Problem 19
Question
An initial amplitude \(k,\) damping constant \(c,\) and frequency \(f\) or period \(p\) are given. (Recall that frequency and period are related by the equation \(f=1 / p . )\) (a) Find a function that models the damped harmonic motion. Use a function of the form \(y=k e^{-c t} \cos \omega t\) in Exercises \(17-20,\) and of the form \(y=k e^{-c t}\) sin \(\omega t\) in Exercises \(21-24\). (b) Graph the function. $$k=100, \quad c=0.05, \quad p=4$$
Step-by-Step Solution
Verified Answer
The function is \( y = 100 e^{-0.05 t} \cos \left(\frac{\pi}{2} t\right) \).
1Step 1: Calculate Angular Frequency
First, we need to determine the angular frequency \( \omega \). We know that the frequency \( f \) is related to the period \( p \) by the equation \( f = \frac{1}{p} \). For period \( p = 4 \), the frequency \( f \) is \( \frac{1}{4} = 0.25 \). The angular frequency \( \omega \) is given by \( \omega = 2\pi f \). Therefore, \( \omega = 2\pi \times 0.25 = \frac{\pi}{2} \).
2Step 2: Choose the Correct Function Form
Since this problem involves using the form \( y = k e^{-c t} \cos \omega t \) for exercises 17-20, we will utilize this cosine function form to represent the damped harmonic motion.
3Step 3: Substitute Given Values
Substitute the given values into the chosen function form. The values are \( k = 100 \), \( c = 0.05 \), and \( \omega = \frac{\pi}{2} \). Thus, the function becomes \( y = 100 e^{-0.05 t} \cos \left(\frac{\pi}{2} t\right) \).
4Step 4: Graph the Function
To graph the function \( y = 100 e^{-0.05 t} \cos \left(\frac{\pi}{2} t\right) \), start by plotting the exponential decay \( 100 e^{-0.05 t} \) which indicates how the amplitude decreases over time. Overlay the cosine wave \( \cos \left(\frac{\pi}{2} t\right) \) which oscillates between -1 and 1. The complete graph will show an oscillating cosine wave with amplitude decreasing exponentially.
Key Concepts
Angular Frequency in Damped Harmonic MotionUnderstanding Exponential DecayRole of the Cosine Function in Oscillations
Angular Frequency in Damped Harmonic Motion
Angular frequency, often represented as \( \omega \), plays a crucial role in damped harmonic motion. It helps determine how rapidly the system oscillates. This can be pivotal in understanding the behavior of systems like vibrating springs or even electrical circuits.
To find angular frequency, we need the frequency \( f \), which we derive from the period \( p \). The relationship is straightforward: \( f = \frac{1}{p} \). Once we've calculated \( f \), we employ the equation \( \omega = 2\pi f \) to find \( \omega \).
To find angular frequency, we need the frequency \( f \), which we derive from the period \( p \). The relationship is straightforward: \( f = \frac{1}{p} \). Once we've calculated \( f \), we employ the equation \( \omega = 2\pi f \) to find \( \omega \).
- For a given period \( p \), like \( p = 4 \), the frequency is \( f = \frac{1}{4} = 0.25 \).
- Multiplying by \( 2\pi \), we find \( \omega = \frac{\pi}{2} \).
Understanding Exponential Decay
Exponential decay is an essential feature in the context of damped harmonic motion, indicating how the system loses energy over time. In the equation \( y = k e^{-c t} \cos \omega t \), the term \( e^{-c t} \) represents exponential decay.
Let's break it down:
Let's break it down:
- The constant \( c \) is the damping constant, which measures how quickly the system's amplitude decreases.
- \( e^{-c t} \) implies that as time \( t \) increases, the amplitude diminishes, approaching zero.
Role of the Cosine Function in Oscillations
In damped harmonic motion, the cosine function reflects the oscillatory movement of the system. The equation \( y = k e^{-c t} \cos \omega t \) uses \( \cos \omega t \) to define the periodic oscillation.
The cosine function is a fundamental function in trigonometry signifying the wave-like pattern of oscillations. Consider:
The cosine function is a fundamental function in trigonometry signifying the wave-like pattern of oscillations. Consider:
- The cosine component moves between -1 and 1, ensuring the motion oscillates smoothly.
- It contributes to the "+" and "-" swings of the harmonic behavior without affecting the exponential decay.
Other exercises in this chapter
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