Problem 19
Question
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$x^{2}-18 x+80=0$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 10\) and \(x = 8\).
1Step 1: Identify the coefficients
Firstly, identify the coefficients from the quadratic equation given in the form \[ax^2 + bx + c = 0\] For the equation \(x^2 - 18x + 80 = 0\), the coefficients are: - \(a = 1\) - \(b = -18\) - \(c = 80\).
2Step 2: Apply the quadratic formula
The quadratic formula is \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] Substitute the values of \(a\), \(b\), and \(c\) into the formula: \[x = \frac{-(-18) \pm \sqrt{(-18)^2 - 4 \cdot 1 \cdot 80}}{2 \cdot 1}\] Simplify inside the square root first.
3Step 3: Calculate the discriminant
The discriminant \(b^2 - 4ac\) determines the nature of the roots.For the given equation:\[(-18)^2 - 4 \cdot 1 \cdot 80 = 324 - 320 = 4\]Since the discriminant is positive, there are two distinct real solutions.
4Step 4: Evaluate the roots
Now use the discriminant in the quadratic formula: \[x = \frac{18 \pm \sqrt{4}}{2}\] Since \(\sqrt{4} = 2\), substitute back into the formula to get: \[x = \frac{18 \pm 2}{2}\] Thus calculate the two possible values for \(x\).
5Step 5: Find the values of x
Calculate each value:1. \[x = \frac{18 + 2}{2} = \frac{20}{2} = 10\]2. \[x = \frac{18 - 2}{2} = \frac{16}{2} = 8\]The solutions to the equation are \(x = 10\) and \(x = 8\).
6Step 6: Verify using sum and product relationships
Check the solutions using the sum and product of roots:1. The sum of the roots \(10 + 8 = 18\) matches \(-b/a\), which is \(-(-18)/1 = 18\).2. The product of the roots \(10 \times 8 = 80\) matches \(c/a\), which is \(80/1 = 80\).Both checks confirm the solutions are correct.
Key Concepts
Quadratic FormulaDiscriminantSum and Product of Roots
Quadratic Formula
The quadratic formula is a powerful tool used to find the roots of a quadratic equation, which takes the general form \(ax^2 + bx + c = 0\). To solve for \(x\), you use the quadratic formula:
To apply this, start by identifying the coefficients \(a\), \(b\), and \(c\) from your quadratic equation. For example, in the equation \(x^2 - 18x + 80 = 0\), the coefficients are \(a = 1\), \(b = -18\), and \(c = 80\). Substituting these values into the formula allows you to solve for the roots by simplifying step-by-step.
Remember, the calculation involves two operations: addition and subtraction before different results are divided by \(2a\). So, always perform these steps carefully to ensure accuracy.
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
To apply this, start by identifying the coefficients \(a\), \(b\), and \(c\) from your quadratic equation. For example, in the equation \(x^2 - 18x + 80 = 0\), the coefficients are \(a = 1\), \(b = -18\), and \(c = 80\). Substituting these values into the formula allows you to solve for the roots by simplifying step-by-step.
Remember, the calculation involves two operations: addition and subtraction before different results are divided by \(2a\). So, always perform these steps carefully to ensure accuracy.
Discriminant
The discriminant is a key component of the quadratic formula, defined as the expression \(b^2 - 4ac\). It provides valuable information about the nature of the roots of a quadratic equation.
Understanding the discriminant not only helps predict the type of roots but also guides whether further simplifications will lead you to real, easy-to-handle numbers or require additional steps for complex solutions.
- If the discriminant is positive, you get two distinct real roots.
- If it's zero, there's exactly one real root (a repeated root).
- If the discriminant is negative, the roots are complex or imaginary.
Understanding the discriminant not only helps predict the type of roots but also guides whether further simplifications will lead you to real, easy-to-handle numbers or require additional steps for complex solutions.
Sum and Product of Roots
The sum and product of roots provide a simple verification tool for checking your solutions to a quadratic equation. According to Viète's formulas:
- The sum of the roots, \(\alpha + \beta\), should equal \(-\frac{b}{a}\).
- The product of the roots, \(\alpha \cdot \beta\), should equal \(\frac{c}{a}\).
- Sum of the roots is \(10 + 8 = 18\), which matches \(-\frac{-18}{1} = 18\).
- Product of the roots is \(10 \times 8 = 80\), which matches \(\frac{80}{1} = 80\).
Other exercises in this chapter
Problem 19
Solve each inequality and graph its solution set on a number line. $$\frac{-x+2}{x-1} \leq 0$$
View solution Problem 19
Solve each quadratic equation using the method that seems most appropriate to you. $$4 t^{2}+4 t-1=0$$
View solution Problem 19
Use the method of completing the square to solve each quadratic equation. $$y^{2}-10 y=1$$
View solution Problem 19
Solve each of the quadratic equations by factoring and applying the property, \(a b=0\) if and only if \(a=0\) or \(b=0\). If necessary, return to Chapter 3 and
View solution