Problem 192
Question
The bond order in \(\mathrm{NO}\) is \(2.5\) while that in \(\mathrm{NO}^{+}\)is 3 . Which of the following statements is true for these two species? [2004] (a) bond length in \(\mathrm{NO}^{+}\)is greater than in NO (b) bond length in \(\mathrm{NO}\) is greater than in \(\mathrm{NO}^{+}\) (c) bond length in \(\mathrm{NO}^{+}\)is equal than in NO (d) bond length is unpredictable
Step-by-Step Solution
Verified Answer
(b) bond length in NO is greater than in NO⁺.
1Step 1: Understanding Bond Order
The bond order is a measure of the number of chemical bonds between a pair of atoms. It is calculated as the difference between the number of bonding electrons and antibonding electrons, divided by two. Generally, a higher bond order indicates a stronger, shorter bond.
2Step 2: Comparing Bond Orders
We're given that the bond order for NO is 2.5 and for NO⁺ it is 3. Higher bond order corresponds to a shorter bond length because more bonding interaction leads to stronger attraction between the two atoms.
3Step 3: Evaluating Bond Lengths
Since the bond order for NO⁺ is greater than that of NO (3 > 2.5), the bond in NO⁺ is stronger and thus shorter than in NO. Consequently, the bond length in NO is greater than that in NO⁺.
4Step 4: Determining the Correct Statement
The correct statement must reflect that the bond with the greater bond order (NO⁺) has a shorter bond length. Therefore, the correct option is (b) bond length in NO is greater than in NO⁺.
Key Concepts
Bond LengthChemical BondsMolecular Structure
Bond Length
In chemistry, bond length is the average distance between the nuclei of two bonded atoms. This measurement is crucial because it provides information about the strength and type of a chemical bond. Generally, shorter bond lengths correspond to stronger bonds. This is because the atoms are held together more tightly.
Several factors affect bond length, including:
Several factors affect bond length, including:
- Bond order: Higher bond order means more shared electrons between atoms, resulting in shorter bonds.
- Atomic size: Larger atoms will generally form longer bonds.
- Electronegativity: Differences in electronegativity can affect bond length, with more polar bonds often being shorter.
Chemical Bonds
Chemical bonds are the attractive forces holding atoms together in molecules and compounds. They form due to interactions between the electrons of atoms.
There are three primary types of chemical bonds:
There are three primary types of chemical bonds:
- Ionic bonds: Formed when electrons are transferred from one atom to another, creating ions that attract each other.
- Covalent bonds: Occur when two atoms share one or more pairs of electrons.
- Metallic bonds: Consist of a lattice of cations surrounded by a 'sea' of delocalized electrons, typical in metals.
Molecular Structure
Molecular structure defines the arrangement of atoms within a molecule. This structure dictates not only the shape and size of the molecule but also its chemical reactivity and properties.
Several factors influence molecular structure:
Several factors influence molecular structure:
- Bond angles: The angles between adjacent bonds influence the molecule's shape.
- Bond lengths: Shorter bonds lead to more compact molecular structures.
- Hybridization: The mixing of atomic orbitals influences molecular geometry.
Other exercises in this chapter
Problem 190
The pair of species having identical shapes for molecules of both species is (a) \(\mathrm{CF}_{4}, \mathrm{SF}_{4}\) (b) \(\mathrm{XeF}_{2}, \mathrm{CO}_{2}\)
View solution Problem 191
The correct order of bond angles (smallest first) in \(\mathrm{H}_{2} \mathrm{~S}, \mathrm{NH}_{3}, \mathrm{BF}_{3}\) and \(\mathrm{SiH}_{4}\) is [2004] (a) \(\
View solution Problem 193
Which of the following has the regular tetrahedral structure? (a) \(\mathrm{BF}_{4}{\underline{\phantom{xx}}}^{-}\) (b) \(\mathrm{SF}_{4}\) (c) \(\left[\mathrm{Ni}(\mathrm{CN})_{a}\ri
View solution Problem 194
The maximum number of \(90^{\circ}\) angles between bond pair-bond pair of electrons is observed in [2004] (a) \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) hybridization
View solution