Problem 19
Question
In \(18-23,\) solve for the variable in each equation. Express the solution to the nearest hundredth. $$ y^{\frac{2}{3}}=6 $$
Step-by-Step Solution
Verified Answer
The solution to the equation is approximately 14.70.
1Step 1: Isolate the term with the variable
The given equation is \( y^{\frac{2}{3}}=6 \). To solve for \( y \), we first need to undo the exponent with a reciprocal exponent.
2Step 2: Apply the cube exponent
To eliminate the fractional exponent, raise both sides of the equation to the reciprocal of \( \frac{2}{3} \), which is \( \frac{3}{2} \). This gives us \( (y^{\frac{2}{3}})^{\frac{3}{2}}=(6)^{\frac{3}{2}} \).
3Step 3: Simplify the left side
Simplifying the left side, we get \( y^{\frac{2}{3} \times \frac{3}{2}} = y^1 = y \).
4Step 4: Simplify the right side
On the right side, \( (6)^{\frac{3}{2}} \) can be broken down as \( (\sqrt{6})^3 \). First, calculate \( \sqrt{6} \), which is approximately 2.45. Then cube this to find \( 2.45^3 \).
5Step 5: Calculate \( 2.45^3 \) and round to the nearest hundredth
Compute \( 2.45^3 \), which is approximately 14.70. Therefore, \( y \approx 14.70 \).
Key Concepts
Rational ExponentsExponentiationSimplifying Expressions
Rational Exponents
Rational exponents are a different way of expressing powers and roots in mathematics. They serve as a bridge between integer exponents and radicals.
Understanding rational exponents is key to solving many algebraic problems.
Understanding rational exponents is key to solving many algebraic problems.
- **Rational exponents** are expressed as fractions. For example, in the expression \( y^{\frac{2}{3}} \), **2** is the numerator, and **3** is the denominator.
- The **numerator** tells us the power we need to raise the base number to. So, in \( y^{\frac{2}{3}} \), the base \( y \) is raised to the power of 2.
- The **denominator** represents the root that must be extracted from the base number. For \( y^{\frac{2}{3}} \), this means taking the cube root of \( y^2 \).
Exponentiation
Exponentiation is a fundamental operation in mathematics that involves raising a number to a power. It's a shortcut for repeated multiplication.
Understanding how to manipulate exponents is crucial for solving exponential equations.
**Handling Exponential Equations**
Understanding how to manipulate exponents is crucial for solving exponential equations.
**Handling Exponential Equations**
- When you **raise a power to another power**, you multiply the exponents. This rule helps simplify complex expressions: \( (a^m)^n = a^{m \times n} \).
- **Finding reciprocal exponents** is useful when dealing with fractional powers. For instance, to get rid of an exponent \( \frac{2}{3} \), you use \( (x^{\frac{2}{3}})^{\frac{3}{2}} = x \).
- To solve equations like \( (6)^{\frac{3}{2}} \), break it down: take the square root first, \( \sqrt{6} \), and then raise it to the power of 3.
Simplifying Expressions
Simplifying expressions is an essential skill when solving equations, particularly those involving exponents.
It involves rewriting expressions in a simpler, more concise form.
**Steps for Simplification**
It involves rewriting expressions in a simpler, more concise form.
**Steps for Simplification**
- Begin by **isolating** the term with a variable or power, if possible.
- Simplify one side at a time, whether it's breaking down radicals or multiplying out powers.
- For an expression like \( (\sqrt{6})^3 \), first compute the square root, then apply the exponent by multiplying: \( 2.45 \times 2.45 \times 2.45 \).
- Always round final answers to the required level of precision, such as to the nearest hundredth, ensuring your final answer is both accurate and precise.
Other exercises in this chapter
Problem 19
In \(3-37,\) express each power as a rational number in simplest form. $$ 9^{-\frac{1}{2}} $$
View solution Problem 19
Solve each equation and check. \(4^{x+2}=4^{2 x}\)
View solution Problem 19
Simplify each expression. In each exercise, all variables are positive. \(\frac{(4 x)^{3}}{4 x^{3}}\)
View solution Problem 20
The decay constant of a radioactive element is \(-0.533\) per minute. If a sample of the element weighs 50 grams, what will be its weight after 2 minutes?
View solution