Problem 19
Question
Find the solution set to each equation. $$x+1+\frac{2 x-5}{x-5}=\frac{x}{x-5}$$
Step-by-Step Solution
Verified Answer
The solution is \( x = -2 \).
1Step 1: Move the rational terms to one side
Start by isolating the rational terms on one side of the equation. Subtract \(\frac{x}{x-5}\) from both sides of the equation: \[ x + 1 + \frac{2x - 5}{x-5} - \frac{x}{x-5} = 0 \]
2Step 2: Combine the rational terms
Combine the terms involving fractions: \[ \frac{2x - 5}{x-5} - \frac{x}{x-5} = \frac{2x - 5 - x}{x-5} = \frac{x - 5}{x-5} = 1 \] So the equation now becomes: \[ x + 1 + 1 = 0 \]
3Step 3: Simplify
Now simplify the equation: \[ x + 2 = 0 \]
4Step 4: Solve for \(x\)
Subtract 2 from both sides to solve for \( x \): \[ x = -2 \]
Key Concepts
Isolating VariablesCombining FractionsSimplifying EquationsSolving Linear Equations
Isolating Variables
When solving rational equations, the first step often involves isolating variables. This means you want to get the variable you're solving for on one side of the equation. In our example, we start by moving the rational terms to one side:
$$x + 1 + \frac{2x - 5}{x-5} = \frac{x}{x-5}$$
To isolate the variables, we subtract \frac{x}{x-5}\ from both sides:
$$x + 1 + \frac{2x - 5}{x-5} - \frac{x}{x-5} = 0$$
. Isolating variables simplifies solving the equation because it groups similar terms together, making the next steps clearer.
$$x + 1 + \frac{2x - 5}{x-5} = \frac{x}{x-5}$$
To isolate the variables, we subtract \frac{x}{x-5}\ from both sides:
$$x + 1 + \frac{2x - 5}{x-5} - \frac{x}{x-5} = 0$$
. Isolating variables simplifies solving the equation because it groups similar terms together, making the next steps clearer.
Combining Fractions
In rational equations, combining fractions is essential when you find you're dealing with terms having the same denominator. In this case, after isolating the variable, you have:
$$\frac{2x - 5}{x-5} - \frac{x}{x-5}$$
Since both fractions share the same denominator, you can easily combine them into one:
$$\frac{2x - 5 - x}{x-5} = \frac{x - 5}{x-5}$$.
. Always remember to combine fractions by dealing with their numerators and keeping the common denominator. This step simplifies the equation significantly, preparing it for solving.
$$\frac{2x - 5}{x-5} - \frac{x}{x-5}$$
Since both fractions share the same denominator, you can easily combine them into one:
$$\frac{2x - 5 - x}{x-5} = \frac{x - 5}{x-5}$$.
. Always remember to combine fractions by dealing with their numerators and keeping the common denominator. This step simplifies the equation significantly, preparing it for solving.
Simplifying Equations
Simplifying equations is crucial in problem-solving. It involves reducing the equation to its simplest form. From the previous step, we had:
$$\frac{x - 5}{x-5}$$
Since the numerator and the denominator are the same, this fraction simplifies to 1:
$$\frac{x - 5}{x-5} = 1$$.
. This turns our equation into a much simpler form:
$$x + 1 + 1 = 0$$
, which simplifies further to:
$$x + 2 = 0$$.
Simplifying equations can be thought of as cleaning up your workspace. It makes the final solving steps much more straightforward.
$$\frac{x - 5}{x-5}$$
Since the numerator and the denominator are the same, this fraction simplifies to 1:
$$\frac{x - 5}{x-5} = 1$$.
. This turns our equation into a much simpler form:
$$x + 1 + 1 = 0$$
, which simplifies further to:
$$x + 2 = 0$$.
Simplifying equations can be thought of as cleaning up your workspace. It makes the final solving steps much more straightforward.
Solving Linear Equations
The final step in many problems like this is solving a linear equation. Once we've simplified, we get to a point where:
$$x + 2 = 0$$
Now, you just have to solve for the variable by isolating it:
Subtract 2 from both sides:
$$x = -2$$
. Solving linear equations usually involves basic operations: addition, subtraction, multiplication, or division. It's about isolating the variable to find its value. And there you go! The solution is neatly found after all these steps:
$$x = -2$
$$x + 2 = 0$$
Now, you just have to solve for the variable by isolating it:
Subtract 2 from both sides:
$$x = -2$$
. Solving linear equations usually involves basic operations: addition, subtraction, multiplication, or division. It's about isolating the variable to find its value. And there you go! The solution is neatly found after all these steps:
$$x = -2$
Other exercises in this chapter
Problem 18
Which real numbers cannot be used in place of the variable in each rational expression? $$\frac{x^{2}-3 x-4}{2 x^{5}-2 x}$$
View solution Problem 19
$$\text { Solve each formula for the indicated variable.}$$ $$V=\frac{4}{3} \pi r^{2} h \text { for } h$$
View solution Problem 19
Reduce each rational expression to its lowest terms. $$\frac{6}{57}$$
View solution Problem 20
$$\text { Solve each formula for the indicated variable.}$$ $$h=\frac{S-2 \pi r^{2}}{2 \pi r} \text { for } S$$
View solution