Problem 18
Question
In Problems 18-23, the given function is not defined at a certain point. How should it be defined in order to make it continuous at that point? (See Example 1.) $$ f(x)=\frac{x^{2}-49}{x-7} $$
Step-by-Step Solution
Verified Answer
Define \( f(7) = 14 \) to make the function continuous at \( x = 7 \).
1Step 1: Identify the point of discontinuity
The function \( f(x) = \frac{x^2 - 49}{x - 7} \) is discontinuous at \( x = 7 \) because the denominator becomes zero, making the expression undefined.
2Step 2: Simplify the function
Factor the numerator: \( x^2 - 49 \) is a difference of squares. Thus, \( x^2 - 49 = (x-7)(x+7) \). The function becomes \( f(x) = \frac{(x-7)(x+7)}{x-7} \).
3Step 3: Cancel common factors
The term \( (x-7) \) appears in both the numerator and denominator, except where \( x = 7 \). Cancel these terms to simplify the function to \( f(x) = x + 7 \) for all \( x eq 7 \).
4Step 4: Define the function at \( x = 7 \)
To make \( f(x) \) continuous at \( x = 7 \), define \( f(x) \) such that its limit as \( x \) approaches 7 equals the function value at \( x = 7 \). Calculate the limit: \( \lim_{{x \to 7}} f(x) = 7 + 7 = 14 \). Therefore, define \( f(7) = 14 \).
Key Concepts
DiscontinuityLimitsFactorizationFunctions
Discontinuity
Discontinuity happens when a function cannot be smoothly followed along its entire domain due to some interruption or gap. In the case of the function \( f(x) = \frac{x^2 - 49}{x - 7} \), the problem lies at \( x = 7 \) because the denominator becomes zero. When a denominator of a fraction within a function becomes zero, it leads to an undefined situation, creating a point of discontinuity.
In practical terms, this means that there is a break in the graph of the function at \( x = 7 \), making it impossible to draw the function without lifting the pencil from the paper at that point. The goal, in such cases, is to redefine a function carefully to ensure it becomes continuous, filling in any gaps or jumps at the troublesome point.
In practical terms, this means that there is a break in the graph of the function at \( x = 7 \), making it impossible to draw the function without lifting the pencil from the paper at that point. The goal, in such cases, is to redefine a function carefully to ensure it becomes continuous, filling in any gaps or jumps at the troublesome point.
Limits
Limits are a fundamental concept in calculus and they help us understand the behavior of a function as it approaches a particular point. Using limits, we can determine the value that a function is approaching even if it is not defined there.
In our example with \( f(x) = \frac{x^2 - 49}{x - 7} \), we determined the limit as \( x \) approaches 7. Since after simplifying, \( f(x) = x + 7 \) wherever \( x eq 7 \), the limit as \( x \to 7 \) becomes \( 14 \).
This means, although \( x = 7 \) is not initially in the domain (because of division by zero), the output of the function is always tending towards 14 as \( x \) approaches 7. By defining \( f(7) = 14 \), we ensure the function is continuous at this point.
In our example with \( f(x) = \frac{x^2 - 49}{x - 7} \), we determined the limit as \( x \) approaches 7. Since after simplifying, \( f(x) = x + 7 \) wherever \( x eq 7 \), the limit as \( x \to 7 \) becomes \( 14 \).
This means, although \( x = 7 \) is not initially in the domain (because of division by zero), the output of the function is always tending towards 14 as \( x \) approaches 7. By defining \( f(7) = 14 \), we ensure the function is continuous at this point.
Factorization
Factorization is the method of breaking down expressions into a product of simpler factors. In the given function, the numerator \( x^2 - 49 \) can be rewritten using the difference of squares method. This polynomial identity states that \( a^2 - b^2 = (a-b)(a+b) \).
Applying this to \( x^2 - 49 \), we get \((x-7)(x+7)\). By factorizing, we simplify the expression so that when it is divided by \( x-7 \) in the denominator, the troublesome \( x-7 \) terms can be canceled out, leaving the much simpler function \( x+7 \) for \( x eq 7 \).
Factorization thus helps to clarify situations where continuity can be re-established by removing apparantly complicating elements in the function's expression.
Applying this to \( x^2 - 49 \), we get \((x-7)(x+7)\). By factorizing, we simplify the expression so that when it is divided by \( x-7 \) in the denominator, the troublesome \( x-7 \) terms can be canceled out, leaving the much simpler function \( x+7 \) for \( x eq 7 \).
Factorization thus helps to clarify situations where continuity can be re-established by removing apparantly complicating elements in the function's expression.
Functions
Functions are mathematical objects that relate a set of inputs to a set of outputs. Every function \( f(x) \) maps each element from its domain to a unique element in its range. The behavior of functions can vary greatly depending on their defining rules.
In the function \( f(x) = \frac{x^2 - 49}{x - 7} \), initially, there seems to be a problem due to the discontinuity at \( x = 7 \). However, by altering the rules slightly – through simplification – we can redefine this function's behavior at that point to maintain continuity.
The essential nature of functions is to provide a predictable and consistent mapping from input to output, and addressing discontinuities through methods such as defining new points or simplifying expressions is crucial in securing that stability across all inputs.
In the function \( f(x) = \frac{x^2 - 49}{x - 7} \), initially, there seems to be a problem due to the discontinuity at \( x = 7 \). However, by altering the rules slightly – through simplification – we can redefine this function's behavior at that point to maintain continuity.
The essential nature of functions is to provide a predictable and consistent mapping from input to output, and addressing discontinuities through methods such as defining new points or simplifying expressions is crucial in securing that stability across all inputs.
Other exercises in this chapter
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