Problem 191
Question
The correct order of bond angles (smallest first) in \(\mathrm{H}_{2} \mathrm{~S}, \mathrm{NH}_{3}, \mathrm{BF}_{3}\) and \(\mathrm{SiH}_{4}\) is [2004] (a) \(\mathrm{H}_{2} \mathrm{~S}<\mathrm{SiH}_{4}<\mathrm{NH}_{3}<\mathrm{BF}_{3}\) (b) \(\mathrm{NH}_{3}<\mathrm{H}_{2} \mathrm{~S}<\mathrm{SiH}_{4}<\mathrm{BF}_{3}\) (c) \(\mathrm{H}_{2} \mathrm{~S}<\mathrm{NH}_{3}<\mathrm{SiH}_{4}<\mathrm{BF}_{3}\) (d) \(\mathrm{H}_{2} \mathrm{~S}<\mathrm{NH}_{3}<\mathrm{BF}_{3}<\mathrm{SiH}_{4}\)
Step-by-Step Solution
Verified Answer
(c) \(\mathrm{H}_2\mathrm{S}<\mathrm{NH}_3<\mathrm{SiH}_4<\mathrm{BF}_3\)
1Step 1: Determine bond angles for H2S
Hydrogen sulfide (\(\mathrm{H}_2\mathrm{S}\)) has a bent shape due to the presence of two lone pairs on the sulfur atom. This results in a bond angle that is typically around \(92.1^\circ\).
2Step 2: Determine bond angles for NH3
Ammonia (\(\mathrm{NH}_3\)) has a trigonal pyramidal shape with one lone pair on the nitrogen atom, leading to a bond angle of approximately \(107.3^\circ\).
3Step 3: Determine bond angles for BF3
Boron trifluoride (\(\mathrm{BF}_3\)) is trigonal planar with bond angles of approximately \(120^\circ\) due to the absence of lone pairs on the boron atom.
4Step 4: Determine bond angles for SiH4
Silane (\(\mathrm{SiH}_4\)) is tetrahedral with a standard bond angle of \(109.5^\circ\) because there are no lone pairs.
5Step 5: Order bond angles from smallest to largest
Based on the bond angles: \(\mathrm{H}_2\mathrm{S}\approx 92.1^\circ\), \(\mathrm{NH}_3\approx 107.3^\circ\), \(\mathrm{SiH}_4\approx 109.5^\circ\), and \(\mathrm{BF}_3\approx 120^\circ\), arrange them in ascending order: \(\mathrm{H}_2\mathrm{S} < \mathrm{NH}_3 < \mathrm{SiH}_4 < \mathrm{BF}_3\).
Key Concepts
Molecular GeometryVSEPR TheoryBent ShapeTrigonal PyramidalTrigonal PlanarTetrahedral
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. This arrangement significantly affects the molecule's properties, including bond angles, reactivity, phase of matter, color, magnetism, and biological activity. Understanding molecular geometry is crucial because it forms the foundation upon which much of chemistry is built.
- Linear Geometry
- Trigonal Planar
- Tetrahedral
- Bent Shape
- Trigonal Pyramidal
VSEPR Theory
The VSEPR (Valence Shell Electron Pair Repulsion) Theory helps us understand and predict the shapes of molecules. The main idea behind VSEPR Theory is that electron pairs around a central atom stay as far apart as possible to minimize repulsion. This concept is key in determining the molecular geometry of a molecule.
- Electron pairs include bonding pairs and lone pairs.
- Lone pairs repel more strongly than bonding pairs.
- The number of domains of electron density (either a pair or a single unpaired electron) around the central atom dictates the shape.
Bent Shape
A bent shape occurs in molecules where the central atom has two bonded atoms and at least one lone pair of electrons. The classic molecules with this geometry are water (
H2O
) and hydrogen sulfide (
H2S
). The bent shape is due to the repulsive forces exerted by the lone pairs that cause the bonded atoms to be pushed together, creating a smaller bond angle compared to a linear shape.
Properties of Bent Shape:
- The typical bond angle is less than 120° and varies based on the number and strength of the repulsions.
- The shape is non-linear due to the lone pairs on the central atom.
- Lone pairs are located in positions that allow them to repel the bonded atoms towards each other.
Trigonal Pyramidal
The trigonal pyramidal shape arises when there is one lone pair on the central atom with three bonded atoms. This results in a pyramidal structure with the lone pair creating a stronger repulsion, slightly pushing the bonded atoms closer together. Ammonia (
NH3
) is the classic example of a molecule with a trigonal pyramidal geometry.
Characteristics of Trigonal Pyramidal:
- The bond angle is slightly less than the tetrahedral angle, often around 107° to 109.5°.
- The lone pair affects the geometry by exerting more repulsion on the bonding pairs.
- The shape gives the appearance of a three-sided pyramid.
Trigonal Planar
Trigonal planar geometry is found in molecules where the central atom is connected to three peripheral atoms with no lone pairs present. This geometry results in a flat, triangular shape where all bond angles are equal. Boron trifluoride (
BF3
) is a typical example of a trigonal planar molecule.
Characteristics of Trigonal Planar:
- The bond angles are all 120°.
- There are no lone pairs on the central atom to distort the angle.
- The molecule lies entirely within a single plane.
Tetrahedral
A tetrahedral geometry occurs when a central atom is surrounded by four bonded atoms and no lone pairs. This arrangement allows for equal spacing in three-dimensional space, reducing repulsion and resulting in symmetric distribution. Silane (
SiH4
) is an example of a molecule with a tetrahedral shape.
Features of Tetrahedral Geometry:
- The bond angles in a tetrahedral molecule are typically 109.5°.
- This arrangement achieves a symmetric, balanced shape with minimal repulsion.
- It is the most common geometry for carbon atoms in organic molecules.
Other exercises in this chapter
Problem 189
Which one of the following pairs of molecules will have permanent dipole moments for both members? [2003] (a) \(\mathrm{SiF}_{4}\) and \(\mathrm{NO}_{2}\) (b) \
View solution Problem 190
The pair of species having identical shapes for molecules of both species is (a) \(\mathrm{CF}_{4}, \mathrm{SF}_{4}\) (b) \(\mathrm{XeF}_{2}, \mathrm{CO}_{2}\)
View solution Problem 192
The bond order in \(\mathrm{NO}\) is \(2.5\) while that in \(\mathrm{NO}^{+}\)is 3 . Which of the following statements is true for these two species? [2004] (a)
View solution Problem 193
Which of the following has the regular tetrahedral structure? (a) \(\mathrm{BF}_{4}{\underline{\phantom{xx}}}^{-}\) (b) \(\mathrm{SF}_{4}\) (c) \(\left[\mathrm{Ni}(\mathrm{CN})_{a}\ri
View solution