Problem 2
Question
In Exercises \(1-4\), write a formula for \(y\) in terms of \(x\) if \(y\) satisfies the given conditions. Proportional to the cube of \(x\), with constant of proportionality -0.35 .
Step-by-Step Solution
Verified Answer
Question: Given that y is proportional to the cube of x with a constant of proportionality of -0.35, find a formula for y in terms of x.
Answer: The formula for y in terms of x is y = -0.35x^3, where y is proportional to the cube of x with a constant of proportionality of -0.35.
1Step 1: Determine the proportionality relationship
Since \(y\) is proportional to the cube of \(x\), we can represent the proportionality relationship as \(y \propto x^3\).
Step 2:
Introduce the constant of proportionality
2Step 2: Include the constant of proportionality in the relationship
To introduce the constant of proportionality, we will replace the proportionality symbol "\(\displaystyle\propto\)" with an equal sign, and multiply the \(x^3\) term by the constant of proportionality. The constant of proportionality is given as -0.35. So, the equation becomes: \[y = -0.35x^3\]
Step 3:
Write the final formula
3Step 3: Present the final formula for y in terms of x
The final formula for \(y\) in terms of \(x\) is \[y = -0.35x^3\], where \(y\) is proportional to the cube of \(x\) with a constant of proportionality of -0.35.
Key Concepts
Cubic FunctionsConstant of ProportionalityAlgebraic Formulas
Cubic Functions
A cubic function is a type of polynomial function where the highest degree is 3. In simpler terms, the variable \(x\) is raised to the power of three, so the basic form of a cubic function is \(y = ax^3 + bx^2 + cx + d\). Understanding cubic functions is essential for many areas of mathematics and physics because they can model various real-world situations, like the volume of a cube or the behavior of certain types of waves.
When dealing with cubic functions, you might notice their characteristic graph shape, a curve that typically has either two turning points or none, which makes it unique compared to quadratic functions that those with parabolas. The steep parts of the curve are due to the cube power, which increases faster than linear or quadratic relationships.
When dealing with cubic functions, you might notice their characteristic graph shape, a curve that typically has either two turning points or none, which makes it unique compared to quadratic functions that those with parabolas. The steep parts of the curve are due to the cube power, which increases faster than linear or quadratic relationships.
- Key Element: The coefficient of \(x^3\) determines how steep or wide the cubic curve is.
- Behavior: Depending on the sign of the leading coefficient, the graph could slope upward or downward.
- Roots: A cubic function can have up to three real roots, which are points where the curve crosses the \(x\)-axis.
Constant of Proportionality
The constant of proportionality is a number that relates two variables that are proportional to each other. When one variable \(y\) changes in a consistent way with another variable \(x\), they are said to be directly proportional if \(y = kx\) for some constant \(k\), which is the constant of proportionality.
In our cubic function case, the constant of proportionality is \(-0.35\). This tells us that every time \(x\) changes, \(y\) will change by \(-0.35\) times the cube of \(x\).
In our cubic function case, the constant of proportionality is \(-0.35\). This tells us that every time \(x\) changes, \(y\) will change by \(-0.35\) times the cube of \(x\).
- Determining Factor: The constant's sign indicates direction—negative implies inverse relationship.
- Scale: It reflects the scale factor, determining how large or small \(y\) will be compared to \(x^3\).
- Units: If needed, it adjusts units of measurement between \(y\) and \(x^3\).
Algebraic Formulas
Algebraic formulas are equations that express relationships between different variables using algebraic expressions. These formulas serve as shortcuts to solving problems by giving us a structured way to manipulate numbers and capture relationships.
In the exercise we looked at, we derived the algebraic formula \(y = -0.35x^3\). This formula helps us quickly compute \(y\), the dependent variable, based on changes in \(x\), the independent variable.
In the exercise we looked at, we derived the algebraic formula \(y = -0.35x^3\). This formula helps us quickly compute \(y\), the dependent variable, based on changes in \(x\), the independent variable.
- Simplification: Algebraic formulas can simplify complex real-world problems into solvable mathematical models.
- Prediction: They allow us to predict outcomes by plugging in variable values.
- Flexibility: Formulas can be adapted to different situations by changing constants and other parameters.
Other exercises in this chapter
Problem 1
In Exercises \(1-21,\) solve the equation for the variable. $$ x^{3}=50 $$
View solution Problem 1
In Exercises \(1-5,\) identify the exponent and the coefficient for each power function. The area of a square of side \(x\) is \(A=x^{2}\).
View solution Problem 2
In Exercises \(1-21,\) solve the equation for the variable. $$ 2 x^{2}=8.6 $$
View solution Problem 2
Are the functions power functions? $$ y=12 \cdot 14^{x} $$
View solution