Problem 18
Question
Write the expression as the logarithm of a single quantity. $$\frac{1}{2} \ln x+2 \ln y-3 \ln z$$
Step-by-Step Solution
Verified Answer
The given expression can be simplified using logarithmic properties as follows:
\(\frac{1}{2} \ln x + 2 \ln y - 3 \ln z = \ln\left(\frac{x^{\frac{1}{2}} \cdot y^2}{z^3}\right)\)
1Step 1: Identify the logarithmic properties to simplify the expression
Here we will use the following logarithm properties:
1. \(log_b(m \cdot n) = log_b(m) + log_b(n)\)
2. \(log_b\left(\frac{m}{n}\right) = log_b(m) − log_b(n)\)
3. \(log_b\left({m}^{n}\right) = n \cdot log_b(m)\)
These properties will be applied to the given expression to make it a logarithm of a single quantity.
2Step 2: Apply the power law
We can start by applying property 3 to the coefficients of the logarithms:
\(\frac{1}{2} \ln x + 2 \ln y - 3 \ln z = \ln\left(x^{\frac{1}{2}}\right) + \ln\left(y^2\right) - \ln\left(z^3\right)\)
3Step 3: Combine the logarithms using properties
Now, we will apply the properties 1 and 2 to the updated expression:
\(\ln\left(x^{\frac{1}{2}}\right) + \ln\left(y^2\right) - \ln\left(z^3\right) = \ln\left(\frac{x^{\frac{1}{2}} \cdot y^2}{z^3}\right)\)
4Step 4: Write the final expression
We now have the expression written as a single logarithm:
\(\frac{1}{2} \ln x + 2 \ln y - 3 \ln z = \ln\left(\frac{x^{\frac{1}{2}} \cdot y^2}{z^3}\right)\)
Key Concepts
Logarithm PropertiesPower Law of LogarithmsSimplification of Expressions
Logarithm Properties
Logarithms have several key properties that help simplify complex expressions. These properties make it easier to manipulate and solve expressions involving logarithms.
Here are the main properties of logarithms you should remember:
Here are the main properties of logarithms you should remember:
- Product Rule: \( \log_b(m \cdot n) = \log_b(m) + \log_b(n) \) - This property states that the logarithm of a product is equal to the sum of the logarithms of the factors.
- Quotient Rule: \( \log_b\left( \frac{m}{n} \right) = \log_b(m) - \log_b(n) \) - This property explains that the logarithm of a quotient is the difference between the logarithms of the numerator and the denominator.
- Power Rule: \( \log_b(m^n) = n \cdot \log_b(m) \) - According to this rule, the logarithm of a power is the exponent times the logarithm of the base.
Power Law of Logarithms
One of the most powerful tools when working with logarithmic expressions is the power law. It is particularly useful when coefficients exist before the logarithm. The power law states that \( \log_b(m^n) = n \cdot \log_b(m) \).
This rule allows us to move any coefficient in front of a logarithm to an exponent on the base. For instance, when given an expression like \( \frac{1}{2} \ln x \), you can rewrite it as \( \ln(x^{\frac{1}{2}}) \).
Similarly, a term like \( 2 \ln y \) becomes \( \ln(y^2) \). This transformation often simplifies the process of combining multiple terms into a single logarithm.
By applying the power law, each log term can be adjusted to facilitate further simplification using other properties. Mastery of this law helps deal with more complex logarithmic expressions efficiently.
This rule allows us to move any coefficient in front of a logarithm to an exponent on the base. For instance, when given an expression like \( \frac{1}{2} \ln x \), you can rewrite it as \( \ln(x^{\frac{1}{2}}) \).
Similarly, a term like \( 2 \ln y \) becomes \( \ln(y^2) \). This transformation often simplifies the process of combining multiple terms into a single logarithm.
By applying the power law, each log term can be adjusted to facilitate further simplification using other properties. Mastery of this law helps deal with more complex logarithmic expressions efficiently.
Simplification of Expressions
When faced with expressions involving logarithms, simplification usually involves combining multiple logs into a single expression. This process utilizes the product, quotient, and power rules of logarithms.
Consider the expression \( \frac{1}{2} \ln x + 2 \ln y - 3 \ln z \). To simplify it as a single logarithm, we apply the power rule to adjust the exponents first:
Consider the expression \( \frac{1}{2} \ln x + 2 \ln y - 3 \ln z \). To simplify it as a single logarithm, we apply the power rule to adjust the exponents first:
- \( \frac{1}{2} \ln x \) becomes \( \ln(x^{\frac{1}{2}}) \)
- \( 2 \ln y \) becomes \( \ln(y^2) \)
- \( -3 \ln z \) becomes \( \ln(z^{-3}) \)
- Addition of logs: \( \ln(x^{\frac{1}{2}}) + \ln(y^2) = \ln(x^{\frac{1}{2}} \cdot y^2) \)
- Subtraction of logs: \( \ln(x^{\frac{1}{2}} \cdot y^2) - \ln(z^3) = \ln\left(\frac{x^{\frac{1}{2}} \cdot y^2}{z^3}\right) \)
Other exercises in this chapter
Problem 17
Write the expression as the logarithm of a single quantity. $$2 \ln a+3 \ln b$$
View solution Problem 17
Solve the equation for \(x\). $$(2.1)^{x+2}=(2.1)^{5}$$
View solution Problem 18
Solve the equation for \(x\). $$(-1.3)^{x-2}=(-1.3)^{2 x+1}$$
View solution Problem 19
The length (in centimeters) of a typical Pacific halibut \(t\) yr old is approximately $$ f(t)=200\left(1-0.956 e^{-0.18 t}\right) $$ What is the length of a ty
View solution