Problem 1
Question
In Exercises \(1-21,\) solve the equation for the variable. $$ x^{3}=50 $$
Step-by-Step Solution
Verified Answer
Answer: The value of x in the equation \(x^3 = 50\) is approximately 3.684.
1Step 1: Understand the equation
The given equation is \(x^3 = 50\). We need to solve for x by finding the value that, when cubed, results in 50.
2Step 2: Find the cube root
To solve for x, we need to find the cube root of 50. The cube root of a number is the value that, when multiplied by itself three times, gives that number. We can represent the cube root using the "∛" symbol or as a fractional exponent. Thus, we have two equivalent expressions for calculating the cube root of 50:
$$
x = \sqrt[3]{50}
$$
or
$$
x = 50^{\frac{1}{3}}
$$
3Step 3: Calculate the cube root
Use a calculator to find the cube root of 50:
$$
x = \sqrt[3]{50} \approx 3.684
$$
or
$$
x = 50^{\frac{1}{3}} \approx 3.684
$$
4Step 4: Write the final solution
Since the cube root of 50 cannot be simplified further, the final solution is:
$$
x \approx 3.684
$$
Key Concepts
Cube RootExponentsAlgebraic Solutions
Cube Root
The cube root of a number is essential when you want to undo a cubed number. Think of it like finding the opposite of cubing a number. If you take any number and multiply it by itself twice (meaning three times in total), you will get a bigger number. However, if you start with the bigger number and want to get back to your original number, you would take the cube root.
For instance:
For instance:
- The cube root of 27 is 3 because 3 × 3 × 3 = 27.
- You can express the cube root using the symbol ∛. For our example, it's written as ∛27 = 3.
Exponents
Exponents are used to denote the number of times a number is multiplied by itself. In the context of our equation, we start with the expression \(x^3 = 50\). The "3" here is the exponent, indicating that "x" is being multiplied by itself twice more (a total of three times).
Exponents are powerful tools:
In our exercise, moving from \(x^3 = 50\) to finding \(x = 50^{\frac{1}{3}}\) showcases changing from a whole number exponent to a fractional one to help us solve the equation.
Exponents are powerful tools:
- They simplify expressions that would otherwise require lengthy multiplication.
- You can use fractional exponents to express roots; for instance, \(x^{\frac{1}{3}}\) represents the cube root of x.
In our exercise, moving from \(x^3 = 50\) to finding \(x = 50^{\frac{1}{3}}\) showcases changing from a whole number exponent to a fractional one to help us solve the equation.
Algebraic Solutions
Algebraic solutions involve manipulating an equation to find the value of a variable. Solving equations allows us to find unknowns using logical operations and principles. In the case of \(x^3 = 50\), we aim to isolate "x" and find its value. Here's how the process unfolds:
- The task: Find "x" such that when cubed, it equals 50.
- Step: Recognize that taking the cube root will isolate x. Thus, x is expressed as \(\sqrt[3]{50}\) or \(50^{\frac{1}{3}}\).
- Outcome: Use a calculator for precision, resulting in \(x \approx 3.684\).
Other exercises in this chapter
Problem 1
In Exercises \(1-4\), write a formula for \(y\) in terms of \(x\) if \(y\) satisfies the given conditions. Proportional to the \(5^{\text {th }}\) power of \(x,
View solution Problem 1
In Exercises \(1-5,\) identify the exponent and the coefficient for each power function. The area of a square of side \(x\) is \(A=x^{2}\).
View solution Problem 2
In Exercises \(1-4\), write a formula for \(y\) in terms of \(x\) if \(y\) satisfies the given conditions. Proportional to the cube of \(x\), with constant of p
View solution Problem 2
In Exercises \(1-21,\) solve the equation for the variable. $$ 2 x^{2}=8.6 $$
View solution