Problem 18
Question
Simplify by using the imaginary unit \(i\). $$ \sqrt{-20} \cdot \sqrt{-5} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-10\).
1Step 1: Understand the Imaginary Unit
The imaginary unit, represented by \(i\), is defined as \(i = \sqrt{-1}\). This definition is important because it allows us to express the square root of any negative number \(a\) as \(\sqrt{-a} = i\sqrt{a}\).
2Step 2: Express Each Square Root with \(i\)
Rewrite each square root using the imaginary unit. \(\sqrt{-20}\) becomes \(i\sqrt{20}\) and \(\sqrt{-5}\) becomes \(i\sqrt{5}\). This is because both expressions involve the square root of a negative number.
3Step 3: Simplify the Product
Compute the product of \(\sqrt{-20} \cdot \sqrt{-5}\) by substituting the expressions from Step 2: \[(i\sqrt{20}) \cdot (i\sqrt{5}) = i^2 \cdot \sqrt{20} \cdot \sqrt{5}\]
4Step 4: Simplify Using \(i^2 = -1\)
Recall that \(i^2 = -1\). Substitute -1 for \(i^2\) in the expression: \[\sqrt{-20} \cdot \sqrt{-5} = -\sqrt{20}\cdot \sqrt{5}\]
5Step 5: Simplify the Radicals
Calculate \(\sqrt{20} \cdot \sqrt{5} = \sqrt{100}\) because multiplying two square roots \(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\). Then, \(\sqrt{100} = 10\).
6Step 6: Combine and Simplify
Substitute the simplified product back into the expression: \(-\sqrt{100} = -10\). Thus, the original expression simplifies to \(-10\).
Key Concepts
Imaginary UnitSimplifying ExpressionsSquare Roots of Negative Numbers
Imaginary Unit
The imaginary unit is a fundamental concept in complex numbers. This unit is represented by the symbol \(i\). The key property of \(i\) is that it is defined by \(i = \sqrt{-1}\). This definition allows mathematicians to deal with the square roots of negative numbers, which otherwise would be undefined in the realm of real numbers.
When you use \(i\), you can express negative square roots as simpler expressions involving \(i\). For example, if you have \(\sqrt{-a}\), you can rewrite it as \(i\sqrt{a}\). This is a very useful tool because it simplifies operations involving negative square roots and gives us the means to expand into the broader field of complex numbers.When working with the imaginary unit, always keep in mind that the square of \(i\) is \(-1\), i.e., \(i^2 = -1\). This property comes in handy for operations like multiplication, as it essentially allows you to convert a part of your expression into a real number, facilitating further simplification.
When you use \(i\), you can express negative square roots as simpler expressions involving \(i\). For example, if you have \(\sqrt{-a}\), you can rewrite it as \(i\sqrt{a}\). This is a very useful tool because it simplifies operations involving negative square roots and gives us the means to expand into the broader field of complex numbers.When working with the imaginary unit, always keep in mind that the square of \(i\) is \(-1\), i.e., \(i^2 = -1\). This property comes in handy for operations like multiplication, as it essentially allows you to convert a part of your expression into a real number, facilitating further simplification.
Simplifying Expressions
Simplifying expressions using the imaginary unit requires a clear understanding of mathematical properties. When you encounter complex expressions, especially those involving square roots of negative numbers, your goal should be to write them as simply as possible.
Start by using the imaginary unit to express square roots of negative numbers. Next, recognize any identities or properties that can help simplify further. For instance, in our exercise:
Start by using the imaginary unit to express square roots of negative numbers. Next, recognize any identities or properties that can help simplify further. For instance, in our exercise:
- You express \(\sqrt{-20}\) as \(i\sqrt{20}\) and \(\sqrt{-5}\) as \(i\sqrt{5}\).
- Multiply these to find \(\sqrt{-20} \cdot \sqrt{-5} = (i\sqrt{20}) \cdot (i\sqrt{5})\).
- Knowing that \(i^2 = -1\), this becomes \(-\sqrt{20} \cdot \sqrt{5}\).
Square Roots of Negative Numbers
Dealing with square roots of negative numbers is a pivotal aspect of complex numbers. In real-number calculations, the square root of a negative number is not defined. However, the introduction of the imaginary unit \(i\) allows us to reframe these calculations.
For any negative number \(-a\), its square root is expressed in terms of \(i\) as \(\sqrt{-a} = i\sqrt{a}\). This conversion simplifies many mathematical operations and gives us new tools to consider problems that involve these roots.Let's say you have an expression \(\sqrt{-b}\) as part of a calculation. By using \(i\), you can rewrite this as \(i\sqrt{b}\). This enables you to perform multiplications, divisions, and other algebraic operations more straightforwardly. Consider the key steps:
For any negative number \(-a\), its square root is expressed in terms of \(i\) as \(\sqrt{-a} = i\sqrt{a}\). This conversion simplifies many mathematical operations and gives us new tools to consider problems that involve these roots.Let's say you have an expression \(\sqrt{-b}\) as part of a calculation. By using \(i\), you can rewrite this as \(i\sqrt{b}\). This enables you to perform multiplications, divisions, and other algebraic operations more straightforwardly. Consider the key steps:
- Identify the negative square root in an expression.
- Rewrite it using the imaginary unit as \(i\sqrt{positive\; part}\).
- Simplify the expression as necessary, often using \(i^2 = -1\).
Other exercises in this chapter
Problem 17
Exercises \(1-28:\) Solve the quadratic equation. Check your answers for Exercises \(1-12\). $$ 2(x-1)^{2}+4=0 $$
View solution Problem 18
Write a formula for a function \(g\) whose graph is similar to \(f(x)\) but satisfies the given conditions. Do not simplify the formula. \(f(x)=5 x^{2}-3\) (a)
View solution Problem 18
Solve each equation and inequality. Use set-builder or interval notation to write solution sets to the inequalities. (a) \(x^{2}+2 x+1=0\) (b) \(x^{2}+2 x+10\)
View solution Problem 18
Exercises \(1-28:\) Solve the quadratic equation. Check your answers for Exercises \(1-12\). $$ -3(x+5)^{2}-6=0 $$
View solution