly approximated by step functions.
View solution Problem 2
Prove that the absolute value of a Riemann integrable function is Riemann integrable.
View solution Problem 2
Give an example of a bounded continuous function on the open interval \((0,1)\) which is not regulated.
View solution