Problem 2

Question

In Exercises \(1-6,\) find the domain and range of each function. $$ f(x)=1-\sqrt{x} $$

Step-by-Step Solution

Verified
Answer
Domain: \([0, \infty)\), Range: \((- fty, 1]\).
1Step 1: Identify the Function Type
The function provided is \( f(x) = 1 - \sqrt{x} \). This is a square root function subtracted from 1.
2Step 2: Determine the Domain
The square root function \( \sqrt{x} \) requires that \( x \geq 0 \) since the square root of a negative number is undefined in the set of real numbers. Therefore, the domain of \( f(x) \) is \( x \geq 0 \). In interval notation, this is \([0, \infty)\).
3Step 3: Find the Range of the Root Function
The \( \sqrt{x} \) function has a range of \([0, \infty)\). This means for any \( x \geq 0 \), the value of \( \sqrt{x} \) ranges from 0 to \( \infty\).
4Step 4: Determine the Range of the Original Function
Since \( f(x) = 1 - \sqrt{x} \), we take the range of \( \sqrt{x} \), which is \([0, \infty)\), and apply the transformation: subtract each value from 1. This transforms the minimum value (0) into 1-0 = 1 and pushes the maximum down towards \(-\infty\) as \( \sqrt{x} \) increases. Thus, the range of \( f(x) \) is \((-fty , 1]\).
5Step 5: Conclusion on Domain and Range
The domain of the function \( f(x) = 1 - \sqrt{x} \) is \([0, \infty)\), and the range is \((-fty , 1]\).

Key Concepts

Square Root FunctionsFunction TransformationReal Numbers
Square Root Functions
The concept of square root functions is essential in understanding how particular functions behave. A square root function usually takes the form of \( f(x) = \sqrt{x} \). This type of function grows gradually as \( x \) increases. It is important to note that square root functions are defined only for non-negative numbers.
  • When the argument of the square root, \( x \), is less than zero, the function becomes undefined in the realm of real numbers.
  • The domain of a standard square root function is \( x \geq 0 \), represented in interval notation as \([0, \infty)\).
  • The range of \( \sqrt{x} \) covers non-negative real numbers, which means it is also \([0, \infty)\).
Understanding these domain and range limitations helps us grasp why the function \( f(x) = 1 - \sqrt{x} \) changes in its domain and range as transformations are applied.
Function Transformation
Function transformations involve shifting, stretching, or compressing a function in various ways. In the function \( f(x) = 1 - \sqrt{x} \), a simple transformation is applied: the square root function is subtracted from 1. This alteration affects both its appearance and range.
  • Transformation by subtraction: The whole graph of the square root function is shifted downward by subtracting each \( y \)-value from a constant (1 in this case).
  • Shifting effects: Because of this shift, the maximum value at the function's starting point (when \( x = 0 \)) changes from 0 to 1.
  • As \( \sqrt{x} \) increases, the values become negative, moving towards \(-\infty\).
This horizontal stretching or shifting allows us to determine a new range for \( f(x) = 1 - \sqrt{x} \), resulting in \((-\infty, 1]\). Understanding how these transformations work can give insight into manipulating functions for desired properties.
Real Numbers
Real numbers are a cornerstone of understanding functions like square root functions and their transformations. They form the extended set of values where many mathematical operations take place.
  • Real numbers include all the rational numbers, such as integers and fractions, as well as all the irrational numbers, which cannot be expressed as fractions, such as \( \sqrt{2} \).
  • In the context of square roots, real numbers determine the existence of square roots. For instance, \( \sqrt{9} = 3 \) is valid because 9 is a non-negative real number.
  • In functions, we often restrict operations to real numbers to avoid undefined expressions, such as trying to find \( \sqrt{-4} \), which isn't possible within the real number system.
Real numbers offer a framework to work with domains and ranges effectively, ensuring that functions behave as expected. It is by staying within real numbers that we confirm the domain of \( f(x) = 1 - \sqrt{x} \) as all non-negative numbers, \([0, \infty)\), to avoid undefined results.