Problem 19
Question
For exercises 7-32, simplify. $$ \frac{p^{2}+11 p+18}{p^{2}-2 p-15} \cdot \frac{p^{2}+3 p-40}{p^{2}+10 p+16} $$
Step-by-Step Solution
Verified Answer
\( \frac{p + 9}{p + 3} \)
1Step 1: Factor the Numerators and Denominators
Factor the expressions in the numerators and denominators. Start with the first fraction: Factor the numerator: \( p^2 + 11p + 18 = (p + 9)(p + 2) \)Factor the denominator: \( p^2 - 2p - 15 = (p - 5)(p + 3) \)For the second fraction:Factor the numerator: \( p^2 + 3p - 40 = (p + 8)(p - 5) \)Factor the denominator: \( p^2 + 10p + 16 = (p + 8)(p + 2) \)
2Step 2: Rewrite the Fraction Product
Using the factors obtained, rewrite the product of fractions: \[ \frac{(p + 9)(p + 2)}{(p - 5)(p + 3)} \times \frac{(p + 8)(p - 5)}{(p + 8)(p + 2)} \]
3Step 3: Cancel Common Factors
Identify and cancel out common factors in the numerators and denominators: \[ \frac{(p + 9)\cancel{(p + 2)}}{(p - 5)(p + 3)} \times \frac{\cancel{(p + 8)}(p - 5)}{\cancel{(p + 8)}\cancel{(p + 2)}} \]This simplifies to: \[ \frac{(p + 9)}{(p + 3)} \times \frac{(p - 5)}{(p - 5)} \]Cancel out the common factor \((p - 5)\):\[ \frac{(p + 9)}{(p + 3)} \times 1 \]So, it reduces to: \[ \frac{(p + 9)}{(p + 3)} \]
4Step 4: Simplified Expression
The simplified expression is: \( \frac{p + 9}{p + 3} \)
Key Concepts
Factoring PolynomialsRational ExpressionsSimplifying Fractions
Factoring Polynomials
Factoring polynomials is the process of breaking down a polynomial into simpler polynomials that, when multiplied together, give the original polynomial. This is a crucial step in simplifying expressions because it allows us to identify and cancel out common factors.
Polynomials in the form of quadratic expressions, like those in our original exercise, usually factor into two binomials. For example:
Polynomials in the form of quadratic expressions, like those in our original exercise, usually factor into two binomials. For example:
- The quadratic expression \( p^2 + 11p + 18 \) factors into \( (p + 9)(p + 2) \).
- Similarly, \( p^2 - 2p - 15 \) is factored as \( (p - 5)(p + 3) \).
Rational Expressions
Rational expressions are fractions where the numerator and the denominator are both polynomials. Simplifying rational expressions involves factoring both the numerator and the denominator and then reducing the fraction by canceling out any common factors.
In our problem, we start with four quadratic polynomials (two for each fraction). After factoring each, we reassemble the product of fractions as follows: \ \( \frac{p^2+11p+18}{p^2-2p-15}\ \times\ \frac{p^2+3p-40}{p^2+10p+16} \ \). After factoring, this becomes: \ \( \frac{(p + 9)(p + 2)}{(p - 5)(p + 3)} \times \frac{(p + 8)(p - 5)}{(p + 8)(p + 2)} \ \).
Next, we'll cancel any common factors. Noticing that \((p + 2) \) and \((p - 5)\ \) appear in both the numerator and the denominator, we can cancel them out, simplifying the expression to \[ \ \frac{p + 9}{p + 3} \ \ \]. Recognizing common factors and reducing rational expressions is key to simplifying.
In our problem, we start with four quadratic polynomials (two for each fraction). After factoring each, we reassemble the product of fractions as follows: \ \( \frac{p^2+11p+18}{p^2-2p-15}\ \times\ \frac{p^2+3p-40}{p^2+10p+16} \ \). After factoring, this becomes: \ \( \frac{(p + 9)(p + 2)}{(p - 5)(p + 3)} \times \frac{(p + 8)(p - 5)}{(p + 8)(p + 2)} \ \).
Next, we'll cancel any common factors. Noticing that \((p + 2) \) and \((p - 5)\ \) appear in both the numerator and the denominator, we can cancel them out, simplifying the expression to \[ \ \frac{p + 9}{p + 3} \ \ \]. Recognizing common factors and reducing rational expressions is key to simplifying.
Simplifying Fractions
Simplifying fractions means to reduce them to their simplest form where the top and bottom of the fraction no longer have any common factors other than 1. For rational expressions, this involves canceling common polynomial factors.
In our case following the cancellation of common factors, we land with: \( \ \frac{(p + 9)}{(p + 3)}\). Here, we reach the 'simplified expression' stage where no further cancellations can be performed. This means the expression \ \ \frac{(p + 9)}{(p + 3)} \ \ is at its simplest form, and we have fully simplified the initial given expression.
In our case following the cancellation of common factors, we land with: \( \ \frac{(p + 9)}{(p + 3)}\). Here, we reach the 'simplified expression' stage where no further cancellations can be performed. This means the expression \ \ \frac{(p + 9)}{(p + 3)} \ \ is at its simplest form, and we have fully simplified the initial given expression.
- Always check for any additional factors that may simplify further.
- Ensure that both numerator and denominator are checked for common terms to cancel.
Other exercises in this chapter
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