Problem 18
Question
Plot the functions \(u(x), l(x)\), and \(f(x)\). Then use these graphs along with the Squeeze Theorem to determine \(\lim _{x \rightarrow 0} f(x)\). $$ u(x)=1, l(x)=1-x^{2}, f(x)=\cos ^{2} x $$
Step-by-Step Solution
Verified Answer
The limit is 1.
1Step 1: Identify the Functions
We are given three functions: \( u(x) = 1 \), \( l(x) = 1 - x^2 \), and \( f(x) = \cos^2 x \). Our goal is to plot these functions over an interval that helps analyze the behavior as \( x \to 0 \).
2Step 2: Understand the Interval
Since we want to find the limit as \( x \to 0 \), it's beneficial to consider a small interval around zero, such as \(-1 \leq x \leq 1\), to capture the relevant behavior of \( f(x) \) with respect to \( u(x) \) and \( l(x) \).
3Step 3: Plot the Functions
Let's plot \( u(x) = 1 \) as a horizontal line, \( l(x) = 1 - x^2 \) which is a downward facing parabola opening from \( y = 1 \) at \( x = 0 \), and \( f(x) = \cos^2 x \), which oscillates between \( 0 \) and \( 1 \) with \( f(0) = 1 \). All graphs are considered within the interval \(-1 \leq x \leq 1\).
4Step 4: Analyze Graphs and Apply the Squeeze Theorem
The Squeeze Theorem states that if \( l(x) \leq f(x) \leq u(x) \) near \( x = 0 \) and \( \lim_{x \to 0} l(x) = \lim_{x \to 0} u(x) = L \), then \( \lim_{x \to 0} f(x) = L \). Here, \( l(x) = 1 - x^2 \to 1 \) and \( u(x) = 1 \to 1 \) as \( x \to 0 \). Also, \( 1 - x^2 \leq \cos^2 x \leq 1 \). Therefore, \( \lim_{x \to 0} f(x) = 1 \).
5Step 5: Conclusion
By the graph and the Squeeze Theorem, we determine that as \( x \approaches 0 \), \( f(x) = \cos^2 x \) is squeezed to the limit \( 1 \). Thus, the limit is \( 1 \).
Key Concepts
Functions PlottingLimit CalculationCosine Function
Functions Plotting
Plotting functions is an essential early step in understanding and analyzing mathematical behaviors. It allows us to visualize and compare the behavior of different functions over a specific interval. For the given exercise, we have three functions:
- \( u(x) = 1 \): This is a constant function, resulting in a horizontal line at \( y = 1 \) on the graph.
- \( l(x) = 1 - x^2 \): This represents a downward-facing parabola. It's highest at \( x = 0 \) where \( y = 1 \), and it drops off as \( x \) moves away from zero.
- \( f(x) = \cos^2 x \): The cosine function squared, which oscillates between \( 0 \) and \( 1 \).
Limit Calculation
Limit calculation is a fundamental concept in calculus that helps us understand the behavior of a function as it approaches a specific point. In this exercise, we are interested in the behavior of \( f(x) = \cos^2 x \) as \( x \rightarrow 0 \). The Squeeze Theorem, also known as the Sandwich Theorem, is particularly useful in determining this limit when direct substitution isn't clear.
To apply the theorem:
To apply the theorem:
- Identify three functions: a lower bound \( l(x) = 1 - x^2 \), an upper bound \( u(x) = 1 \), and the target function \( f(x) = \cos^2 x \) we aim to find the limit for.
- For \( x \) near 0, ensure that \( l(x) \leq f(x) \leq u(x) \). Over the interval chosen, this holds true, as noted from their plotted graphs.
- Evaluate the limit of \( l(x) \) and \( u(x) \) as \( x \rightarrow 0 \). Both \( l(x) \) and \( u(x) \) simplify to \( 1 \), meeting the theorem's conditions.
Cosine Function
The cosine function, denoted as \( \cos(x) \), is a fundamental trigonometric function that is periodic and oscillates between -1 and 1. When squared, as in \( f(x) = \cos^2 x \), the oscillation remains but shifts between 0 and 1 instead, providing a different range of values for its outputs.
A few key properties of the cosine function and its square are:
A few key properties of the cosine function and its square are:
- The function is even, meaning \( \cos(-x) = \cos(x) \), indicating symmetry about the y-axis.
- \( \cos^2 x \) allows periodicity with a period of \( \pi \), due to the nature of the squared cosine cycle.
- At \( x = 0 \), \( \cos^2 0 = 1^2 = 1 \), which is relevant for limit calculation as \( x \rightarrow 0 \).
Other exercises in this chapter
Problem 18
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