Problem 18
Question
In Exercises 7 through 28 , draw a sketch of the graph of the equation. $$ y=-|x|+2 $$
Step-by-Step Solution
Verified Answer
Draw an upside-down V with vertex at (0,2).
1Step 1: Identify the Base Function
The base function is the absolute value function, which is written as \( y = |x| \). This is a V-shaped graph that opens upwards and is symmetric about the y-axis.
2Step 2: Apply the Negation
The equation given is \( y = -|x| + 2 \). Negating the absolute value function, \( -|x| \), flips the V-shaped graph upside down. Now the graph opens downwards.
3Step 3: Apply the Vertical Shift
The equation has a +2 at the end, which means the entire graph is shifted 2 units upwards. This moves the vertex of the upside-down V from (0,0) to (0,2).
4Step 4: Sketch the Graph
Combine the information from the previous steps to sketch the graph. Start at the vertex (0,2) and draw two lines extending downwards to the left and right symmetrically. The left part of the graph will follow the line \( y = -x + 2 \) and the right part will follow the line \( y = x + 2 \) when considering the absolute value.
Key Concepts
absolute value functiongraph transformationsvertex of a graphvertical shiftsreflection of functions
absolute value function
The absolute value function is a fundamental concept in algebra. Generally written as \( y = |x| \), it produces a V-shaped graph. This graph opens upwards and is symmetric about the y-axis. The absolute value function measures the distance of a number from zero, giving only non-negative outputs.
Understanding the basic shape and properties of \( y = |x| \) is crucial before applying any transformations.
Understanding the basic shape and properties of \( y = |x| \) is crucial before applying any transformations.
graph transformations
Graph transformations help alter the appearance of the base function. For the given problem, we start with the base function \( y = |x| \). There are many types of transformations:
For instance, the equation \( y = -|x| + 2 \) involves a reflection and a vertical shift.
- Vertical Shifts
- Horizontal Shifts
- Reflections
- Stretching and Compressing
For instance, the equation \( y = -|x| + 2 \) involves a reflection and a vertical shift.
vertex of a graph
The vertex of a graph is a key feature, particularly in absolute value functions. For \( y = |x| \), the vertex is the point where the graph changes direction, located at (0,0).
In the given problem, transformations shift the vertex:
In the given problem, transformations shift the vertex:
- The negation affects the direction (reflection)
- The vertical shift changes the vertical position
vertical shifts
Vertical shifts move the graph up or down without changing its shape. This is done by adding or subtracting a constant to the function. In our exercise, the +2 at the end of \( y = -|x| + 2 \) shifts the graph 2 units upwards.
Hence, what was originally at (0,0) for \( y = -|x| \), becomes (0,2) for \( y = -|x| + 2 \).
Hence, what was originally at (0,0) for \( y = -|x| \), becomes (0,2) for \( y = -|x| + 2 \).
reflection of functions
Reflections flip the graph over a specific axis. The equation \( y = -|x| \) involves a reflection over the x-axis. This means our V-shaped graph, which originally opens upwards, now opens downwards.
The reflection affects the direction of our graph, making it open downwards but still symmetric about the y-axis.
The reflection affects the direction of our graph, making it open downwards but still symmetric about the y-axis.
Other exercises in this chapter
Problem 18
In Exercises 15 through 20 , determine whether the graph is a circle, a point- circle, or the empty set. $$ x^{2}+y^{2}+2 x-4 y+5=0 $$
View solution Problem 18
In Exercises 15 through 26 , find the solution set of the given inequality, and illustrate the solution on the real number line. $$ |6-2 x| \geq 7 $$
View solution Problem 18
$$ \text { Three consecutive vertices of a parallelogram are }(-4,1),(2,3), \text { and }(8,9) \text {. Find the coordinates of the fourth vertex. } $$
View solution Problem 19
Determine whether the composite function \(f \circ g\) is odd or even in each of the following cases: (a) \(f\) and \(g\) are both even; (b) \(f\) and \(g\) are
View solution