Problem 19
Question
Write a mathematical model for the number problem, and solve the problem. One positive number is five times another positive number. The difference between the two numbers is 148 . Find the numbers.
Step-by-Step Solution
Verified Answer
The two numbers are 185 and 37.
1Step 1: Define Variables
Let \( X \) be the first number and \( Y \) be the second positive number.
2Step 2: Build Equations from the Problem
According to the problem, you can set up two equations as follows:\n\nEquation 1: One positive number is five times another positive number. This can be written as: \( X = 5Y \).\n\nEquation 2: The difference between the two numbers is 148. This can be written as: \( X - Y = 148 \).
3Step 3: Substitution
Substitute \( X \) from Equation 1 into Equation 2: \( 5Y - Y = 148 \)
4Step 4: Solve for Y
Combine like terms to find the value of Y: \( 4Y = 148 \). Then divide by 4: \( Y = 37 \).
5Step 5: Solve for X
Substitute the value of \( Y \) into the Equation 1: \( X = 5*37 \). So, \( X = 185 \).
Key Concepts
Defining Variables in AlgebraSetting Up EquationsSubstitution Method in Algebra
Defining Variables in Algebra
To tackle any algebraic word problem effectively, one must first translate the given information into mathematical terms. That involves the crucial step of defining variables. Variables are symbols, usually letters like X or Y, that represent unknown values. It's akin to using placeholders for pieces of the puzzle not yet known.
In the context of our number problem, we started by naming the first positive number as X and the second as Y. By doing so, we created a reference point that allows us to translate the descriptive language of the problem ('one positive number is five times another positive number' and 'the difference between the two numbers is 148') into mathematical expressions.
In the context of our number problem, we started by naming the first positive number as X and the second as Y. By doing so, we created a reference point that allows us to translate the descriptive language of the problem ('one positive number is five times another positive number' and 'the difference between the two numbers is 148') into mathematical expressions.
Setting Up Equations
Once variables are established, the next foundational skill is setting up equations. An equation is a statement that asserts the equality of two expressions. Developing an equation from a word problem often involves identifying how these expressions relate to the real-world quantities in the problem.
For our number problem, two relationships were described—multiplication and subtraction. The first is expressed by the equation \( X = 5Y \) or equal to five times the second number. The second relationship reflects the difference between these numbers, \( X - Y = 148 \) translates the word 'difference' into an algebraic subtraction operation.
For our number problem, two relationships were described—multiplication and subtraction. The first is expressed by the equation \( X = 5Y \) or equal to five times the second number. The second relationship reflects the difference between these numbers, \( X - Y = 148 \) translates the word 'difference' into an algebraic subtraction operation.
Substitution Method in Algebra
The substitution method is one of the essential techniques for solving systems of equations in algebra. It's particularly useful when you have one equation that can be solved explicitly for one variable in terms of the others.
In the exercise, we first expressed X in terms of Y (\( X = 5Y \) and then replaced X with \( 5Y \) in the other equation (\( X - Y = 148 \). This substitution gave us a single variable equation \( 5Y - Y = 148 \) that we could solve straightforwardly. By isolating Y, we eventually discovered that the second number is 37, leading us to find X (the first number) by substituting back into \( X = 5Y \) and finding it to be 185.
In the exercise, we first expressed X in terms of Y (\( X = 5Y \) and then replaced X with \( 5Y \) in the other equation (\( X - Y = 148 \). This substitution gave us a single variable equation \( 5Y - Y = 148 \) that we could solve straightforwardly. By isolating Y, we eventually discovered that the second number is 37, leading us to find X (the first number) by substituting back into \( X = 5Y \) and finding it to be 185.
Other exercises in this chapter
Problem 19
Use the Quadratic Formula to solve the quadratic equation. $$ 12 x-9 x^{2}=-3 $$
View solution Problem 19
Solve the quadratic equation by factoring. $$ x^{2}+4 x=12 $$
View solution Problem 19
Solve the equation and check your solution. (Some equations have no solution.) $$ 7-2 x=15 $$
View solution Problem 20
Solve the inequality. Then graph the solution set on the real number line. \(x^{2}-4 x-1>0\)
View solution