Problem 18
Question
The imaginary part of \(i^{i}\) is (a) 0 (b) 1 (c) 2 (d) \(-1\)
Step-by-Step Solution
Verified Answer
The imaginary part of \(i^i\) is 0.
1Step 1: Express Imaginary i in Exponential Form
The first step is to express the imaginary unit, i, in its exponential form using Euler's formula. The complex number i can be written as \( e^{i\frac{\pi}{2}} \) because it represents a 90-degree rotation in the complex plane.
2Step 2: Apply Power to Exponential Form
To find \( i^i \), we apply the power to the exponential form: \( (e^{i\frac{\pi}{2}})^i = e^{i^2 \frac{\pi}{2}} = e^{-\frac{\pi}{2}} \). Here, we've used the fact that \( i^2 = -1 \).
3Step 3: Simplify Expression to Identify Real and Imaginary Parts
The expression \( e^{-\frac{\pi}{2}} \) is a real number since the exponent is purely real. Therefore, the imaginary part of \( i^i = e^{-\frac{\pi}{2}} \) is \( 0 \).
Key Concepts
The Imaginary UnitUnderstanding Euler's FormulaExponential Form and its UseVisualizing the Complex Plane
The Imaginary Unit
The imaginary unit, commonly denoted as \(i\), is a fundamental concept in complex numbers. It is defined as the square root of -1. This may seem strange at first because there is no real number that, when squared, gives a negative result. This property is unique to \(i\), making it useful for extending our understanding of numbers beyond the real number line.
The defining property of the imaginary unit is essential in complex number arithmetic. In essence, \(i^2 = -1\). This property opens up a whole new dimension of numbers, literally, as it allows us to represent and compute numbers that are not expressible in the standard number system.
With \(i\), we can perform operations that respect the normal rules of algebra. For example:
The defining property of the imaginary unit is essential in complex number arithmetic. In essence, \(i^2 = -1\). This property opens up a whole new dimension of numbers, literally, as it allows us to represent and compute numbers that are not expressible in the standard number system.
With \(i\), we can perform operations that respect the normal rules of algebra. For example:
- Adding: \(a + bi\)
- Multiplying: \((a + bi)(c + di)\)
- Conjugating: \(a - bi\)
Understanding Euler's Formula
Euler's formula is a brilliant equation that connects complex exponentials with trigonometric functions. It states that:\[e^{ix} = \cos(x) + i\sin(x)\]where \(x\) is a real number.
Euler's formula is particularly useful because it bridges the gap between exponential expressions and rotations in the complex plane. It tells us how complex exponentials behave in terms of circles and angles. This formula is used to express complex numbers in their polar form, a representation that emphasizes the magnitude and angle.
By utilizing Euler's formula, complex numbers like \(i\) can be expressed elegantly in terms of an exponential function. For \(i\), it can be written as:\[i = e^{i\frac{\pi}{2}}\]This representation portrays \(i\) as a 90-degree rotation, which can be very insightful when visualizing and working with complex numbers in the plane.
Euler's formula is particularly useful because it bridges the gap between exponential expressions and rotations in the complex plane. It tells us how complex exponentials behave in terms of circles and angles. This formula is used to express complex numbers in their polar form, a representation that emphasizes the magnitude and angle.
By utilizing Euler's formula, complex numbers like \(i\) can be expressed elegantly in terms of an exponential function. For \(i\), it can be written as:\[i = e^{i\frac{\pi}{2}}\]This representation portrays \(i\) as a 90-degree rotation, which can be very insightful when visualizing and working with complex numbers in the plane.
Exponential Form and its Use
Exponential form provides a powerful way to express complex numbers, making calculations involving powers and roots much more straightforward. The exponential form of a complex number relies on Euler's formula. Instead of working with rectangular coordinates, we switch to polar coordinates.
For a complex number \(z = re^{i\theta}\), \(r\) is the magnitude (or modulus) and \(\theta\) is the argument (or angle) in the complex plane. This format is especially advantageous when multiplying or dividing complex numbers, as multiplication and division are much easier to handle:
For a complex number \(z = re^{i\theta}\), \(r\) is the magnitude (or modulus) and \(\theta\) is the argument (or angle) in the complex plane. This format is especially advantageous when multiplying or dividing complex numbers, as multiplication and division are much easier to handle:
- Multiplication: \(z_1 \cdot z_2 = r_1e^{i\theta_1} \cdot r_2e^{i\theta_2} = r_1r_2e^{i(\theta_1 + \theta_2)}\)
- Division: \(\frac{z_1}{z_2} = \frac{r_1}{r_2}e^{i(\theta_1 - \theta_2)}\)
Visualizing the Complex Plane
The complex plane is an extension of the real number line into two dimensions, allowing us to visualize complex numbers more naturally.
In the complex plane, the horizontal axis is the real axis, and the vertical axis is the imaginary axis. Each complex number \(a + bi\) is represented as a point, or vector, in this plane.
Understanding the complex plane is crucial because it provides insight into how complex numbers behave, particularly regarding addition, multiplication, and how they can represent rotations and scaling:
In the complex plane, the horizontal axis is the real axis, and the vertical axis is the imaginary axis. Each complex number \(a + bi\) is represented as a point, or vector, in this plane.
Understanding the complex plane is crucial because it provides insight into how complex numbers behave, particularly regarding addition, multiplication, and how they can represent rotations and scaling:
- Adding complex numbers corresponds to vector addition.
- Multiplying complex numbers relates to rotating and scaling vectors.
- Conjugation reflects a complex number across the real axis.
Other exercises in this chapter
Problem 16
Let \(c\) be the set of complex numbers and \(z_{1}, z_{2}\) are in \(C .\) (i). Argument \(z_{1}=\) argument \(z_{2} \Rightarrow z_{1}=z_{2}\) (ii). \(\left|z_
View solution Problem 17
If \(y=\cos \theta+i \sin \theta\), then the value of \(y+\frac{1}{y}\) is (a) \(2 \cos \theta\) (b) \(2 \sin \theta\) (c) \(2 \operatorname{cosec} \theta\) (d)
View solution Problem 19
If \(z_{1}\) and \(z_{2}\) are any two complex numbers, then which of the following is not true. (a) \(\left|z_{1}+z_{2}\right| \leq\left|z_{1}\right|+\left|z_{
View solution Problem 20
If \(z^{2}=-i\), then \(z=\) (a) \(\frac{1}{\sqrt{2}}(1+i)\) (b) \(\frac{1}{\sqrt{2}}(1+i)\) (c) \(\pm \frac{1}{\sqrt{2}}(1-i)\) (d) none of these
View solution