Problem 19
Question
Solve each equation. Check the result. $$ 2 x+6(2 x+3)=-10 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = -2 \).
1Step 1: Expand the Equation
Start by distributing the 6 across the terms inside the parentheses. The equation is: \[ 2x + 6(2x + 3) = -10 \]After expanding, this becomes: \[ 2x + 12x + 18 = -10 \]
2Step 2: Combine Like Terms
Combine the terms that have \( x \) in them. We have \( 2x + 12x \), so:\[ 14x + 18 = -10 \]
3Step 3: Isolate the Variable
Subtract 18 from both sides to move the constant term to the right side of the equation:\[ 14x = -10 - 18 \]Simplifying gives:\[ 14x = -28 \]
4Step 4: Solve for x
Divide both sides by 14 to solve for \( x \):\[ x = \frac{-28}{14} \]This simplifies to:\[ x = -2 \]
5Step 5: Check Your Solution
Substitute \( x = -2 \) back into the original equation to verify the solution. The original equation is: \[ 2(-2) + 6(2(-2) + 3) = -10 \]Calculate inside the parentheses first:\[ 2(-2) + 6(-4 + 3) = -10 \]This becomes:\[ -4 + 6(-1) = -10 \]Finally, simplify:\[ -4 - 6 = -10 \]This is true, so the solution is verified.
Key Concepts
Distributive PropertyCombining Like TermsIsolation of VariablesSolution Verification
Distributive Property
The distributive property is a fundamental concept in algebra used to simplify expressions. It allows you to multiply a single term by each term inside parentheses in an expression. In our original equation:\[2x + 6(2x + 3) = -10\]we use the distributive property to expand the expression inside the parentheses. This means we multiply 6 by both \(2x\) and 3, which gives us:
- 6 times \(2x\) equals \(12x\)
- 6 times 3 equals 18
Combining Like Terms
Once we have expanded the equation using the distributive property, the next step is to simplify it by combining like terms. Like terms are terms that have the same variable component. In our equation, the like terms are those with the variable \(x\):\[2x + 12x + 18 = -10\]To combine the like terms \(2x\) and \(12x\), simply add their coefficients together:
- \(2x + 12x = 14x\)
Isolation of Variables
After combining like terms, the goal is to isolate the variable, which means getting the variable \(x\) alone on one side of the equation. Our equation now looks like this:\[14x + 18 = -10\]To isolate \(x\), we need to move the constant 18 to the other side. This is done by subtracting 18 from both sides:\[14x = -10 - 18\]Simplifying the right side gives:\[14x = -28\]Now, to solve for \(x\), divide both sides by 14:\[x = \frac{-28}{14}\]This further simplifies to:\[x = -2\]By isolating the variable, we've determined the solution for \(x\).
Solution Verification
Verifying the solution is an essential final step in solving equations to ensure that your answer is correct. Here, we take the solution \(x = -2\) and substitute it back into the original equation to see if it satisfies the equation:\[2(-2) + 6(2(-2) + 3) = -10\]First, calculate inside the parentheses:
- \(2(-2) = -4\)
- \(2(-2) + 3 = -4 + 3 = -1\)
- \(6(-1) = -6\)
Other exercises in this chapter
Problem 19
Solve each equation. \(|x|=23\)
View solution Problem 19
Let \(A=\\{0,1,2,3,4,5,6\\}, B=\\{4,6,8,10\\}\) \(C=\\{-3,-1,0,1,2\\},\) and \(D=\\{-3,1,2,5,8\\}\) Find each set. $$ C \cap D $$
View solution Problem 20
The LCD for \(\frac{2 x+1}{x^{2}+5 x+6}\) and \(\frac{3 x}{x^{2}-4}\) is $$\mathrm{LCD}=(x+2)(x+3)(x-2)$$ If we want to subtract these rational expressions, wha
View solution Problem 20
Find the domain and range of each relation. See Example 1. $$ \\{(15,-3),(0,0),(4,6),(-3,-8)\\} $$
View solution