Problem 19
Question
In Problems 17-22, find the Cartesian equations of the graphs of the given polar equations. \(r \cos \theta+3=0\)
Step-by-Step Solution
Verified Answer
The Cartesian equation is \( x = -3 \).
1Step 1: Convert Polar Equation to Cartesian Form
The given polar equation is \( r \cos \theta + 3 = 0 \). To convert this into Cartesian coordinates, we recall the relation between polar and Cartesian systems: \( x = r \cos \theta \) and \( y = r \sin \theta \). Substitute \( x \) for \( r \cos \theta \), resulting in the equation \( x + 3 = 0 \).
2Step 2: Rearrange the Equation
The equation from the previous step is \( x + 3 = 0 \). Isolate \( x \) by subtracting 3 from both sides to obtain \( x = -3 \).
3Step 3: Interpret the Solution
The Cartesian equation \( x = -3 \) represents a vertical line in the Cartesian plane that crosses the x-axis at -3. This line is parallel to the y-axis and every point on this line has the same x-coordinate, which is -3.
Key Concepts
Polar CoordinatesConversion Between SystemsPolar to Cartesian ConversionEquation of a Line
Polar Coordinates
Polar coordinates provide a unique way to express points on a plane. Instead of using the typical xy-coordinate system, polar coordinates use a different approach. Here, each point on the plane is defined by:
- A distance from a specific point called the origin (denoted as \( r \)).
- An angle \( \theta \), measured in radians or degrees, from a fixed direction.
- If \( r \) is positive, it indicates the distance out from the origin in the direction given by \( \theta \).
- If \( r \) is negative, it represents a point in the opposite direction along the same line.
Conversion Between Systems
When working with problems involving different systems of coordinates, conversion becomes important. Switching from polar to Cartesian coordinates is a common task, involving these simple relationships:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
- \( r = \sqrt{x^2 + y^2} \)
- \( \theta = \tan^{-1}(\frac{y}{x}) \)
Polar to Cartesian Conversion
The process of converting equations from polar to Cartesian form involves using the right substitutions. As demonstrated in the example, if you start with a polar equation like:
\( r \cos \theta + 3 = 0 \)
You can use the conversion formula \( x = r \cos \theta \). By substituting \( x \) for \( r \cos \theta \), the equation simplifies to:
\( r \cos \theta + 3 = 0 \)
You can use the conversion formula \( x = r \cos \theta \). By substituting \( x \) for \( r \cos \theta \), the equation simplifies to:
\( x + 3 = 0 \)
This is a typical step in converting polar equations into a system that is often easier to work within specific contexts, especially when sketching graphs on a Cartesian plane. It's about identifying these common substitutions and systematically applying them to simplify and interpret the given mathematical relationship.Equation of a Line
In Cartesian coordinates, lines have several standard forms, and each tells us something different about the line's characteristics. The equation derived from the conversion, \( x = -3 \), is a straightforward example of a vertical line. Vertical lines in the Cartesian plane:
- Run parallel to the y-axis.
- Have an undefined slope.
- Can be expressed using equations of the form \( x = a \), where "a" is a constant.
Other exercises in this chapter
Problem 18
Sketch the region that is inside the circle \(r=3 \sin \theta\) and outside the cardioid \(r=1+\sin \theta\), and find its area.
View solution Problem 18
Find the equation of the parabola whose vertex is the origin and whose axis is the \(y\)-axis if the parabola passes through the point \((-3,5)\). Make a sketch
View solution Problem 19
In each of Problems 1-20, a parametric representation of a curve is given. (a) Graph the curve. (b) Is the curve closed? Is it simple? (c) Obtain the Cartesian
View solution Problem 19
Find the equation of the given central conic. Ellipse with a focus at \((0,-5)\) and eccentricity \(\frac{1}{3}\)
View solution