Problem 18
Question
A person is lying on a diving board 3.00 m above the surface of the water in a swimming pool. The person looks at a penny that is on the bottom of the pool directly below her. The penny appears to the person to be a distance of 8.00 \(\mathrm{m}\) from her. What is the depth of the water at this point?
Step-by-Step Solution
Verified Answer
The depth of the water is 6.65 m.
1Step 1: Understand the Refraction Concept
Light bends when it moves from water to air due to refraction. This bending causes objects underwater to appear closer than they actually are. The apparent depth and real depth can be linked using the refractive index of water.
2Step 2: Apply Snell's Law
The relationship between the apparent depth (d_a) and the real depth (d_r) is given by the formula: \(d_a = \frac{d_r}{n}\), where \(n ≈ 1.33\) is the refractive index of water. We need to use this formula to find the real depth.
3Step 3: Find Apparent Distance to the Penny
The person is 3 m above the water, and the penny appears to be 8 m away. This means the apparent depth as seen by the person is the distance from the water surface to the penny: \(d_a = 8 \text{ m} - 3 \text{ m} = 5 \text{ m}\).
4Step 4: Solve for Actual Depth
Use the equation \(d_a = \frac{d_r}{n}\) to find the real depth \(d_r\): \(5 = \frac{d_r}{1.33}\). Multiply both sides by 1.33 to get \(d_r = 5 \times 1.33 = 6.65\text{ m}\).
5Step 5: Conclusion
The calculation shows that the real depth of water at this point, taking into account the refraction, is \(6.65 \text{ m}\).
Key Concepts
Snell's LawRefractive IndexApparent Depth vs Real Depth
Snell's Law
Snell's Law is a fundamental principle in optics that describes how light bends or refracts when it moves between different mediums. Imagine light as a traveler crossing borders — each time it enters a new region, it changes direction. The law is captured in the equation \( n_1 \sin \theta_1 = n_2 \sin \theta_2 \), where \( n_1 \) and \( n_2 \) are the refractive indices of the two media, and \( \theta_1 \) and \( \theta_2 \) are the angles of incidence and refraction, respectively. This relationship allows us to determine how much the light will bend.
Applying Snell's Law helps us understand why objects under water appear closer than they really are. When light travels from water to air, it slows down, resulting in a decrease in its path distance. Hence, the penny at the pool's bottom seems nearer because of this bending effect, which is reflected through the refractive index of water.
Applying Snell's Law helps us understand why objects under water appear closer than they really are. When light travels from water to air, it slows down, resulting in a decrease in its path distance. Hence, the penny at the pool's bottom seems nearer because of this bending effect, which is reflected through the refractive index of water.
Refractive Index
The refractive index, often represented as \( n \), is a dimensionless number that describes how fast light travels in a material compared to its speed in a vacuum. Think of it as a "light speed limit" specific to each medium. This index determines the degree to which light bends when entering a new medium.
For water, the refractive index is approximately \( 1.33 \). This means that light travels 1.33 times slower in water than in a vacuum. A higher refractive index indicates a greater bending effect of light entering at an angle.
Understanding the refractive index is crucial for predicting how deep something appears when looking through water. In the pool exercise, this principle helps calculate the apparent and real depths of the penny, helping to understand and quantify this optical illusion.
For water, the refractive index is approximately \( 1.33 \). This means that light travels 1.33 times slower in water than in a vacuum. A higher refractive index indicates a greater bending effect of light entering at an angle.
- If \( n > 1 \), light bends towards the normal line when entering the medium.
- If \( n < 1 \), light bends away from the normal line.
- If \( n = 1 \), light travels without bending.
Understanding the refractive index is crucial for predicting how deep something appears when looking through water. In the pool exercise, this principle helps calculate the apparent and real depths of the penny, helping to understand and quantify this optical illusion.
Apparent Depth vs Real Depth
When you gaze into a pool at the bottom objects, you might not see them at their true location. This discrepancy in observed position is due to refraction. The apparent depth is the perceived depth from the viewer's perspective, while the real depth is the actual depth of the object under water.
To bridge the gap between what you see and reality, we use the formula \( d_a = \frac{d_r}{n} \). Here, \( d_a \) is the apparent depth, \( d_r \) is the real depth, and \( n \) is the refractive index of the medium (in this case, water).
To bridge the gap between what you see and reality, we use the formula \( d_a = \frac{d_r}{n} \). Here, \( d_a \) is the apparent depth, \( d_r \) is the real depth, and \( n \) is the refractive index of the medium (in this case, water).
- The apparent depth is always less than the real depth because light bends as it moves from water to air.
- Knowing the apparent depth (what is seen) along with the refractive index helps precisely calculate the real depth (the actual measure).
Other exercises in this chapter
Problem 16
A tank whose bottom is a mirror is filled with water to a depth of 20.0 \(\mathrm{cm} .\) A small fish floats motionless 7.0 \(\mathrm{cm}\) under the surface o
View solution Problem 17
A person swimming 0.80 \(\mathrm{m}\) below the surface of the water in a swimming pool looks at the diving board that is directly overhead and sees the image o
View solution Problem 20
The left end of a long glass rod 6.00 \(\mathrm{cm}\) in diameter has a convex hemispherical surface 3.00 \(\mathrm{cm}\) in radius. The refractive index of the
View solution Problem 22
The left end of a long glass rod 8.00 \(\mathrm{cm}\) in diameter, with an index of refraction of \(1.60,\) is ground and polished to a convex hemispherical sur
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