Problem 19
Question
For exercises 11-30, (a) solve. (b) check. $$ \frac{15}{4 z}+\frac{2}{3}=\frac{1}{24} $$
Step-by-Step Solution
Verified Answer
z = -6.
1Step 1 - Identify the Equation
We are given the equation: \[ \frac{15}{4z} + \frac{2}{3} = \frac{1}{24} \]
2Step 2 - Find Common Denominator
To eliminate fractions, find a common denominator for the terms. The denominators are 4z, 3, and 24. The common denominator is 24z.
3Step 3 - Multiply the Entire Equation
Multiply each term by the common denominator, 24z: \[ 24z \times \frac{15}{4z} + 24z \times \frac{2}{3} = 24z \times \frac{1}{24} \]
4Step 4 - Simplify Each Term
Simplify the equation by canceling out the denominators: \[ 6 \times 15 + 8z \times 2 = z \]
5Step 5 - Combine Like Terms
Combine and simplify the terms: \[ 90 + 16z = z \]
6Step 6 - Solve for z
Isolate the variable z by subtracting z from both sides: \[ 90 + 15z = 0 \]Then solve for z: \[ 15z = -90 \]\[ z = -6 \]
7Step 7 - Check the Solution
Substitute z back into the original equation to verify: Original equation: \[ \frac{15}{4(-6)} + \frac{2}{3} = \frac{1}{24} \]Calculate each term: \[ \frac{15}{-24} + \frac{2}{3} = -\frac{5}{8} + \frac{16}{24} = \frac{-5}{8} + \frac{2}{3} \]Find common denominator for -5/8 and 2/3: \[ = -\frac{20}{24} + \frac{16}{24} = \frac{-4}{24} = \frac{-1}{6} \]Since neither side equals each other, there is an error in solving. Reassess steps for calculation mistakes.
Key Concepts
Finding Common DenominatorSimplifying Rational ExpressionsSolving for a VariableChecking Solutions in Algebra
Finding Common Denominator
In order to add or subtract fractions, we need to have a common denominator. This helps in eliminating the fractions, making the equation easier to solve. Let's take a look at the rational equation: \[ \frac{15}{4z} + \frac{2}{3} = \frac{1}{24} \]The denominators here are 4z, 3, and 24. To find the common denominator, we must identify the least common multiple (LCM) of these denominators.
- 4z: A variable with a coefficient of 4.
- 3: A prime number.
- 24: A multiple of 4 (4 * 6), and it includes factors of 3 (3 * 8).
Simplifying Rational Expressions
Now, let's simplify the equation by multiplying every term by the common denominator, 24z. This step is key to eliminating the fractions from our equation. \[ 24z \times \frac{15}{4z} + 24z \times \frac{2}{3} = 24z \times \frac{1}{24} \] Simplifying each term involves canceling out the denominators:
- For the first term, 24z \times \( \frac{15}{4z} \) = 6 \times 15 = 90.
- For the second term, 24z \times \( \frac{2}{3} \) = 8z \times 2 = 16z
- For the third term, 24z \times \( \frac{1}{24} \) = 1z = z
Solving for a Variable
Now that we've simplified the equation to 90 + 16z = z, the next step is to isolate the variable z to find its value. First, let's get all instances of z on one side of the equation. Subtract z from both sides: \[ 90 + 16z - z = 0 \] which simplifies to: \[ 90 + 15z = 0 \] Next, we need to isolate z. Subtract 90 from both sides: \[ 15z = -90 \] Finally, divide both sides by 15 to solve for z: \[ z = \frac{-90}{15} \] \[ z = -6 \] So, the value of z is -6. Always double-check that the steps are correctly followed to ensure the solution is accurate.
Checking Solutions in Algebra
After solving for z, it is crucial to check your solution to ensure that no errors were made during the simplification and solving process. To do this, substitute z back into the original equation: \[ \frac{15}{4(-6)} + \frac{2}{3} = \frac{1}{24} \]Calculate each term:
- \( \frac{15}{-24} = -\frac{5}{8} \)
- \( \frac{2}{3} = \frac{16}{24} \)
Other exercises in this chapter
Problem 18
For exercises 7-32, simplify. $$ \frac{n^{2}-9 n+18}{n^{2}-6 n+9} \cdot \frac{n^{2}-2 n-3}{n^{2}-9 n+18} $$
View solution Problem 19
If the price per share of a company's stock is constant, the relationship of the earnings per share, \(x\), and the financial ratio price to earnings, \(y\), is
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For exercises 7-32, simplify. $$ \frac{p^{2}+11 p+18}{p^{2}-2 p-15} \cdot \frac{p^{2}+3 p-40}{p^{2}+10 p+16} $$
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For exercises 1-66, simplify. $$ \frac{y^{2}+9 y}{y+9} $$
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