Problem 18
Question
Graph the functions in Exercises \(7-18 .\) What symmetries, if any, do the graphs have? Specify the intervals over which the function is increasing and the intervals where it is decreasing. $$ y=-x^{2 / 3} $$
Step-by-Step Solution
Verified Answer
The graph is symmetric about the y-axis, increasing on \((-\infty,0)\) and decreasing on \((0,\infty)\).
1Step 1: Identify the Function Type
The function given is a cubic root function, specifically, \( y = -x^{2/3} \). This means it is not a polynomial with an even power, which would affect the kind of symmetry it may have.
2Step 2: Check for Symmetries
To determine symmetry, check for even or odd functions. An even function satisfies \( f(-x) = f(x) \) and an odd function satisfies \( f(-x) = -f(x) \). Compute \( f(-x) = -(-x)^{2/3} = -x^{2/3} = f(x) \), indicating that the function is even and symmetric about the y-axis.
3Step 3: Determine Critical Points and Sign Changes
The derivative of the function needs to be evaluated to find intervals of increase or decrease. Compute the first derivative \( f'(x) = -\frac{2}{3}x^{-1/3} \). The derivative changes signs due to \( x^{-1/3} \) when crossing \( x=0 \).
4Step 4: Analyze Intervals of Increase/Decrease
Set \( f'(x) \) to greater or less than zero to understand where the function increases or decreases. From \( f'(x) \): - When \( x < 0 \), \( f'(x) > 0 \), indicating the function is increasing.- When \( x > 0 \), \( f'(x) < 0 \), indicating the function is decreasing.
5Step 5: Conclusion from Analysis
The graph of \( y=-x^{2/3} \) is symmetric about the y-axis. The function is increasing on the interval \( (-\infty, 0) \) and decreasing on the interval \( (0, \infty) \).
Key Concepts
Cubic Root FunctionIntervals of Increase and DecreaseEven Function SymmetryDerivative Analysis
Cubic Root Function
A cubic root function typically involves the cube root of an expression, but in this case, we have a different variant in the form of \( y = -x^{2/3} \). This expression means that the function is defined by taking \( x \) to the power of \( \frac{2}{3} \), introducing a cubic root component.
What makes this function unique is that it combines both a square and a cube root aspect. This structure results in intriguing behaviors, such as influencing the graph's shape and symmetry characteristics.
Additionally, in functions like \( y = -x^{2/3} \), the negative sign in front of the power means the graph will reflect over the x-axis, further adding to its distinct form.
What makes this function unique is that it combines both a square and a cube root aspect. This structure results in intriguing behaviors, such as influencing the graph's shape and symmetry characteristics.
Additionally, in functions like \( y = -x^{2/3} \), the negative sign in front of the power means the graph will reflect over the x-axis, further adding to its distinct form.
Intervals of Increase and Decrease
To find where a function increases or decreases, we look at the derivative, which gives the slope of the tangent at any point of the function. For our function \( y = -x^{2/3} \), the derivative is \( f'(x) = -\frac{2}{3}x^{-1/3} \).
This derivative tells us how the rate of change in the function behaves. When the derivative is positive, the function increases. Conversely, if it’s negative, the function decreases.
For \( y = -x^{2/3} \):
This derivative tells us how the rate of change in the function behaves. When the derivative is positive, the function increases. Conversely, if it’s negative, the function decreases.
For \( y = -x^{2/3} \):
- When \( x < 0 \), \( f'(x) > 0 \). Here, the function increases as we move towards zero from the left.
- When \( x > 0 \), \( f'(x) < 0 \). In this interval, the function decreases as we move away from zero towards positive infinity.
Even Function Symmetry
An even function shows symmetry about the y-axis, meaning the left and right sides of the graph mirror each other. For a function to be even, it satisfies the condition \( f(-x) = f(x) \).
Analyzing \( y = -x^{2/3} \), we compute \( f(-x) = -(-x)^{2/3} \), which simplifies to \( -x^{2/3} = f(x) \). This confirms the function is even.
Thus, for \( y = -x^{2/3} \), the graph is symmetric about the y-axis. This symmetry simplifies understanding its geometric behavior and helps in predicting its reflection attributes.
Analyzing \( y = -x^{2/3} \), we compute \( f(-x) = -(-x)^{2/3} \), which simplifies to \( -x^{2/3} = f(x) \). This confirms the function is even.
Thus, for \( y = -x^{2/3} \), the graph is symmetric about the y-axis. This symmetry simplifies understanding its geometric behavior and helps in predicting its reflection attributes.
Derivative Analysis
Derivative analysis is crucial for understanding the behavior of functions, especially regarding their increasing and decreasing nature. For the cubic root function \( y = -x^{2/3} \), the derivative \( f'(x) = -\frac{2}{3}x^{-1/3} \) provides essential insights.
By setting \( f'(x) = 0 \), we identify critical points, although for this function, it's undefined at \( x = 0 \) due to natural division by zero issues from \( x^{-1/3} \).
Nevertheless, analyzing the derivative's sign changes across the x-axis reveals:
By setting \( f'(x) = 0 \), we identify critical points, although for this function, it's undefined at \( x = 0 \) due to natural division by zero issues from \( x^{-1/3} \).
Nevertheless, analyzing the derivative's sign changes across the x-axis reveals:
- Positive derivative for \( x < 0 \), indicating an increasing segment.
- Negative derivative for \( x > 0 \), indicating a decreasing segment.
Other exercises in this chapter
Problem 17
In Exercises 17–30, write an equation for each line described. Passes through \((-1,1)\) with slope \(-1\)
View solution Problem 18
In Exercises 5–30, determine an appropriate viewing window for the given function and use it to display its graph. $$ y=1-\frac{1}{x+3} $$
View solution Problem 18
Solve the equations in Exercises \(13-18\) $$ \left|\frac{s}{2}-1\right|=1 $$
View solution Problem 18
In Exercises 17–30, write an equation for each line described. Passes through \((2,-3)\) with slope 1\(/ 2\)
View solution