Problem 19
Question
Find three ordered pairs that are solutions of the equation. $$ x=\frac{1}{2} $$
Step-by-Step Solution
Verified Answer
The three ordered pairs that are solutions of the equation \(x=\frac{1}{2}\) are: \(\left(\frac{1}{2}, -1\right)\), \(\left(\frac{1}{2}, 0\right)\), and \(\left(\frac{1}{2}, 1\right)\).
1Step 1: Understanding the Equation
Look at the given equation, \(x=\frac{1}{2}\). The value of x is constant and equal to \(\frac{1}{2}\) for all points on the graph of this equation. The y-value isn't specified, which means it can be any real number.
2Step 2: Choosing Y-Values
It's arbitrary which y-values to choose because it can be any real number. For instance, let's select y-values to be -1, 0, and 1.
3Step 3: Forming Ordered Pairs
For each chosen y-value, formulate an ordered pair. Since x is always \(\frac{1}{2}\), the ordered pairs are \(\left(\frac{1}{2}, -1\right)\), \(\left(\frac{1}{2}, 0\right)\), and \(\left(\frac{1}{2}, 1\right)\).
Key Concepts
Constants in EquationsGraphing EquationsSolutions of Equations
Constants in Equations
When we talk about constants in equations, we're referring to numbers that remain fixed in value. In the equation \(x = \frac{1}{2}\), \(x\) is a constant because it always equals \(\frac{1}{2}\), no matter what. Constants are crucial because they define specific, unchanging parts of an equation. In our case, though \(x\) is fixed, the equation tells us that \(y\) could be any value. This unique setup helps us understand what lines would look like on a graph. Whenever you encounter an equation with a constant like this, it simplifies part of the problem by giving you a piece of the puzzle you don't need to guess about.
Graphing Equations
Graphing an equation involves plotting points based on the relationship between variables. In the equation \(x = \frac{1}{2}\), the graph is a vertical line at \(x = \frac{1}{2}\). Why vertical? Because no matter what, \(x\) does not change, even if \(y\) does. To graph such an equation, follow these simple steps:
- Identify the fixed value for \(x\), which is \(\frac{1}{2}\).
- Select various \(y\) values, such as -1, 0, and 1, which can be any real number.
- Plot the points: \(\left(\frac{1}{2}, -1\right)\), \(\left(\frac{1}{2}, 0\right)\), and \(\left(\frac{1}{2}, 1\right)\).
Solutions of Equations
Solutions in equations refer to the set of values that satisfy an equation. For our equation \(x = \frac{1}{2}\), every solution is where \(x\) equals \(\frac{1}{2}\) and \(y\) can be any number. This means there are infinite solutions because there are infinite possible values for \(y\).Steps to determine solutions:
- Start with the fixed value from the equation—in this instance, \(x = \frac{1}{2}\).
- Select any real number for \(y\) and pair it with the constant \(x\).
- Form ordered pairs, such as \((\frac{1}{2}, -1)\), \((\frac{1}{2}, 0)\), \((\frac{1}{2}, 1)\).
Other exercises in this chapter
Problem 19
Find the slope and y-intercept of the graph of the equation. $$y=2 x-9$$
View solution Problem 19
Find the x-intercept of the line. $$ x+4 y=-2 $$
View solution Problem 19
Determine whether the ordered pair is a solution of the equation. $$ 5 x-8 y=15,(3,0) $$
View solution Problem 19
Without plotting the point, tell whether it is in Quadrant I, Quadrant II, Quadrant III, or Quadrant IV. $$ (5,-3) $$
View solution