Problem 19
Question
In each of Problems 1-20, a parametric representation of a curve is given. (a) Graph the curve. (b) Is the curve closed? Is it simple? (c) Obtain the Cartesian equation of the curve by eliminating the parameter (see Examples 1-4). $$ x=\cos \theta, y=-2 \sin ^{2} 2 \theta ;-\infty<\theta<\infty $$
Step-by-Step Solution
Verified Answer
(a) Plot the parametric form for visualization. (b) The curve relates through periodic trigonometric functions, suggesting non-simple and closed properties. (c) The Cartesian equation is \( y = -16x^4 + 16x^2 - 2 \).
1Step 1: Understanding the Parametric Equations
We are given the parametric equations: \( x = \cos \theta \) and \( y = -2 \sin^2 2\theta \). Here, \( \theta \) is the parameter that describes the curve, and it ranges from \(-\infty\) to \(\infty\).
2Step 2: Graphing the Curve
To graph the curve, we explore the values that \( x \) and \( y \) take. The range for \( x \) is from -1 to 1 since cosine varies between -1 and 1. We calculate a few points by selecting values of \( \theta \) and plotting corresponding \( (x, y) \) values. This will help us visualize the curve. Use a graphing software or calculator if necessary to plot these points.
3Step 3: Investigating Curve Properties
A curve is simple if it doesn't intersect itself, and it's closed if it forms a loop where the endpoint coincides with the start point. For \(-\infty < \theta < \infty\), we check whether \( x \) and \( y \) ever return to the same values as \( \theta \) varies, which would suggest closedness. Using trigonometric identities, observe periodic patterns of sine and cosine that may indicate such properties.
4Step 4: Eliminating the Parameter
To eliminate the parameter and obtain a Cartesian equation, we use trigonometric identities. Start with \( x = \cos \theta \), which implies \( \cos \theta = x \). Then, substitute in \( y = -2 \sin^2 2\theta \). Recall, \( \sin^2 2\theta = \frac{1 - \cos 4\theta}{2} \). We need to express \( \cos 4\theta \) in terms of \( x \). Use the double angle identities: \( \cos 2\theta = 2\cos^2 \theta - 1 = 2x^2 - 1 \), and \( \cos 4\theta = 2\cos^2 2\theta - 1 = 2(2x^2 - 1)^2 - 1 \). Substitute back to find \( y \) in terms of \( x \).
5Step 5: Formulating the Equation
Simplify the relation \( y = -2\sin^2 2\theta = -\left(1 - \cos 4\theta \right)\) and substitute \( \cos 4\theta = 2(2x^2 - 1)^2 - 1 \) to get the equation: \( y = -\left(1 - (2(2x^2 - 1)^2 - 1) \right) \) which simplifies to: \[ y = -2 (8x^4 - 8x^2 + 1) = -16x^4 + 16x^2 - 2 \]
6Step 6: Checking the Final Form
Ensure that all steps in converting the parametric equations involve correct trigonometric identities and algebraic manipulations. Double check substitutions and ensure they lead to the consistent Cartesian equation. The final result integrates both parametric forms into a unified curve description.
Key Concepts
Graphing CurvesTrigonometric IdentitiesCartesian EquationsCurve Properties
Graphing Curves
Graphing parametric curves involves plotting points based on parametric equations. A parametric equation specifies the coordinates of the points on a curve as functions of an independent parameter. In our case, the parameter is \( \theta \) and the equations are \( x = \cos \theta \) and \( y = -2 \sin^2 2\theta \).
As \( \theta \) changes, \( x \) varies between -1 and 1 because the cosine function ranges from -1 to 1.
As \( \theta \) changes, \( x \) varies between -1 and 1 because the cosine function ranges from -1 to 1.
- Begin by selecting a range of \( \theta \) values.
- Calculate \( x \) and \( y \) for each \( \theta \).
- Connect these points smoothly, as they form the continuous curve.
Trigonometric Identities
Trigonometric identities are formulas that express relationships between the angles and lengths of triangles. They are especially useful in simplifying expressions involving trigonometric functions. In the context of our parametric equations, we used several key identities.The double angle identities allow us to relate \( \sin^2 \theta \) and \( \cos^2 \theta \) to other angles. For instance:
- \( \cos 2\theta = 2\cos^2 \theta - 1 \)
- \( \sin^2 2\theta = \frac{1 - \cos 4\theta}{2} \)
Cartesian Equations
A Cartesian equation represents a curve by relating \( x \) and \( y \) in a single equation. To convert parametric equations into a Cartesian format, we eliminate the parameter by expressing \( y \) solely in terms of \( x \).
Here's how we proceed:
Here's how we proceed:
- Start from \( x = \cos \theta \), implying that \( \theta = \arccos x \).
- Using \( y = -2 \sin^2 2\theta \), substitute and simplify using identities such as \( \cos 4\theta \).
- Eventually, obtain a polynomial or other expression in terms of \( x \).
Curve Properties
Analyzing curve properties involves understanding certain geometric features, such as whether a curve is closed or simple. A closed curve loops back onto itself, while a simple curve does not intersect itself.
For the given parametric equations, curve properties can be inspected using periodicity:
For the given parametric equations, curve properties can be inspected using periodicity:
- Sine and cosine are periodic, which implies repetitiveness in the path of the curve.
- Calculate intersection points by checking if and when \( (x, y) \) pairs repeat over specified intervals of \( \theta \).
Other exercises in this chapter
Problem 18
Find the equation of the parabola whose vertex is the origin and whose axis is the \(y\)-axis if the parabola passes through the point \((-3,5)\). Make a sketch
View solution Problem 19
In Problems 17-22, find the Cartesian equations of the graphs of the given polar equations. \(r \cos \theta+3=0\)
View solution Problem 19
Find the equation of the given central conic. Ellipse with a focus at \((0,-5)\) and eccentricity \(\frac{1}{3}\)
View solution Problem 19
Sketch the graph of the given equation. $$ (x+2)^{2}=8(y-1) $$
View solution