Problem 19
Question
If \(z_{1}\) and \(z_{2}\) are any two complex numbers, then which of the following is not true. (a) \(\left|z_{1}+z_{2}\right| \leq\left|z_{1}\right|+\left|z_{2}\right|\) (b) \(\left|z_{1}-z_{2}\right| \leq\left|z_{1}\right|+\left|z_{2}\right|\) (c) \(\left|z_{1}-z_{2}\right| \geq \| z_{1}|-| z_{2}||\) (d) \(\left|z_{1}\right|-\left|z_{2}\right| \geq\left|z_{1}-z_{2}\right|\)
Step-by-Step Solution
Verified Answer
The correct answer is option (d), as it is not true.
1Step 1: Analyze Option (a)
Option (a) states \(\left|z_{1}+z_{2}\right| \leq\left|z_{1}\right|+\left|z_{2}\right|\). This is known as the Triangle Inequality for complex numbers, which is always true. Therefore, option (a) is true.
2Step 2: Analyze Option (b)
Option (b) states \(\left|z_{1}-z_{2}\right| \leq\left|z_{1}\right|+\left|z_{2}\right|\). This is also a form of the Triangle Inequality applied to complex numbers, and it is always true. Thus, option (b) is true.
3Step 3: Analyze Option (c)
Option (c) states \(\left|z_{1}-z_{2}\right| \geq \| z_{1}|-| z_{2}||\). This represents the Reverse Triangle Inequality, which is a fundamental property of norms in a vector space, and is always true. So, option (c) is true.
4Step 4: Analyze Option (d)
Option (d) states \(\left|z_{1}\right| - \left|z_{2}\right| \geq \left|z_{1} - z_{2}\right|\). This suggests that the difference in magnitudes of two complex numbers is greater than or equal to the magnitude of their difference, which contradicts the Triangle Inequality, making it not true. Therefore, option (d) is not true.
Key Concepts
Understanding the Triangle InequalityExploring the Reverse Triangle InequalityDelving into Complex Number Properties
Understanding the Triangle Inequality
The triangle inequality is a fundamental concept in the study of complex numbers, and it plays a crucial role in many mathematical proofs and applications. It is expressed as: \[ |z_1 + z_2| \leq |z_1| + |z_2| \] This inequality shows that the magnitude (or absolute value) of the sum of two complex numbers is always less than or equal to the sum of their magnitudes. Here's a simple way to think about it: imagine two sides of a triangle with lengths corresponding to \(|z_1|\) and \(|z_2|\) respectively. According to the triangle inequality, the length of the side formed by adding these vectors, \(|z_1 + z_2|\), will always be less or in line with the sum \(|z_1| + |z_2|\).
- This is an inequality not just applicable to complex numbers, but also to vectors in general.
- It demonstrates how adding two magnitudes cannot produce a magnitude greater than the sum of individual magnitudes.
Exploring the Reverse Triangle Inequality
While the triangle inequality deals with the addition of magnitudes, the reverse triangle inequality concerns their differences. It is represented as: \[ |z_1 - z_2| \geq ||z_1| - |z_2|| \] This inequality tells us that the absolute difference in magnitudes cannot be greater than the magnitude of the difference between two complex numbers. In simpler terms, if you subtract two complex numbers, the resulting magnitude \(|z_1 - z_2|\) will always be equal or greater than the absolute difference of their magnitudes. This makes sure that:
- The absolute distances between points (like vectors) respect their individual magnitude differences.
- It provides a bound on what the minimum distance can be when dealing with differences.
Delving into Complex Number Properties
Complex numbers extend the real number system to include solutions to equations like \( x^2 + 1 = 0 \). They are expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit, defined by \(i^2 = -1\). Here are key properties of complex numbers:
- Magnitude/Absolute Value: This is computed as \( |z| = \sqrt{a^2 + b^2} \), representing the distance from the origin in the complex plane.
- Conjugate: The conjugate of \( z = a + bi \) is \( \bar{z} = a - bi \), which reflects the number across the real axis.
- Addition and Subtraction: Cand be performed by adding or subtracting their respective real and imaginary parts.
Other exercises in this chapter
Problem 17
If \(y=\cos \theta+i \sin \theta\), then the value of \(y+\frac{1}{y}\) is (a) \(2 \cos \theta\) (b) \(2 \sin \theta\) (c) \(2 \operatorname{cosec} \theta\) (d)
View solution Problem 18
The imaginary part of \(i^{i}\) is (a) 0 (b) 1 (c) 2 (d) \(-1\)
View solution Problem 20
If \(z^{2}=-i\), then \(z=\) (a) \(\frac{1}{\sqrt{2}}(1+i)\) (b) \(\frac{1}{\sqrt{2}}(1+i)\) (c) \(\pm \frac{1}{\sqrt{2}}(1-i)\) (d) none of these
View solution Problem 21
If \(\omega\) is a non real cube root of unity, then \(\frac{a+b \omega+c \omega^{2}}{a \omega+c+b \omega^{2}}\) (a) 1 (b) \(\omega^{2}\) (c) \(\omega\) (d) non
View solution