Problem 19
Question
Simplify each expression. In each exercise, all variables are positive. \(\frac{(4 x)^{3}}{4 x^{3}}\)
Step-by-Step Solution
Verified Answer
The expression simplifies to 16.
1Step 1: Understanding the Problem
We are given the expression \( \frac{(4x)^3}{4x^3} \) to simplify, where all variables are considered positive. This involves simplifying both the numerator and the denominator separately.
2Step 2: Expanding the Numerator
The numerator of the expression is \((4x)^3\). To expand this, use the property of exponents that states \((ab)^n = a^n b^n\). We have \((4x)^3 = 4^3 \cdot x^3 = 64x^3\).
3Step 3: Simplifying the Fraction
Now the expression becomes \( \frac{64x^3}{4x^3} \). We can simplify this fraction by cancelling out common terms from the numerator and the denominator. The terms \(x^3\) in both the numerator and the denominator cancel each other out.
4Step 4: Simplifying the Remaining Expression
With \(x^3\) cancelled, we are left with \( \frac{64}{4} \). Divide 64 by 4 to simplify the expression: \( \frac{64}{4} = 16 \). Thus, the expression simplifies to 16.
Key Concepts
Understanding Exponent RulesFraction Simplification TechniquesRole of Positive Variables
Understanding Exponent Rules
Exponents can initially seem tricky, but following a few fundamental rules makes them much easier to handle. When simplifying expressions with exponents, you often encounter the 'Power of a Product' rule. This rule tells us that when you have \((ab)^n = a^n imes b^n\). It's a straightforward principle that states you apply the exponent to each factor inside the parentheses. For instance, let's look at the numerator in our exercise: \((4x)^3\).Using the rule, this expands to:
- \(4^3 imes x^3 = 64x^3\)
Fraction Simplification Techniques
Simplifying fractions is an essential skill when tackling algebraic expressions. The method is to cancel common factors in the numerator and the denominator. Let’s work through the example \( \frac{64x^3}{4x^3} \).1. **Identify Common Factors:** The terms \(x^3\) appear in both the numerator and denominator, allowing them to cancel out. After this cancellation, you get: \( \frac{64}{4} \).2. **Simplify Remaining Values:** Simplifying \( \frac{64}{4} \) gives you 16.
- This step involves basic division. Divide the top number by the bottom number.
- Ensure there are no more common factors left to cancel before concluding simplification.
Role of Positive Variables
In algebraic simplification, it’s critical to note when variables are restricted to positive values. Given the premise that variables are positive in the exercise, it streamlines the simplification:
- No need to worry about negative exponents or zero-denominator scenarios, which can complicate the process.
- For example, knowing \(x^3\) is positive ensures direct and valid cancellations occurred in the previous section.
Other exercises in this chapter
Problem 19
Solve each equation and check. \(4^{x+2}=4^{2 x}\)
View solution Problem 19
In \(18-23,\) solve for the variable in each equation. Express the solution to the nearest hundredth. $$ y^{\frac{2}{3}}=6 $$
View solution Problem 20
The decay constant of a radioactive element is \(-0.533\) per minute. If a sample of the element weighs 50 grams, what will be its weight after 2 minutes?
View solution Problem 20
In \(11-22,\) find the value of each expression when \(x \neq 0\) $$ \frac{3^{0}}{4} $$
View solution