Problem 19
Question
Determine whether the composite function \(f \circ g\) is odd or even in each of the following cases: (a) \(f\) and \(g\) are both even; (b) \(f\) and \(g\) are both odd; (c) \(f\) is even and \(g\) is odd; (d) \(f\) is odd and \(g\) is even.
Step-by-Step Solution
Verified Answer
(a) even, (b) odd, (c) even, (d) odd
1Step 1 - Recall Definitions
An even function satisfies the property: \( f(x) = f(-x) \) for all \( x \). An odd function satisfies the property: \( f(x) = -f(-x) \) for all \( x \).
2Step 2 - Analyze Case (a)
For \( f \) and \( g \) both being even functions: \( f(x) = f(-x) \) and \( g(x) = g(-x) \). Therefore, \( f(g(x)) = f(g(-x)) \), showing that \( f \circ g \) is even.
3Step 3 - Analyze Case (b)
For \( f \) and \( g \) both being odd functions: \( f(x) = -f(-x) \) and \( g(x) = -g(-x) \). Therefore, \( f(g(x)) = f(-g(-x)) = -f(g(-x)) \), showing that \( f \circ g \) is odd.
4Step 4 - Analyze Case (c)
For \( f \) being even and \( g \) being odd functions: \( f(x) = f(-x) \) and \( g(x) = -g(-x) \). Therefore, \( f(g(x)) = f(-g(-x)) = f(g(-x)) \), showing that \( f \circ g \) is even.
5Step 5 - Analyze Case (d)
For \( f \) being odd and \( g \) being even functions: \( f(x) = -f(-x) \) and \( g(x) = g(-x) \). Therefore, \( f(g(x)) = -f(g(-x)) \), showing that \( f \circ g \) is odd.
Key Concepts
Even FunctionsOdd FunctionsFunction PropertiesFunction Composition
Even Functions
Understanding whether a function is even can help in many mathematical problems. An even function is symmetric with respect to the y-axis. That means when you reflect the graph of the function across the y-axis, it remains unchanged. Mathematically, a function is even if it satisfies the condition: An example would be a simple quadratic function and . This property is essential to know, as it can simplify complex problems. It often allows you to consider only non-negative values of x and then use symmetry.
Odd Functions
An odd function behaves differently from an even function. It is symmetric with respect to the origin. This means reflecting the graph of the function across both the x-axis and y-axis leaves the graph unchanged. A function is classified as odd if it satisfies the condition: A common example. would be the cubic function Knowing if a function is odd or even can help in simplifying integrals and solving equations, as it provides valuable symmetry properties
Function Properties
Functions have a variety of important properties beyond just being even or odd. Critical properties include:
- Composability: You can combine functions to create new ones using composition Continuity: A function is continuous if you can draw it without lifting your pencil Differentiability: A function is differentiable if it has a derivative at every point in its domain
Function Composition
Function composition involves creating a new function by applying one function to the results of another. Mathematically, this is written as This operator can help simplify complex functions by breaking them into more manageable parts. In the context of even and odd functions, the composition can change the symmetry properties of the resulting function. For example, if both f and g are even, then Otherwise changes and which can streamline your analysis and computation.
Other exercises in this chapter
Problem 18
In Exercises 7 through 28 , draw a sketch of the graph of the equation. $$ y=-|x|+2 $$
View solution Problem 18
$$ \text { Three consecutive vertices of a parallelogram are }(-4,1),(2,3), \text { and }(8,9) \text {. Find the coordinates of the fourth vertex. } $$
View solution Problem 19
In Exercises 11 through 34, the function is the set of all ordered pairs \((x, y)\) satisfying the given equation. Find the domain and range of the function, an
View solution Problem 19
In Exercises 15 through 20 , determine whether the graph is a circle, a point- circle, or the empty set. $$ 36 x^{2}+36 y^{2}-48 x+36 y-119=0 $$
View solution